Type promotion in operations in NumPy - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is type promotion in numpy operations?

Type promotion is when numpy automatically converts data types during operations to a common type that can hold all values without loss.

beginner

What happens when you add an integer array and a float array in numpy?

Numpy promotes the integer array to float type before adding, so the result is a float array.

beginner

Why does numpy promote types during operations?

To avoid losing information by ensuring the result can represent all input values correctly.

intermediate

What is the result type when you multiply a float32 array with an int64 array in numpy?

The result is promoted to float64 because numpy chooses a common type that can hold both values safely.

intermediate

How does numpy handle type promotion with boolean and integer arrays?

Boolean values are promoted to integers (0 or 1) before the operation, so the result is an integer array.

What type does numpy promote when adding int32 and float64 arrays?

A float64

B int32

C float32

D int64

Numpy promotes to the more general type, float64, to avoid losing decimal information.

When multiplying a boolean array with an int array, what is the result type?

A boolean

B integer

C float

D string

Booleans are promoted to integers (0 or 1) before multiplication, so the result is integer.

If you add a float32 array and a float64 array, what will be the output type?

A float32

B object

C int64

D float64

Numpy promotes to the higher precision float64 to keep accuracy.

Why does numpy promote types during operations?

A To speed up calculations

B To save memory

C To avoid losing data

D To convert all to strings

Type promotion ensures no data is lost during operations.

What happens when you add an int8 array and a uint16 array?

A Result is int32

B Result is uint16

C Result is float64

D Result is int8

Numpy promotes to int32 to safely hold values from both types.

Explain how numpy decides the output data type when performing operations on arrays with different types.

Think about how numpy chooses a type that can hold all input values safely.

Describe what happens when you perform arithmetic operations between boolean and numeric numpy arrays.

Remember how True and False behave as numbers in numpy.

Practice

1. What happens in NumPy when you add an integer array to a float array?

easy

A. The result array will have integer type, truncating floats.

B. The result array will have float type due to type promotion.

C. NumPy throws a type error and stops execution.

D. The result array will have string type.

Solution

1. Step 1: Understand type promotion in mixed operations

   When adding int and float arrays, NumPy promotes the int to float to avoid losing decimal information.

2. Step 2: Check the resulting data type

   The output array will have float dtype because float has higher precision than int.

3. Final Answer:

   The result array will have float type due to type promotion. -> Option B

4. Quick Check:

   int + float = float [OK]

Hint: Mixed int and float always promote to float [OK]

Common Mistakes:

• Assuming result stays integer and truncates decimals
• Thinking NumPy throws an error on mixed types
• Believing result becomes string type

2. Which of the following NumPy operations correctly promotes types when multiplying an int array by a float scalar?

easy

A. np.array([1, 2, 3]) * 2.0

B. np.array([1, 2, 3]) * '2'

C. np.array([1, 2, 3]) * 2

D. np.array([1, 2, 3]) * np.array(['2', '3', '4'])

Solution

1. Step 1: Identify valid type promotion in multiplication

   Multiplying an int array by a float scalar promotes the result to float.

2. Step 2: Check each option for correct type promotion

   np.array([1, 2, 3]) * 2.0 multiplies by 2.0 (float), so result is float array. np.array([1, 2, 3]) * 2 multiplies by int 2, no promotion. The options involving strings cause errors.

3. Final Answer:

   np.array([1, 2, 3]) * 2.0 -> Option A

4. Quick Check:

   int array * float scalar = float array [OK]

Hint: Multiply int array by float scalar for float result [OK]

Common Mistakes:

• Using string instead of numeric scalar
• Expecting int result when multiplying by float
• Confusing string multiplication with numeric

3. What is the dtype of the result when you run this code?

import numpy as np
arr1 = np.array([1, 2, 3], dtype=np.int32)
arr2 = np.array([1.5, 2.5, 3.5], dtype=np.float64)
result = arr1 + arr2
dtype_result = result.dtype

medium

A. int32

B. object

C. float32

D. float64

Solution

1. Step 1: Identify input array dtypes

   arr1 is int32, arr2 is float64.

2. Step 2: Understand type promotion rules

   When adding int32 and float64, NumPy promotes to float64 to preserve precision.

3. Final Answer:

   float64 -> Option D

4. Quick Check:

   int32 + float64 = float64 [OK]

Hint: Higher precision float wins in mixed int-float ops [OK]

Common Mistakes:

• Assuming result is int32
• Confusing float32 with float64
• Expecting object dtype for numeric arrays

4. Consider this code snippet:

import numpy as np
arr = np.array([1, 2, 3], dtype=np.int8)
result = arr + 1.5

Why might the result's dtype not be what you expect if you change arr to np.int16?

medium

A. Because int16 promotes to string, causing unexpected dtype.

B. Because int16 does not promote and causes an error.

C. Because int16 promotes to float64, changing result dtype.

D. Because int16 promotes to int8, lowering precision.

Solution

1. Step 1: Understand type promotion with int8 and int16

   Adding float 1.5 to int8 promotes to float64. Similarly, int16 also promotes to float64.

2. Step 2: Explain why dtype changes with int16

   int16 has higher precision than int8 but still promotes to float64 when added to float, so result dtype is float64, not int16.

3. Final Answer:

   Because int16 promotes to float64, changing result dtype. -> Option C

4. Quick Check:

   int16 + float = float64 [OK]

Hint: Adding float promotes int16 to float64, not int16 [OK]

Common Mistakes:

• Thinking int16 causes error with float addition
• Assuming int16 promotes down to int8
• Believing result becomes string dtype

5. You have two arrays:

arr_int = np.array([1000, 2000], dtype=np.int16)
arr_float = np.array([0.1, 0.2], dtype=np.float32)

You want to add them and keep the result as float32 to save memory. Which code correctly achieves this with type promotion?

hard

A. result = arr_int.astype(np.float32) + arr_float

B. result = arr_int + arr_float.astype(np.float64)

C. result = arr_int + arr_float

D. result = arr_int.astype(np.int32) + arr_float

Solution

1. Step 1: Understand default type promotion

   Adding int16 and float32 promotes to float64 by default, increasing memory.

2. Step 2: Convert int16 to float32 before addition

   By converting arr_int to float32, adding float32 arrays keeps result as float32, saving memory.

3. Step 3: Check other options

   result = arr_int + arr_float.astype(np.float64) promotes to float64, increasing memory. result = arr_int + arr_float promotes to float64 by default. result = arr_int.astype(np.int32) + arr_float promotes int16 to int32, then adds float32, promoting to float64.

4. Final Answer:

   result = arr_int.astype(np.float32) + arr_float -> Option A

5. Quick Check:

   Cast int to float32 first to keep float32 result [OK]

Hint: Cast int to float32 before adding float32 to keep dtype [OK]

Common Mistakes:

• Ignoring default promotion to float64
• Casting float to float64 increasing memory
• Not casting int before addition