Echo statement in PHP - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

What is the output of this PHP echo statement?

Consider the following PHP code snippet. What will it print?

PHP

<?php
echo "Hello " . "World!";
?>

A Hello World!

B Hello.World!

C HelloWorld!

D Hello + World!

💡 Hint

The dot (.) operator in PHP joins strings together.

The dot operator concatenates strings in PHP. So "Hello " . "World!" becomes "Hello World!".

❓ Predict Output

intermediate

What does this echo statement output?

Look at this PHP code. What will be printed?

PHP

<?php
echo 5 + 3;
?>

A 53

B 5 + 3

C Error

D 8

💡 Hint

PHP evaluates expressions inside echo before printing.

The expression 5 + 3 is calculated to 8, which is then printed.

❓ Predict Output

advanced

What is the output of this PHP echo with variables?

Given the code below, what will echo print?

PHP

<?php
$name = "Alice";
echo "Hello, $name!";
?>

A Hello, Alice!

B Error

C Hello, !

D Hello, $name!

💡 Hint

Double quotes allow variable interpolation in PHP.

Inside double quotes, PHP replaces $name with its value, so it prints Hello, Alice!

❓ Predict Output

advanced

What error does this PHP echo statement cause?

What error will this PHP code produce?

PHP

<?php
echo 'Hello, $name!';
?>

A Syntax error

B Prints Hello, Alice!

C Prints Hello, $name!

D Undefined variable error

💡 Hint

Single quotes do not replace variables in PHP strings.

Single quotes print the string as is, so $name is not replaced and prints literally.

🧠 Conceptual

expert

How many items are printed by this PHP echo statement?

What is the number of separate items printed by this echo statement?

PHP

<?php
echo "Hi", " there", "!";
?>

A 2

B 3

C 1

D Error

💡 Hint

Echo can take multiple comma-separated arguments.

Echo can print multiple strings separated by commas, so it prints 3 items.

Practice

1. What does the echo statement do in PHP?

easy

A. It stores data in a variable.

B. It creates a function.

C. It prints text or variables to the screen.

D. It deletes a file.

Solution

1. Step 1: Understand the purpose of echo

   The echo statement is used to output text or variables to the screen in PHP.

2. Step 2: Compare with other options

   Other options describe different PHP actions like storing data, creating functions, or deleting files, which are not done by echo.

3. Final Answer:

   It prints text or variables to the screen. -> Option C

4. Quick Check:

   Echo = print output [OK]

Hint: Echo always shows output on the screen [OK]

Common Mistakes:

• Thinking echo stores data
• Confusing echo with function creation
• Assuming echo deletes files

2. Which of the following is the correct syntax to print the text Hello World using echo in PHP?

easy

A. echo "Hello World";

B. echo (Hello World);

C. echo 'Hello World';

D. echo Hello World;

Solution

1. Step 1: Check the syntax for echo with text

   Text must be inside quotes (single or double) when printed with echo. echo "Hello World"; uses double quotes and ends with a semicolon.

2. Step 2: Identify syntax errors in other options

   echo Hello World; misses quotes around text. echo 'Hello World' misses semicolon. echo (Hello World); incorrectly uses parentheses without quotes.

3. Final Answer:

   echo "Hello World"; -> Option A

4. Quick Check:

   Text in quotes + semicolon = correct echo syntax [OK]

Hint: Always put text inside quotes and end with semicolon [OK]

Common Mistakes:

• Forgetting quotes around text
• Missing semicolon at end
• Using parentheses incorrectly

3. What will be the output of the following PHP code?

<?php
$name = "Alice";
echo "Hello, $name!";
?>

medium

A. Hello, $name!

B. Hello, Alice!

C. Hello, !

D. Syntax Error

Solution

1. Step 1: Understand variable interpolation in double quotes

   In PHP, variables inside double quotes are replaced by their values. Here, $name is "Alice".

2. Step 2: Determine the output of echo

   The echo statement prints "Hello, Alice!" because $name is replaced by "Alice".

3. Final Answer:

   Hello, Alice! -> Option B

4. Quick Check:

   Variables in double quotes show values [OK]

Hint: Variables inside double quotes print their values [OK]

Common Mistakes:

• Expecting variable name printed literally
• Using single quotes which don't interpolate
• Assuming syntax error due to variable

4. Identify the error in the following PHP code:

<?php
echo 'Welcome to PHP!";
?>

medium

A. Incorrect use of echo keyword

B. Missing semicolon at the end

C. Variable not defined

D. Mismatched quotes in echo statement

Solution

1. Step 1: Check the quotes used in echo

   The echo statement starts with a single quote but ends with a double quote, causing mismatched quotes.

2. Step 2: Understand PHP string syntax

   Strings must start and end with the same type of quote (both single or both double). Mismatched quotes cause syntax errors.

3. Final Answer:

   Mismatched quotes in echo statement -> Option D

4. Quick Check:

   Quotes must match in strings [OK]

Hint: Start and end quotes must be the same type [OK]

Common Mistakes:

• Mixing single and double quotes
• Forgetting semicolon
• Assuming variable error instead

5. You want to print the following sentence exactly as it is, including the dollar sign:
The price's $price.
Which echo statement will produce this output correctly?

hard

A. echo "The price's \$price.";

B. echo 'The price's $price.';

C. echo "The price's $price.";

D. echo 'The price's \$price.';

Solution

1. Step 1: Understand variable interpolation and escaping

   In double quotes, $ starts variable interpolation. To print a literal $, it must be escaped with a backslash (\$).

2. Step 2: Analyze each option

   echo "The price's $price."; prints "The price's " followed by $price (undefined, empty), resulting in "The price's .". echo 'The price's $price.'; syntax error due to unescaped apostrophe in "price's". echo "The price's \$price."; escapes $ correctly in double quotes (apostrophe fine), printing exactly. echo 'The price's \$price.'; syntax error from unescaped apostrophe (backslash literal if fixed).

3. Final Answer:

   echo "The price's \$price."; -> Option A

4. Quick Check:

   Escape $ in double quotes with \$ [OK]

Hint: Escape $ with \$ inside double quotes to print it [OK]

Common Mistakes:

• Not escaping $ in double quotes
• Using backslash in single quotes incorrectly
• Syntax error with unescaped apostrophe in single quotes