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Node.jsframework~30 mins

Child process exit codes in Node.js - Mini Project: Build & Apply

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Child Process Exit Codes in Node.js
📖 Scenario: You are building a Node.js script that runs a child process to execute a simple command. You want to check the exit code of the child process to know if it ran successfully or if there was an error.
🎯 Goal: Create a Node.js script that spawns a child process to run the ls command, captures its exit code, and prints a message based on whether the command succeeded or failed.
📋 What You'll Learn
Use the child_process module to spawn a child process
Run the ls command using spawn
Listen for the exit event to get the exit code
Print Success if exit code is 0, otherwise print Failure
💡 Why This Matters
🌍 Real World
Developers often run other programs from Node.js scripts and need to know if those programs finished successfully.
💼 Career
Understanding child process exit codes is important for building reliable automation scripts, deployment tools, and server-side applications.
Progress0 / 4 steps
1
Import the child_process module and create the child process
Write code to import spawn from the child_process module and create a child process called lsProcess that runs the ls command with no arguments.
Node.js
Hint

Use const { spawn } = require('child_process') to import spawn. Then call spawn('ls') to run the command.

2
Add a variable to hold the exit code
Create a variable called exitCode and set it to null. This will store the exit code of the child process.
Node.js
Hint

Use let exitCode = null to create the variable.

3
Listen for the exit event and save the exit code
Add an event listener on lsProcess for the exit event. Use (code) => as the callback parameter and assign code to the exitCode variable.
Node.js
Hint

Use lsProcess.on('exit', (code) => { exitCode = code; }) to capture the exit code.

4
Print success or failure based on the exit code
Add an event listener on lsProcess for the close event. Inside the callback, check if exitCode is 0. If yes, print Success. Otherwise, print Failure.
Node.js
Hint

Use lsProcess.on('close', () => { if (exitCode === 0) console.log('Success'); else console.log('Failure'); }).

Practice

(1/5)
1. What does an exit code of 0 from a Node.js child process usually mean?
easy
A. The process finished successfully without errors.
B. The process was terminated by a signal.
C. The process encountered an error and crashed.
D. The process is still running.

Solution

  1. Step 1: Understand exit codes in Node.js child processes

    Exit codes indicate how a process ended. Code 0 means success.
  2. Step 2: Interpret exit code 0

    Exit code 0 means the process finished without errors or interruptions.
  3. Final Answer:

    The process finished successfully without errors. -> Option A
  4. Quick Check:

    Exit code 0 = success [OK]
Hint: Exit code 0 always means success in child processes [OK]
Common Mistakes:
  • Confusing exit code 0 with error codes
  • Thinking signal termination returns 0
  • Assuming non-zero codes mean success
2. Which of the following is the correct way to listen for a child process exit event in Node.js?
easy
A. child.listen('exit', (code) => { /* handle exit */ });
B. child.exit(() => { /* handle exit */ });
C. child.onExit((code) => { /* handle exit */ });
D. child.on('exit', (code, signal) => { /* handle exit */ });

Solution

  1. Step 1: Recall Node.js child process event syntax

    Node.js child processes emit events listened with on method.
  2. Step 2: Confirm correct event and parameters

    The 'exit' event uses child.on('exit', (code, signal) => {}) syntax.
  3. Final Answer:

    child.on('exit', (code, signal) => { /* handle exit */ }); -> Option D
  4. Quick Check:

    Use child.on('exit', callback) [OK]
Hint: Use child.on('exit', callback) to catch exit events [OK]
Common Mistakes:
  • Using non-existent methods like exit() or onExit()
  • Using listen() instead of on()
  • Missing parameters in the callback
3. Consider this code snippet:
const { spawn } = require('child_process');
const child = spawn('node', ['-e', "process.exit(5)"]);
child.on('exit', (code, signal) => {
  console.log(`Exit code: ${code}, Signal: ${signal}`);
});

What will be printed when this code runs?
medium
A. Exit code: 0, Signal: null
B. Exit code: 5, Signal: null
C. Exit code: null, Signal: SIGTERM
D. Exit code: 1, Signal: null

Solution

  1. Step 1: Understand the child process exit code

    The child process runs process.exit(5), so it exits with code 5.
  2. Step 2: Check the exit event parameters

    The exit event callback receives code 5 and signal null because it exited normally with code 5.
  3. Final Answer:

    Exit code: 5, Signal: null -> Option B
  4. Quick Check:

    process.exit(5) sets exit code 5 [OK]
Hint: process.exit(n) sets exit code n, signal is null if normal exit [OK]
Common Mistakes:
  • Assuming exit code is always 0
  • Confusing signal with exit code
  • Expecting signal to be set on normal exit
4. You wrote this code to spawn a child process and listen for exit:
const { spawn } = require('child_process');
const child = spawn('node', ['-e', "setTimeout(() => process.exit(0), 1000)"]);
child.unref();
child.on('exit', (code) => {
  console.log(`Exited with code ${code}`);
});

But the console never logs anything. What is the likely problem?
medium
A. The exit event callback is missing the signal parameter.
B. The child process is not exiting because the event loop is blocked.
C. The child process exits after 1 second, but the main program ends before that.
D. The spawn command syntax is incorrect.

Solution

  1. Step 1: Analyze the child process behavior

    The child process exits after 1 second due to setTimeout.
  2. Step 2: Consider the main program lifecycle

    If the main program ends before 1 second, it may exit before child finishes, so no log appears.
  3. Final Answer:

    The child process exits after 1 second, but the main program ends before that. -> Option C
  4. Quick Check:

    Main program must stay alive to see child exit [OK]
Hint: Keep main program alive to catch delayed child exit events [OK]
Common Mistakes:
  • Thinking missing signal parameter breaks event
  • Assuming spawn syntax is wrong without error
  • Ignoring asynchronous timing of child exit
5. You want to run a child process and handle both normal exit and signal termination. Which code snippet correctly logs the exit code or signal received?
hard
A. child.on('exit', (code, signal) => { if (code !== null) console.log(`Exited with code ${code}`); else console.log(`Terminated by signal ${signal}`); });
B. child.on('exit', (code) => { if (code === 0) console.log('Success'); else console.log('Error'); });
C. child.on('close', (signal) => { console.log(`Closed with signal ${signal}`); });
D. child.on('exit', () => { console.log('Process ended'); });

Solution

  1. Step 1: Understand exit event parameters

    The 'exit' event provides two parameters: code (number or null) and signal (string or null).
  2. Step 2: Handle both exit code and signal

    If code is not null, process ended normally; if null, it was terminated by a signal.
  3. Step 3: Check code snippet correctness

    child.on('exit', (code, signal) => { if (code !== null) console.log(`Exited with code ${code}`); else console.log(`Terminated by signal ${signal}`); }); correctly checks code and signal and logs accordingly.
  4. Final Answer:

    child.on('exit', (code, signal) => { if (code !== null) console.log(`Exited with code ${code}`); else console.log(`Terminated by signal ${signal}`); }); -> Option A
  5. Quick Check:

    Check code !== null to distinguish exit vs signal [OK]
Hint: Check if exit code is null to detect signal termination [OK]
Common Mistakes:
  • Ignoring the signal parameter in exit event
  • Using 'close' event instead of 'exit' for exit codes
  • Not checking for null exit code before logging