PHP - FunctionsHow can you pass an argument by reference to a PHP function so that changes inside affect the original variable?APrefix the parameter with & in the function definitionBUse global keyword inside the functionCPass the argument as a stringDUse static keyword in the functionCheck Answer
Step-by-Step SolutionSolution:Step 1: Understand passing by referencePassing by reference means the function can modify the original variable.Step 2: Identify PHP syntax for referenceIn PHP, prefixing the parameter with & in the function definition allows passing by reference.Final Answer:Prefix the parameter with & in the function definition -> Option AQuick Check:Reference passing = & before parameter [OK]Quick Trick: Use & before parameter to pass by reference [OK]Common Mistakes:Using global instead of referencePassing by value expecting changesConfusing static with reference
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