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Regularization (Ridge, Lasso) in ML Python - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to import the Ridge regression model from scikit-learn.

ML Python
from sklearn.linear_model import [1]
Drag options to blanks, or click blank then click option'
ALinearRegression
BLasso
CLogisticRegression
DRidge
Attempts:
3 left
💡 Hint
Common Mistakes
Confusing Ridge with Lasso.
Trying to import LinearRegression instead.
2fill in blank
medium

Complete the code to create a Lasso regression model with alpha set to 0.1.

ML Python
model = Lasso(alpha=[1])
Drag options to blanks, or click blank then click option'
A0.1
B0
C10
D1.0
Attempts:
3 left
💡 Hint
Common Mistakes
Using alpha=0 which disables regularization.
Using a very large alpha like 10 which over-regularizes.
3fill in blank
hard

Fix the error in the code to fit a Ridge model to data X and y.

ML Python
model = Ridge(alpha=1.0)
model.[1](X, y)
Drag options to blanks, or click blank then click option'
Apredict
Btransform
Cfit
Dscore
Attempts:
3 left
💡 Hint
Common Mistakes
Calling predict before fitting the model.
Using transform which is not available for Ridge.
4fill in blank
hard

Fill both blanks to create a dictionary of coefficients from a trained Lasso model for features in feature_names.

ML Python
coef_dict = {feature: model.[1][i] for i, feature in enumerate([2])}
Drag options to blanks, or click blank then click option'
Acoef_
Bfeature_names
Cintercept_
Dpredict
Attempts:
3 left
💡 Hint
Common Mistakes
Using intercept_ instead of coef_.
Using predict which is a method, not an attribute.
5fill in blank
hard

Fill all three blanks to compute the mean squared error (MSE) between true values y_true and predicted values y_pred.

ML Python
from sklearn.metrics import [1]
y_pred = model.predict(X_test)
mse = [2](y_true, [3])
Drag options to blanks, or click blank then click option'
Amean_squared_error
By_pred
Daccuracy_score
Attempts:
3 left
💡 Hint
Common Mistakes
Using accuracy_score which is for classification.
Mixing up the order of true and predicted values.

Practice

(1/5)
1. What is the main purpose of regularization in machine learning models?
easy
A. To prevent overfitting by adding a penalty to large weights
B. To increase the size of the training dataset
C. To speed up the training process by reducing data
D. To remove all features from the model

Solution

  1. Step 1: Understand overfitting

    Overfitting happens when a model learns noise instead of the true pattern, causing poor performance on new data.
  2. Step 2: Role of regularization

    Regularization adds a penalty to large weights, which helps the model generalize better by keeping weights small.
  3. Final Answer:

    To prevent overfitting by adding a penalty to large weights -> Option A
  4. Quick Check:

    Regularization = Prevent overfitting [OK]
Hint: Regularization controls model complexity by penalizing big weights [OK]
Common Mistakes:
  • Thinking regularization increases data size
  • Confusing regularization with feature removal
  • Believing regularization speeds up training
2. Which of the following is the correct way to import Ridge regression from scikit-learn in Python?
easy
A. import sklearn.linear_model.Ridge
B. from sklearn.linear_model import Ridge
C. from sklearn import Ridge
D. import Ridge from sklearn.linear_model

Solution

  1. Step 1: Recall Python import syntax

    In Python, to import a class from a module, the syntax is 'from module import Class'.
  2. Step 2: Apply to Ridge regression

    Ridge is a class inside sklearn.linear_model, so the correct import is 'from sklearn.linear_model import Ridge'.
  3. Final Answer:

    from sklearn.linear_model import Ridge -> Option B
  4. Quick Check:

    Correct import syntax = from sklearn.linear_model import Ridge [OK]
Hint: Use 'from module import Class' to import classes in Python [OK]
Common Mistakes:
  • Using 'import Class from module' which is invalid syntax
  • Trying to import module and class together incorrectly
  • Using dot notation in import statement
3. Consider the following Python code using Lasso regression:
from sklearn.linear_model import Lasso
import numpy as np

X = np.array([[1, 2], [3, 4], [5, 6]])
y = np.array([1, 2, 3])
model = Lasso(alpha=2.0)
model.fit(X, y)
pred = model.predict(np.array([[7, 8]]))
print(round(pred[0], 2))

What is the printed output?
medium
A. 2.5
B. 2.0
C. 3.0
D. 1.0

Solution

  1. Step 1: Understand Lasso fitting on small data

    Lasso applies L1 penalty, shrinking some coefficients possibly to zero. With alpha=2.0, coefficients shrink significantly.
  2. Step 2: Predict value for input [7, 8]

    Given the linear trend in X and y (unregularized prediction 4.0), with alpha=2.0 the prediction is approximately 2.5 after regularization.
  3. Final Answer:

    2.5 -> Option A
  4. Quick Check:

    Lasso prediction ≈ 2.5 [OK]
Hint: Lasso shrinks coefficients, prediction near linear trend but reduced by alpha [OK]
Common Mistakes:
  • Assuming prediction equals last y value
  • Ignoring effect of alpha on coefficients
  • Confusing Ridge and Lasso penalties
4. The following code tries to use Ridge regression but throws an error:
from sklearn.linear_model import Ridge
model = Ridge(alpha='one')
model.fit(X_train, y_train)

What is the error and how to fix it?
medium
A. SyntaxError due to wrong import statement; fix import syntax
B. NameError because Ridge is not imported; fix by importing Ridge
C. ValueError because X_train is missing; fix by defining X_train
D. ValueError because alpha must be a float; fix by using alpha=1.0

Solution

  1. Step 1: Identify the error cause

    Alpha parameter expects a numeric value (float), but 'one' is a string causing ValueError.
  2. Step 2: Fix the error

    Replace alpha='one' with alpha=1.0 to provide a valid float value.
  3. Final Answer:

    ValueError because alpha must be a float; fix by using alpha=1.0 -> Option D
  4. Quick Check:

    Alpha must be float, not string [OK]
Hint: Alpha must be a number, not a string [OK]
Common Mistakes:
  • Passing string instead of float for alpha
  • Ignoring error message details
  • Assuming import error without checking code
5. You have a dataset with many features, some of which are irrelevant. You want a model that both reduces overfitting and selects important features by setting some coefficients exactly to zero. Which regularization method should you choose?
hard
A. Ridge regression because it shrinks coefficients but keeps all features
B. Neither Ridge nor Lasso; use standard linear regression
C. Lasso regression because it can set some coefficients to zero, removing features
D. Use Ridge with very small alpha to remove features

Solution

  1. Step 1: Understand feature selection need

    To remove irrelevant features, the model must set some coefficients exactly to zero.
  2. Step 2: Compare Ridge and Lasso

    Ridge shrinks coefficients but does not zero them out; Lasso uses L1 penalty and can zero coefficients, effectively selecting features.
  3. Final Answer:

    Lasso regression because it can set some coefficients to zero, removing features -> Option C
  4. Quick Check:

    Lasso = feature selection + regularization [OK]
Hint: Lasso zeros coefficients; Ridge only shrinks [OK]
Common Mistakes:
  • Thinking Ridge removes features by zeroing coefficients
  • Choosing no regularization for feature selection
  • Confusing alpha size effect on feature removal
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10 questions~5 mineasy hard