[Solved] Consider the following PHP code snippet:$var = null;if (empty($var)) { echo 'Empty';} else { echo 'Not Empty';}Why does this code print "Empty"? | PHP

PHP - Type Handling

Consider the following PHP code snippet:

$var = null;
if (empty($var)) {
    echo 'Empty';
} else {
    echo 'Not Empty';
}

Why does this code print "Empty"?

ABecause <code>empty</code> returns false for null values.

BBecause <code>empty</code> only checks if variable is set.

CBecause <code>empty</code> returns true for null values.

DBecause <code>empty</code> throws an error for null values.

Step-by-Step Solution

Solution:

Step 1: Understand empty behavior with null
empty returns true if the variable is not set or its value is considered empty, including null.
Step 2: Analyze the code output
Since $var is null, empty($var) returns true, so "Empty" is printed.
Final Answer:
Because empty returns true for null values. -> Option C
Quick Check:
empty true for null [OK]

Quick Trick: empty true for null or unset variables [OK]

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