[Solved] Consider this PHP code:$x = 5; if ($x > 0) { if ($x % 2 == 0) { echo "Even"; } else { echo "Odd"; } } else { echo "Non-positive"; }What will be the output? | PHP

PHP - Conditional Statements

Consider this PHP code:

$x = 5;
if ($x > 0) {
    if ($x % 2 == 0) {
        echo "Even";
    } else {
        echo "Odd";
    }
} else {
    echo "Non-positive";
}

What will be the output?

AError

BOdd

CNon-positive

DEven

Step-by-Step Solution

Solution:

Step 1: Check outer if condition $x > 0
Since $x is 5, which is greater than 0, the outer if block runs.
Step 2: Check inner if condition $x % 2 == 0
5 modulo 2 is 1, so condition is false; inner else runs printing "Odd".
Final Answer:
Odd -> Option B
Quick Check:
Nested if else correctly identifies odd number [OK]

Quick Trick: Nested if checks conditions stepwise [OK]

Common Mistakes:

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