[Solved] Find the mistake in this PHP code:$value = "hello";if (gettype $value == "string") { echo "It is a string.";} | PHP

PHP - Type Handling

Find the mistake in this PHP code:

$value = "hello";
if (gettype $value == "string") {
  echo "It is a string.";
}

AVariable $value is not defined

BWrong comparison operator used

CMissing parentheses in gettype function call

DEcho statement syntax is incorrect

Step-by-Step Solution

Solution:

Step 1: Check gettype() function call syntax
Functions in PHP require parentheses around arguments, so gettype $value is invalid.
Step 2: Verify other parts
Comparison operator == is correct, $value is defined, echo syntax is valid.
Final Answer:
Missing parentheses in gettype function call -> Option C
Quick Check:
Function calls need parentheses in PHP [OK]

Quick Trick: Always use parentheses when calling functions [OK]

Common Mistakes:

Master "Type Handling" in PHP

9 interactive learning modes - each teaches the same concept differently

More PHP Quizzes

Find the mistake in this PHP code: