[Solved] Identify the problem in this PHP code:for ($i = 0; $i — Ans: continue 3 is invalid because only 2 nested loops exist | PHP

PHP - Loops

Identify the problem in this PHP code:

for ($i = 0; $i < 2; $i++) {
    for ($j = 0; $j < 2; $j++) {
        if ($j == 1) continue 3;
        echo "$i$j ";
    }
}

Acontinue 3 behaves like continue 1

Bcontinue 3 is invalid because only 2 nested loops exist

Ccontinue 3 skips all loops correctly

DNo problem, code runs fine

Step-by-Step Solution

Solution:

Step 1: Check number of nested loops
There are only 2 nested loops: outer and inner.
Step 2: Validate continue level number
continue 3 tries to skip 3 levels, which is invalid and causes a fatal error.
Final Answer:
continue 3 is invalid because only 2 nested loops exist -> Option B
Quick Check:
continue n > nested loops = error [OK]

Quick Trick: continue n must not exceed nested loop depth [OK]

Common Mistakes:

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