PHP - Variables and Data Types
What will the following PHP code output?
$name = 'John';
echo 'Hello, $name!';
What will the following PHP code output?
easy📝 Conceptual Q2 of 15
Step-by-Step Solution
Solution:
Step 1: Analyze single quotes behavior
Single quotes do not replace variables with their values; they print the text as is.Step 2: Check the output of the echo statement
The string 'Hello, $name!' is printed literally, including the $name part.Final Answer:
Hello, $name! -> Option DQuick Check:
Single quotes print variables literally = Hello, $name! [OK]
Quick Trick: Single quotes print variables as text, no substitution [OK]
Common Mistakes:
- Expecting variable substitution with single quotes
- Confusing single and double quotes behavior
- Assuming syntax error due to variable inside quotes
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