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NumPydata~10 mins

np.mean() for average in NumPy - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to calculate the average of the list using numpy.

NumPy
import numpy as np
numbers = [10, 20, 30, 40, 50]
average = np.[1](numbers)
print(average)
Drag options to blanks, or click blank then click option'
Amedian
Bsum
Cmean
Dmax
Attempts:
3 left
๐Ÿ’ก Hint
Common Mistakes
Using np.sum() instead of np.mean() which sums the numbers instead of averaging.
Using np.max() which finds the largest number, not the average.
2fill in blank
medium

Complete the code to calculate the average of the numpy array.

NumPy
import numpy as np
arr = np.array([5, 15, 25, 35, 45])
avg = np.[1](arr)
print(avg)
Drag options to blanks, or click blank then click option'
Amean
Bsum
Cmin
Dstd
Attempts:
3 left
๐Ÿ’ก Hint
Common Mistakes
Using np.sum() which adds all elements instead of averaging.
Using np.min() which finds the smallest element.
3fill in blank
hard

Fix the error in the code to correctly calculate the average of the list.

NumPy
import numpy as np
values = [2, 4, 6, 8, 10]
average = np.[1](values)
print(average)
Drag options to blanks, or click blank then click option'
Amean
Baverage
Cavg
Dmedian
Attempts:
3 left
๐Ÿ’ก Hint
Common Mistakes
Using 'average' or 'avg' which are not numpy functions.
Using 'median' which calculates the middle value, not the average.
4fill in blank
hard

Fill both blanks to create a dictionary with words as keys and their lengths as values, but only include words longer than 3 letters.

NumPy
words = ['cat', 'house', 'dog', 'elephant']
lengths = {word: [1] for word in words if len(word) [2] 3}
print(lengths)
Drag options to blanks, or click blank then click option'
Alen(word)
Bword
C>
D<=
Attempts:
3 left
๐Ÿ’ก Hint
Common Mistakes
Using the word itself as the value instead of its length.
Using '<=' instead of '>' which includes shorter words.
5fill in blank
hard

Fill all three blanks to create a dictionary with uppercase words as keys and their lengths as values, including only words longer than 4 letters.

NumPy
words = ['apple', 'bat', 'carrot', 'dog']
result = { [1]: [2] for w in words if len(w) [3] 4 }
print(result)
Drag options to blanks, or click blank then click option'
Aw.upper()
Blen(w)
C>
Dw
Attempts:
3 left
๐Ÿ’ก Hint
Common Mistakes
Using the original word instead of uppercase for keys.
Using '<' or '<=' instead of '>' which changes the filter condition.

Practice

(1/5)
1. What does the function np.mean() do when applied to a list or array?
easy
A. Counts the number of elements in the list or array
B. Finds the maximum value in the list or array
C. Sorts the list or array in ascending order
D. Calculates the average (mean) value of the numbers

Solution

  1. Step 1: Understand the purpose of np.mean()

    The function np.mean() is designed to calculate the average value of numbers in a list or array.
  2. Step 2: Compare with other options

    Other options describe different functions: maximum value, count, or sorting, which are not what np.mean() does.
  3. Final Answer:

    Calculates the average (mean) value of the numbers -> Option D
  4. Quick Check:

    np.mean() = average [OK]
Hint: Mean = sum of values รท number of values [OK]
Common Mistakes:
  • Confusing mean with max or count
  • Thinking it sorts the data
  • Using sum instead of mean
2. Which of the following is the correct syntax for np.mean() to calculate the mean of a NumPy array named arr?
easy
A. np.mean(arr)
B. mean(arr)
C. arr.mean()
D. np.average(arr)

Solution

  1. Step 1: Identify the standard NumPy function for mean

    The correct function to calculate mean in NumPy is np.mean(), which takes the array as an argument.
  2. Step 2: Check other options

    mean(arr) is not defined without importing; arr.mean() is valid but not the function asked; np.average(arr) is similar but not the exact function requested.
  3. Final Answer:

    np.mean(arr) -> Option A
  4. Quick Check:

    Use np.mean(array) for average [OK]
Hint: Use np.mean(array) to get average quickly [OK]
Common Mistakes:
  • Calling mean() without np prefix
  • Using arr.mean() instead of np.mean(arr)
  • Confusing np.mean() with np.average()
3. What is the output of the following code?
import numpy as np
arr = np.array([[1, 2, 3], [4, 5, 6]])
result = np.mean(arr, axis=0)
print(result)
medium
A. [1.5 2.5 3.5]
B. [3. 4. 5.]
C. [2.5 3.5 4.5]
D. [3.5 4.5 5.5]

Solution

  1. Step 1: Understand the array and axis parameter

    The array is 2 rows by 3 columns: [[1,2,3],[4,5,6]]. Using axis=0 means calculating the mean down each column.
  2. Step 2: Calculate mean for each column

    Column 1: (1+4)/2 = 2.5, Column 2: (2+5)/2 = 3.5, Column 3: (3+6)/2 = 4.5. So the result is [2.5, 3.5, 4.5].
  3. Step 3: Check options carefully

    [2.5 3.5 4.5] matches the calculated values exactly.
  4. Final Answer:

    [2.5 3.5 4.5] -> Option C
  5. Quick Check:

    Mean along axis=0 averages columns [OK]
Hint: Axis=0 averages columns, axis=1 averages rows [OK]
Common Mistakes:
  • Mixing axis=0 and axis=1
  • Calculating mean of entire array instead of axis
  • Misreading array shape
4. The following code throws an error. What is the problem?
import numpy as np
arr = [1, 2, 3, 4]
result = np.mean(arr, axis=1)
print(result)
medium
A. np.mean() cannot be used on lists
B. The list is 1D, so axis=1 is invalid
C. Missing parentheses in np.mean
D. The variable name 'arr' is reserved

Solution

  1. Step 1: Check the array shape

    The variable arr is a 1D list with shape (4,). Axis 1 does not exist in 1D data.
  2. Step 2: Understand axis parameter

    Axis=1 means operate along columns in 2D or higher arrays. Using axis=1 on 1D data causes an error.
  3. Final Answer:

    The list is 1D, so axis=1 is invalid -> Option B
  4. Quick Check:

    Axis must exist in array shape [OK]
Hint: Check array dimensions before using axis [OK]
Common Mistakes:
  • Using axis parameter on 1D arrays
  • Thinking np.mean can't handle lists
  • Confusing axis indexing
5. You have a 3D NumPy array representing daily temperatures for 2 cities over 3 days with 4 measurements each day:
temps = np.array([
  [[20, 22, 21, 23], [19, 20, 22, 21]],
  [[21, 23, 22, 24], [20, 21, 23, 22]],
  [[22, 24, 23, 25], [21, 22, 24, 23]]
])

Which code correctly calculates the average temperature for each city over all days and measurements?
hard
A. np.mean(temps, axis=(0,2))
B. np.mean(temps, axis=0)
C. np.mean(temps, axis=1)
D. np.mean(temps, axis=2)

Solution

  1. Step 1: Understand the array shape and axes

    The array shape is (3, 2, 4): 3 days, 2 cities, 4 measurements each day.
  2. Step 2: Identify axes to average over

    To get average per city over all days and measurements, we average over days (axis 0) and measurements (axis 2), keeping axis 1 (cities).
  3. Step 3: Use axis=(0,2) in np.mean

    Using np.mean(temps, axis=(0,2)) averages over days and measurements, resulting in average per city.
  4. Final Answer:

    np.mean(temps, axis=(0,2)) -> Option A
  5. Quick Check:

    Average over days and measurements = axis 0 and 2 [OK]
Hint: Use tuple axis to average multiple dimensions [OK]
Common Mistakes:
  • Averaging over wrong axes
  • Using single axis instead of tuple
  • Confusing city axis with day or measurement axis
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