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NumPydata~10 mins

reshape() for changing dimensions in NumPy - Step-by-Step Execution

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Concept Flow - reshape() for changing dimensions
Start with 1D or ND array
Call reshape(new_shape)
Check if total elements match
Create new array
Return reshaped array
reshape() changes the shape of an array if the total number of elements stays the same. If not, it gives an error.
Execution Sample
NumPy
import numpy as np
arr = np.array([1, 2, 3, 4, 5, 6])
new_arr = arr.reshape((2, 3))
print(new_arr)
This code changes a 1D array of 6 elements into a 2x3 2D array.
Execution Table
StepActionInput ShapeNew ShapeCheck Total ElementsResult
1Create array(6,)--Array with elements [1 2 3 4 5 6]
2Call reshape((2,3))(6,)(2,3)6 == 2*3 (6)Pass
3Reshape array(6,)(2,3)-New array: [[1 2 3] [4 5 6]]
4Print new array(2,3)--[[1 2 3] [4 5 6]]
5Try invalid reshape(6,)(3,4)6 != 3*4 (12)Error: cannot reshape array of size 6 into shape (3,4)
💡 Execution stops after error because reshape dimensions do not match total elements.
Variable Tracker
VariableStartAfter reshape((2,3))After failed reshape((3,4))
arr[1 2 3 4 5 6][1 2 3 4 5 6][1 2 3 4 5 6]
new_arrN/A[[1 2 3] [4 5 6]]Error - no change
Key Moments - 2 Insights
Why does reshape((3,4)) cause an error when the original array has 6 elements?
Because 3*4=12 which is not equal to the original 6 elements. reshape() requires total elements to match exactly (see execution_table row 5).
Does reshape() change the data or just the shape?
reshape() only changes the shape, not the data order or values (see execution_table row 3 and 4).
Visual Quiz - 3 Questions
Test your understanding
Look at the execution table, what is the shape of new_arr after step 3?
A(2, 3)
B(3, 2)
C(6,)
D(3, 4)
💡 Hint
Check the 'New Shape' and 'Result' columns at step 3 in the execution_table.
At which step does the reshape operation fail due to incompatible dimensions?
AStep 2
BStep 5
CStep 3
DStep 4
💡 Hint
Look for the 'Error' message in the 'Result' column of the execution_table.
If the original array had 12 elements, which reshape would NOT cause an error?
Areshape((2, 3))
Breshape((4, 4))
Creshape((3, 4))
Dreshape((1, 5))
💡 Hint
Check the total elements needed for each shape and compare with 12.
Concept Snapshot
reshape() changes the shape of a numpy array without changing data.
Syntax: array.reshape(new_shape)
Total elements must match: product of new_shape == original size.
Raises error if sizes mismatch.
Useful to convert 1D arrays to 2D or higher dimensions.
Full Transcript
The reshape() function in numpy changes the shape of an array while keeping the same data. It requires that the total number of elements before and after reshaping is the same. For example, a 1D array with 6 elements can be reshaped into a 2x3 2D array. If you try to reshape into a shape that does not match the total elements, numpy raises an error. The data order stays the same; only the shape changes.