PHP - Output and String Handling
Why does the following PHP code print the string literal instead of the variable value?
<?php
$name = "John";
echo 'Hello, $name!';
?>
Why does the following PHP code print the string literal instead of the variable value?
hard📝 Conceptual Q10 of 15
Step-by-Step Solution
Solution:
Step 1: Understand string quoting rules in PHP
Single-quoted strings treat everything literally, so variables are not replaced by their values.Step 2: Analyze the code behavior
The code prints exactly 'Hello, $name!' because $name is inside single quotes.Final Answer:
Because single quotes do not parse variables inside strings -> Option BQuick Check:
Single quotes print variables literally [OK]
Quick Trick: Single quotes do not replace variables inside strings [OK]
Common Mistakes:
- Assuming variables are parsed in single quotes
- Thinking variable is undefined
- Ignoring string quoting rules
Master "Output and String Handling" in PHP
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