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PHPprogramming~15 mins

Array search functions in PHP - Mini Project: Build & Apply

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Array search functions
📖 Scenario: You are working on a small PHP program to find specific values inside an array of fruits. This is like looking for your favorite fruit in a fruit basket.
🎯 Goal: You will create an array of fruits, set a fruit to search for, use PHP array search functions to find if the fruit is in the basket, and then print the result.
📋 What You'll Learn
Create an array called $fruits with the exact values: 'apple', 'banana', 'cherry', 'date', 'elderberry'
Create a variable called $searchFruit and set it to 'cherry'
Use the PHP function in_array() with $searchFruit and $fruits to check if the fruit is in the array
Print "Found cherry in the basket!" if the fruit is found, otherwise print "cherry is not in the basket."
💡 Why This Matters
🌍 Real World
Searching arrays is common when you want to check if an item exists in a list, like checking if a username is taken or if a product is in stock.
💼 Career
Knowing how to search arrays is a basic skill for PHP developers working on websites, data processing, or any application that handles lists of data.
Progress0 / 4 steps
1
Create the fruits array
Create an array called $fruits with these exact values: 'apple', 'banana', 'cherry', 'date', 'elderberry'.
PHP
Hint

Use square brackets [] to create the array and separate values with commas.

2
Set the fruit to search
Create a variable called $searchFruit and set it to the string 'cherry'.
PHP
Hint

Use the assignment operator = to set the variable.

3
Check if the fruit is in the array
Use the PHP function in_array() with $searchFruit and $fruits to check if the fruit is in the array. Store the result in a variable called $found.
PHP
Hint

The function in_array() returns true if the value is found, otherwise false.

4
Print the search result
Write an if statement to print "Found cherry in the basket!" if $found is true, otherwise print "cherry is not in the basket.".
PHP
Hint

Use if ($found) to check the boolean and print() to show the message.

Practice

(1/5)
1. Which PHP function returns the key of a value in an array if found, or false if not found?
easy
A. in_array
B. array_search
C. array_key_exists
D. array_keys

Solution

  1. Step 1: Understand function purpose

    array_search looks for a value and returns its key if found.
  2. Step 2: Compare with other functions

    in_array returns true/false, not key; array_key_exists checks keys; array_keys returns all keys.
  3. Final Answer:

    array_search -> Option B
  4. Quick Check:

    Key returned by array_search = array_search [OK]
Hint: array_search returns key, in_array returns true/false [OK]
Common Mistakes:
  • Confusing array_search with in_array
  • Thinking array_key_exists returns value
  • Assuming array_keys searches values
2. Which of the following is the correct syntax to check if the value 5 exists in array $arr using in_array?
easy
A. in_array(5, $arr);
B. in_array($arr, 5);
C. in_array($arr => 5);
D. in_array(5 => $arr);

Solution

  1. Step 1: Recall in_array syntax

    The correct syntax is in_array(value, array).
  2. Step 2: Match syntax with options

    in_array(5, $arr); matches in_array(5, $arr); which is correct.
  3. Final Answer:

    in_array(5, $arr); -> Option A
  4. Quick Check:

    in_array(value, array) = in_array(5, $arr) [OK]
Hint: Remember in_array(value, array) order [OK]
Common Mistakes:
  • Swapping parameters order
  • Using arrow syntax instead of comma
  • Passing array as first argument
3. What is the output of the following PHP code?
$arr = ['apple', 'banana', 'cherry'];
$key = array_search('banana', $arr);
echo $key;
medium
A. 0
B. banana
C. false
D. 1

Solution

  1. Step 1: Understand array_search behavior

    It returns the key of the searched value if found.
  2. Step 2: Check array keys and searched value

    Array keys are 0=>'apple', 1=>'banana', 2=>'cherry'. Searching 'banana' returns key 1.
  3. Final Answer:

    1 -> Option D
  4. Quick Check:

    array_search('banana', $arr) = 1 [OK]
Hint: array_search returns index/key of found value [OK]
Common Mistakes:
  • Expecting value instead of key
  • Confusing false with 0
  • Assuming it returns boolean
4. Identify the error in the following PHP code snippet:
$arr = ['x' => 10, 'y' => 20];
if (array_search(30, $arr)) {
    echo 'Found';
} else {
    echo 'Not Found';
}
medium
A. array_search returns false but condition treats 0 as false
B. array_search returns key but 30 is not in array, so condition fails correctly
C. array_search should be replaced with in_array for this check
D. No error, code works as expected

Solution

  1. Step 1: Analyze array_search return and condition

    array_search returns key or false. If key is 0, condition fails because 0 is falsey.
  2. Step 2: Check searched value presence

    30 is not in array, so array_search returns false, condition is false, prints 'Not Found'. But if value was at key 0, condition would fail incorrectly.
  3. Step 3: Suggest correct function for boolean check

    Use in_array which returns true/false directly for presence check.
  4. Final Answer:

    array_search should be replaced with in_array for this check -> Option C
  5. Quick Check:

    Use in_array for boolean presence check [OK]
Hint: Use in_array for true/false presence checks [OK]
Common Mistakes:
  • Using array_search in if without strict check
  • Ignoring 0 key treated as false
  • Not using === to check false
5. Given the array $data = ['a' => 0, 'b' => false, 'c' => null, 'd' => '0'];, which function call correctly checks if the value 0 exists in the array considering type?
hard
A. in_array(0, $data, true);
B. array_search(0, $data);
C. in_array(0, $data);
D. array_search('0', $data, true);

Solution

  1. Step 1: Understand strict checking

    Using third parameter true enforces type checking in in_array and array_search.
  2. Step 2: Analyze array values and types

    Values are 0 (int), false (bool), null, and '0' (string). Only strict check distinguishes 0 (int) from others.
  3. Step 3: Choose correct function and parameters

    in_array(0, $data, true) returns true only if exact int 0 found. array_search without strict may confuse types.
  4. Final Answer:

    in_array(0, $data, true); -> Option A
  5. Quick Check:

    Use in_array with strict=true for exact type match [OK]
Hint: Use in_array with strict=true to check exact value and type [OK]
Common Mistakes:
  • Ignoring strict parameter causing false positives
  • Using array_search without strict for type-sensitive check
  • Confusing '0' string with 0 integer
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