Regular expressions for text cleaning in NLP - ML Experiment: Train & Evaluate

Experiment - Regular expressions for text cleaning

Problem:You have a text dataset with noisy data including extra spaces, special characters, and inconsistent capitalization. This noise makes it hard for your model to learn well.

Current Metrics:Text cleaning accuracy: 70% (measured by how well cleaned text matches expected clean text samples)

Issue:The current cleaning method misses many unwanted characters and does not normalize text well, causing poor data quality.

Your Task

Improve text cleaning by using regular expressions to remove unwanted characters, extra spaces, and normalize text to lowercase, aiming for at least 90% cleaning accuracy.

Use Python's re module for regular expressions

Do not use external text cleaning libraries

Keep the cleaning function simple and efficient

Hint 1

Hint 2

Hint 3

Hint 4

Solution

NLP

import re

def clean_text(text: str) -> str:
    # Remove special characters except letters and spaces
    text = re.sub(r'[^a-zA-Z\s]', '', text)
    # Convert to lowercase
    text = text.lower()
    # Replace multiple spaces with a single space
    text = re.sub(r'\s+', ' ', text)
    # Strip leading and trailing spaces
    return text.strip()

# Example usage
sample_text = "Hello!!! This   is a sample... Text, with #noisy *characters* & extra spaces."
cleaned = clean_text(sample_text)
print(cleaned)  # Output: 'hello this is a sample text with noisy characters extra spaces'

Used re.sub() to remove all characters except letters and spaces

Converted all text to lowercase for normalization

Replaced multiple spaces with a single space

Trimmed leading and trailing spaces

Results Interpretation

Before: Text cleaning accuracy was 70%, with many special characters and inconsistent spacing remaining.

After: Accuracy improved to 92%, with text normalized to lowercase, special characters removed, and spacing fixed.

Regular expressions are powerful tools to clean and normalize text data, which improves data quality and helps machine learning models perform better.

Bonus Experiment

Try extending the cleaning function to also remove common stopwords (like 'the', 'is', 'and') using a simple list.

💡 Hint

After cleaning, split text into words, filter out stopwords, then join back into a string.

Practice

1. What is the main purpose of using regular expressions in text cleaning for NLP?

easy

A. To find and remove unwanted patterns or characters in text

B. To train machine learning models directly

C. To store large datasets efficiently

D. To visualize text data with graphs

Solution

1. Step 1: Understand the role of regular expressions

   Regular expressions are used to identify patterns in text, such as unwanted characters or specific sequences.

2. Step 2: Connect to text cleaning

   Text cleaning involves removing or replacing unwanted parts of text to prepare it for analysis or modeling.

3. Final Answer:

   To find and remove unwanted patterns or characters in text -> Option A

4. Quick Check:

   Regular expressions clean text by pattern matching [OK]

Hint: Regular expressions = pattern search and replace in text [OK]

Common Mistakes:

• Confusing regex with model training
• Thinking regex stores data
• Assuming regex creates visualizations

2. Which of the following is the correct Python syntax to import the regular expression module?

easy

A. from regex import *

B. import regex

C. import re

D. import regular_expression

Solution

1. Step 1: Recall Python's regex module name

   Python's built-in module for regular expressions is named 're'.

2. Step 2: Check syntax correctness

   The correct import statement is 'import re' to use regex functions.

3. Final Answer:

   import re -> Option C

4. Quick Check:

   Python regex module = re [OK]

Hint: Remember: Python regex module is 're' not 'regex' [OK]

Common Mistakes:

• Using 'import regex' which is not standard
• Trying to import non-existent modules
• Confusing module names with function names

3. What will be the output of this Python code snippet?

import re
text = "Hello, World! 123"
cleaned = re.sub(r'[^a-zA-Z ]', '', text)
print(cleaned)

medium

A. Hello World

B. Hello World 123

C. Hello, World!

D. HelloWorld123

Solution

1. Step 1: Understand the regex pattern used

   The pattern '[^a-zA-Z ]' means any character NOT a letter (a-z or A-Z) or space.

2. Step 2: Apply re.sub to remove unwanted characters

   All characters except letters and spaces are removed, so commas, exclamation marks, and digits are deleted.

3. Final Answer:

   Hello World -> Option A

4. Quick Check:

   Regex removes non-letters/spaces = 'Hello World ' [OK]

Hint: [^...] means NOT those characters, so it removes digits and punctuation [OK]

Common Mistakes:

• Thinking digits remain after substitution
• Confusing character classes with ranges
• Ignoring spaces in the pattern

4. Identify the error in this regex code snippet for removing digits from text:

import re
text = "Price: 100 dollars"
cleaned = re.sub(r'\d', '', text)
print(cleaned)

medium

A. The pattern '\d' should be '\D' to remove digits

B. The backslash in '\d' is not escaped properly

C. The re.sub function is used incorrectly

D. The code will run correctly and remove digits

Solution

1. Step 1: Check regex pattern correctness

   The pattern r'\d' correctly matches digits (0-9).

2. Step 2: Verify code syntax and function usage

   The code uses raw string r'\d' which properly escapes the backslash, so digits are removed as intended.

3. Final Answer:

   The code will run correctly and remove digits -> Option D

4. Quick Check:

   r'\d' matches digits; re.sub removes them correctly [OK]

Hint: In raw strings, r'\d' matches digits; no extra escaping needed [OK]

Common Mistakes:

• Thinking '\d' needs double escaping outside raw strings
• Confusing '\d' with '\D' (non-digit)
• Assuming re.sub syntax is wrong

5. You want to clean a text dataset by removing all URLs and extra spaces. Which regex pattern and code snippet correctly achieves this in Python?

import re
text = "Visit https://example.com now!  Enjoy!"
cleaned = re.sub(_____, ' ', text)
cleaned = re.sub(r'\s+', ' ', cleaned).strip()
print(cleaned)

hard

A. r'http://[a-z]+'

B. r'https?://\S+'

C. r'www\.[a-z]+\.com'

D. r'https?://[a-z]+'

Solution

1. Step 1: Identify a regex pattern that matches URLs

   The pattern 'https?://' matches 'http://' or 'https://', and '\S+' matches non-space characters following it, capturing full URLs.

2. Step 2: Understand the code's cleaning steps

   First, URLs are replaced by a space, then multiple spaces are reduced to one, and leading/trailing spaces removed.

3. Final Answer:

   r'https?://\S+' -> Option B

4. Quick Check:

   Use 'https?://\S+' to remove URLs effectively [OK]

Hint: Use 'https?://' plus '\S+' to match full URLs [OK]

Common Mistakes:

• Using too narrow patterns missing https or full URL
• Not removing extra spaces after substitution
• Using patterns that match only partial URLs