[Solved] Find the error in this PHP code snippet:$x = 5;if ($x = '5') { echo 'Equal';} else { echo 'Not equal';} | PHP

PHP - Operators

Find the error in this PHP code snippet:

$x = 5;
if ($x = '5') {
  echo 'Equal';
} else {
  echo 'Not equal';
}

AMissing semicolon after echo

BUsing strict comparison (===) instead of loose

CAssignment (=) used instead of comparison (==)

DVariable $x is not defined

Step-by-Step Solution

Solution:

Step 1: Identify operator in if condition
The condition uses = which assigns '5' to $x instead of comparing.
Step 2: Understand effect of assignment in condition
Assignment returns the assigned value, which is truthy, so 'Equal' always prints regardless of original $x.
Final Answer:
Assignment (=) used instead of comparison (==) -> Option C
Quick Check:
Use == for comparison, not = [OK]

Quick Trick: Use == for comparison, not = assignment [OK]

Common Mistakes:

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