PHP dynamic typing behavior - Cheat Sheet & Quick Revision

Recall & Review

beginner

What does dynamic typing mean in PHP?

Dynamic typing means PHP variables do not have a fixed type. The type is determined automatically based on the value assigned to the variable.

beginner

How does PHP handle adding a string and an integer?

PHP converts the string to a number if possible, then adds the two numbers. For example, '5' + 3 results in 8.

beginner

What happens if you use a variable before assigning a value in PHP?

PHP treats the variable as NULL and may show a warning depending on error settings.

intermediate

Explain type juggling in PHP.

Type juggling is PHP automatically converting types when performing operations, like converting strings to numbers or booleans to integers.

intermediate

Can you force a variable to a specific type in PHP? How?

Yes, by using type casting like (int), (string), (bool), etc. For example, (int) '123' converts the string to an integer.

What type will the variable have after this code?
$var = 10;

A Float

B Integer

C Boolean

D String

Assigning 10 makes $var an integer type.

What is the result of '5' + 2 in PHP?

A Error

B '52'

C 7

D '5 2'

PHP converts '5' to integer 5 and adds 2, resulting in 7.

What does PHP do if you add a boolean TRUE to an integer 3?

A TRUE3

B 3

C Error

D 4

TRUE is converted to 1, so 1 + 3 = 4.

Which of these is NOT a way to cast a variable to a type in PHP?

A (var)

B (string)

C (float)

D (int)

(var) is not a valid type cast in PHP.

If you assign $x = 'abc'; and then add 5 to $x, what is the result?

A 5

B 'abc5'

C Error

D 0

PHP converts 'abc' to 0 when used in arithmetic, so 0 + 5 = 5.

Explain how PHP's dynamic typing affects variable usage and operations.

Think about how PHP changes variable types based on context.

Describe how you can control or change variable types explicitly in PHP.

Consider how to force a variable to be a certain type.

Practice

1. In PHP, what happens if you assign a string value to a variable and then assign an integer to the same variable later?

easy

A. PHP throws a type error because the variable type is fixed.

B. The variable keeps the original string type and ignores the integer.

C. The variable changes its type dynamically to integer.

D. The variable becomes an array containing both values.

Solution

1. Step 1: Understand PHP variable typing

   PHP variables do not have fixed types and can change type dynamically during execution.

2. Step 2: Assign different types to the same variable

   Assigning a string first and then an integer changes the variable's type to integer automatically.

3. Final Answer:

   The variable changes its type dynamically to integer. -> Option C

4. Quick Check:

   PHP variables are dynamically typed = B [OK]

Hint: Remember: PHP variables change type automatically when reassigned [OK]

Common Mistakes:

• Thinking PHP variables have fixed types like in Java
• Assuming PHP throws errors on type changes
• Believing variables keep old values as arrays

2. Which of the following is the correct way to assign a float value to a variable in PHP?

easy

A. $num = 3.14; // float assignment

B. $num = '3.14'; // string assignment

C. $num = (int)3.14; // integer cast

D. $num = float(3.14); // float function

Solution

1. Step 1: Identify correct float assignment syntax

   In PHP, assigning a float is done by directly assigning a number with decimal point without quotes.

2. Step 2: Evaluate each option

   $num = 3.14; // float assignment assigns 3.14 as a float correctly. $num = '3.14'; // string assignment assigns a string, C casts to int, D uses invalid syntax.

3. Final Answer:

   $num = 3.14; // float assignment -> Option A

4. Quick Check:

   Float assignment uses decimal number without quotes = A [OK]

Hint: Assign floats without quotes; quotes make it a string [OK]

Common Mistakes:

• Using quotes around numbers to assign floats
• Trying to cast with invalid functions like float()
• Casting floats to int unintentionally

3. What will be the output of the following PHP code?

$a = '5';
$b = 3;
$c = $a + $b;
echo gettype($c) . ' ' . $c;

medium

A. integer 8

B. integer 53

C. string 8

D. string 53

Solution

1. Step 1: Analyze the addition operation with mixed types

   PHP converts the string '5' to integer 5 automatically when used with + operator.

2. Step 2: Determine the result type and value

   Adding 5 + 3 gives integer 8. gettype($c) returns 'integer' and echo prints 'integer 8'.

3. Final Answer:

   integer 8 -> Option A

4. Quick Check:

   String + int converts string to int = D [OK]

Hint: PHP converts numeric strings to numbers in math operations [OK]

Common Mistakes:

• Expecting string concatenation with + operator
• Thinking result type stays string
• Confusing + with . operator for strings

4. Consider this PHP code snippet:

$x = '10 apples';
$y = 5;
$z = $x + $y;
echo $z;

What is the issue and how to fix it?

medium

A. No issue; output is 15.

B. Warning due to non-numeric string; fix by extracting number before addition.

C. Syntax error; fix by adding semicolon after $y.

D. Runtime error; fix by casting $y to string.

Solution

1. Step 1: Understand PHP's behavior with non-numeric strings in math

   PHP tries to convert '10 apples' to number; it extracts leading number 10 but may raise a warning if strict error reporting is on.

2. Step 2: Identify the fix

   To avoid warnings, explicitly extract the numeric part (e.g., using intval) before addition.

3. Final Answer:

   Warning due to non-numeric string; fix by extracting number before addition. -> Option B

4. Quick Check:

   Non-numeric strings cause warnings in math = C [OK]

Hint: Extract numbers from strings before math to avoid warnings [OK]

Common Mistakes:

• Assuming no warnings with mixed strings
• Confusing syntax errors with runtime warnings
• Casting integers to strings unnecessarily

5. You have an array of mixed values:

$values = ['10', 20, '30 apples', true, null, 5.5];
$sum = 0;
foreach ($values as $v) {
    $sum += $v;
}
echo $sum;

What will be the output and why?

hard

A. Warning and sum is 0 due to invalid types.

B. Error because null and boolean cannot be added.

C. 65 because floats are truncated in addition.

D. 66.5 because PHP converts all values to numbers in addition.

Solution

1. Step 1: Understand PHP type conversion in addition

   PHP converts strings with leading numbers to those numbers, booleans true to 1, null to 0, and floats remain floats.

2. Step 2: Calculate sum step-by-step

   '10' -> 10, 20 -> 20, '30 apples' -> 30, true -> 1, null -> 0, 5.5 -> 5.5; sum = 10+20+30+1+0+5.5 = 66.5

3. Step 3: Check calculation carefully

   Sum is 66.5; re-check addition: 10+20=30, +30=60, +1=61, +0=61, +5.5=66.5

4. Final Answer:

   66.5 because PHP converts all values to numbers in addition. -> Option D

5. Quick Check:

   PHP converts all to numbers in math = A [OK]

Hint: PHP converts all types to numbers in math operations [OK]

Common Mistakes:

• Ignoring boolean and null conversions
• Assuming floats truncate to int
• Expecting errors on mixed types