np.min() and np.max() in NumPy - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to find the minimum value in the array.

NumPy

import numpy as np
arr = np.array([3, 7, 1, 9, 5])
min_value = np.[1](arr)
print(min_value)

Drag options to blanks, or click blank then click option'

Amax

Bmean

Csum

Dmin

Attempts:

3 left

💡 Hint

Common Mistakes

Using np.max() instead of np.min()

Trying to use Python's built-in min() without numpy

The np.min() function returns the smallest value in the array.

2fill in blank

medium

Complete the code to find the maximum value in the 2D array.

NumPy

import numpy as np
arr = np.array([[4, 2, 8], [1, 7, 5]])
max_value = np.[1](arr)
print(max_value)

Drag options to blanks, or click blank then click option'

Amax

Bmin

Cmedian

Daverage

Attempts:

3 left

💡 Hint

Common Mistakes

Using np.min() instead of np.max()

Trying to use Python's built-in max() without numpy

The np.max() function returns the largest value in the array.

3fill in blank

hard

Fix the error in the code to correctly find the minimum value along axis 0.

NumPy

import numpy as np
arr = np.array([[10, 20], [5, 15]])
min_values = np.min(arr, [1]=0)
print(min_values)

Drag options to blanks, or click blank then click option'

Aaxis

Baxes

Cdim

Ddirection

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'axes' instead of 'axis'

Using 'dim' or 'direction' which are invalid parameters

The correct parameter name to specify the axis is axis.

4fill in blank

hard

Fill both blanks to create a dictionary of max values for each column in the array.

NumPy

import numpy as np
arr = np.array([[3, 6, 9], [2, 8, 5]])
max_dict = {i: np.[1](arr, [2]=0)[i] for i in range(arr.shape[1])}
print(max_dict)

Drag options to blanks, or click blank then click option'

Amax

Bmin

Caxis

Ddim

Attempts:

3 left

💡 Hint

Common Mistakes

Using np.min() instead of np.max()

Using 'dim' instead of 'axis' as parameter

Use np.max() to find max values and axis to specify the dimension.

5fill in blank

hard

Fill all three blanks to create a dictionary of min values for each row in the array.

NumPy

import numpy as np
arr = np.array([[7, 4, 1], [3, 9, 6]])
min_dict = {i: np.[1](arr, [2]=1)[[3]] for i in range(arr.shape[0])}
print(min_dict)

Drag options to blanks, or click blank then click option'

Amax

Bmin

Caxis

Di

Attempts:

3 left

💡 Hint

Common Mistakes

Using np.max() instead of np.min()

Using wrong parameter name instead of 'axis'

Using a fixed number instead of the loop variable

Use np.min() to find minimum values, axis to specify dimension, and i as the axis index.