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np.vstack() and np.hstack() in NumPy - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to stack arrays vertically using numpy.

NumPy
import numpy as np

arr1 = np.array([1, 2, 3])
arr2 = np.array([4, 5, 6])
result = np.[1]([arr1, arr2])
print(result)
Drag options to blanks, or click blank then click option'
Ahstack
Bvstack
Cconcatenate
Dstack
Attempts:
3 left
💡 Hint
Common Mistakes
Using np.hstack() which stacks arrays horizontally.
Using np.concatenate() without specifying axis.
Using np.stack() which requires axis argument.
2fill in blank
medium

Complete the code to stack arrays horizontally using numpy.

NumPy
import numpy as np

arr1 = np.array([1, 2, 3])
arr2 = np.array([4, 5, 6])
result = np.[1]([arr1, arr2])
print(result)
Drag options to blanks, or click blank then click option'
Aconcatenate
Bvstack
Chstack
Dstack
Attempts:
3 left
💡 Hint
Common Mistakes
Using np.vstack() which stacks arrays vertically.
Using np.concatenate() without specifying axis.
Using np.stack() which requires axis argument.
3fill in blank
hard

Fix the error in the code to stack two 2D arrays vertically.

NumPy
import numpy as np

arr1 = np.array([[1, 2], [3, 4]])
arr2 = np.array([[5, 6]])
result = np.[1]([arr1, arr2])
print(result)
Drag options to blanks, or click blank then click option'
Ahstack
Bconcatenate
Cstack
Dvstack
Attempts:
3 left
💡 Hint
Common Mistakes
Using np.hstack() which requires matching row counts.
Using np.concatenate() without axis=0.
Using np.stack() without axis argument.
4fill in blank
hard

Fill both blanks to create a dictionary of word lengths for words longer than 3 letters.

NumPy
words = ['cat', 'house', 'dog', 'elephant']
lengths = {word: [1] for word in words if len(word) [2] 3}
print(lengths)
Drag options to blanks, or click blank then click option'
Alen(word)
B>
C<
Dword
Attempts:
3 left
💡 Hint
Common Mistakes
Using word instead of len(word) for value.
Using '<' instead of '>' in condition.
Not filtering words by length.
5fill in blank
hard

Fill all three blanks to create a dictionary with uppercase keys and values greater than 0.

NumPy
data = {'a': 1, 'b': -2, 'c': 3}
result = { [1]: [2] for k, v in data.items() if v [3] 0 }
print(result)
Drag options to blanks, or click blank then click option'
Ak.upper()
Bv
C>
Dk
Attempts:
3 left
💡 Hint
Common Mistakes
Using original keys without uppercase.
Filtering values less than or equal to zero.
Swapping keys and values in dictionary comprehension.

Practice

(1/5)
1. What does np.vstack() do with arrays?
easy
A. Stacks arrays vertically, adding rows
B. Stacks arrays horizontally, adding columns
C. Flattens arrays into one dimension
D. Splits arrays into smaller parts

Solution

  1. Step 1: Understand vertical stacking

    np.vstack() stacks arrays by adding rows one below another.
  2. Step 2: Compare with horizontal stacking

    np.hstack() stacks arrays side by side by adding columns, so it is different.
  3. Final Answer:

    Stacks arrays vertically, adding rows -> Option A
  4. Quick Check:

    np.vstack() = vertical stack [OK]
Hint: Remember 'v' in vstack means vertical stacking [OK]
Common Mistakes:
  • Confusing vertical and horizontal stacking
  • Thinking vstack flattens arrays
  • Assuming vstack splits arrays
2. Which of the following is the correct syntax to horizontally stack two arrays a and b using NumPy?
easy
A. np.hstack(a, b)
B. np.hstack[a, b]
C. np.hstack((a, b))
D. np.hstack{a, b}

Solution

  1. Step 1: Check function call syntax

    NumPy functions use parentheses and tuples for multiple arrays, so np.hstack((a, b)) is correct.
  2. Step 2: Identify incorrect syntax

    Square brackets, missing parentheses, or curly braces are invalid for function calls in Python.
  3. Final Answer:

    np.hstack((a, b)) -> Option C
  4. Quick Check:

    Correct function call uses parentheses and tuple [OK]
Hint: Use double parentheses for multiple arrays in hstack [OK]
Common Mistakes:
  • Using square brackets instead of parentheses
  • Passing arrays without tuple parentheses
  • Using curly braces which are invalid
3. What is the output of the following code?
import numpy as np
x = np.array([[1, 2], [3, 4]])
y = np.array([[5, 6], [7, 8]])
result = np.vstack((x, y))
print(result)
medium
A. [[1 2 5 6] [3 4 7 8]]
B. [[1 2 3 4] [5 6 7 8]]
C. [[1 2] [5 6] [3 4] [7 8]]
D. [[1 2] [3 4] [5 6] [7 8]]

Solution

  1. Step 1: Understand np.vstack behavior

    It stacks arrays vertically, so rows of y come below rows of x.
  2. Step 2: Combine arrays row-wise

    Result has 4 rows: first two from x, next two from y, each with 2 columns.
  3. Final Answer:

    [[1 2] [3 4] [5 6] [7 8]] -> Option D
  4. Quick Check:

    Vertical stack adds rows below [OK]
Hint: vstack adds rows; hstack adds columns [OK]
Common Mistakes:
  • Confusing vstack with hstack output
  • Expecting horizontal concatenation
  • Misreading array shapes
4. What error will occur when running this code?
import numpy as np
a = np.array([1, 2, 3])
b = np.array([[4, 5, 6], [7, 8, 9]])
result = np.hstack((a, b))
print(result)
medium
A. No error, outputs concatenated array
B. TypeError because inputs are not lists
C. SyntaxError due to wrong function call
D. ValueError due to incompatible shapes

Solution

  1. Step 1: Check shapes of arrays

    a is shape (3,), b is shape (2,3). They differ in first dimension.
  2. Step 2: Understand hstack requirements

    np.hstack() stacks arrays along their second axis if possible. Here, a is 1D and b is 2D, but NumPy broadcasts a to shape (1,3) and stacks along axis 1, resulting in shape (3,3).
  3. Step 3: Result

    No error occurs; arrays are concatenated.
  4. Final Answer:

    No error, outputs concatenated array -> Option A
  5. Quick Check:

    NumPy broadcasts 1D array and concatenates [OK]
Hint: NumPy can broadcast 1D arrays when stacking [OK]
Common Mistakes:
  • Assuming hstack requires same number of rows
  • Confusing ValueError with TypeError
  • Ignoring NumPy broadcasting rules
5. Given two arrays:
a = np.array([[1, 2], [3, 4]])
b = np.array([[5, 6, 7], [8, 9, 10]])
Which method correctly combines them into a single array with shape (2, 5) by stacking horizontally?
hard
A. np.vstack((a, b))
B. np.hstack((a, b))
C. np.hstack((a.T, b.T)).T
D. np.vstack((a.T, b.T)).T

Solution

  1. Step 1: Check shapes of arrays

    a shape is (2, 2), b shape is (2, 3). Both have 2 rows, so horizontal stacking is possible.
  2. Step 2: Apply np.hstack

    np.hstack((a, b)) concatenates columns, resulting in shape (2, 5).
  3. Step 3: Verify other options

    np.vstack((a, b)) would fail due to different column counts; transposes complicate shape and are unnecessary here.
  4. Final Answer:

    np.hstack((a, b)) -> Option B
  5. Quick Check:

    Same rows, hstack adds columns [OK]
Hint: For same rows, use hstack to add columns [OK]
Common Mistakes:
  • Using vstack with different column counts
  • Overcomplicating with transpose
  • Mixing up row and column dimensions
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