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K-Means clustering in ML Python - Practice Problems & Coding Challenges

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Challenge - 5 Problems
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K-Means Mastery
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🧠 Conceptual
intermediate
2:00remaining
Understanding the K-Means Objective
What is the main goal of the K-Means clustering algorithm?
ATo minimize the sum of squared distances between data points and their assigned cluster centers
BTo find the cluster centers that maximize the total variance within clusters
CTo assign each data point to a unique cluster without overlap
DTo maximize the distance between all data points in the dataset
Attempts:
2 left
💡 Hint
Think about how K-Means groups points close to each other.
❓ Predict Output
intermediate
2:00remaining
Output of K-Means Cluster Assignments
What is the output of the following Python code snippet using scikit-learn's KMeans?
ML Python
from sklearn.cluster import KMeans
import numpy as np

X = np.array([[1, 2], [1, 4], [1, 0], [10, 2], [10, 4], [10, 0]])
kmeans = KMeans(n_clusters=2, random_state=0).fit(X)
print(kmeans.labels_)
A[1 1 1 0 0 0]
B[0 1 0 1 0 1]
C[1 0 1 0 1 0]
D[0 0 0 1 1 1]
Attempts:
2 left
💡 Hint
Look at how points are grouped by proximity.
❓ Hyperparameter
advanced
2:00remaining
Choosing the Number of Clusters (k)
Which method is commonly used to decide the best number of clusters (k) in K-Means clustering?
AElbow method by plotting within-cluster sum of squares versus k
BUsing the highest possible k to maximize clusters
CChoosing k based on the number of features in the dataset
DRandomly selecting k without evaluation
Attempts:
2 left
💡 Hint
Think about a plot that shows diminishing returns.
❓ Metrics
advanced
2:00remaining
Evaluating K-Means Clustering Quality
Which metric measures how well-separated the clusters are in K-Means clustering?
AMean squared error
BSilhouette score
CAccuracy score
DCross-entropy loss
Attempts:
2 left
💡 Hint
This metric ranges from -1 to 1 and considers cohesion and separation.
🔧 Debug
expert
2:00remaining
Debugging K-Means Convergence Issue
You run K-Means on a dataset but notice the algorithm does not converge and runs indefinitely. Which is the most likely cause?
AThe random_state parameter is not set
BThe dataset contains only numerical features
CThe number of clusters k is set larger than the number of unique data points
DThe data is normalized before clustering
Attempts:
2 left
💡 Hint
Think about what happens if clusters cannot be assigned uniquely.

Practice

(1/5)
1. What does the n_clusters parameter in K-Means control?
easy
A. The initial random seed for cluster centers
B. The maximum number of iterations for the algorithm
C. The number of groups (clusters) to find in the data
D. The distance metric used to measure similarity

Solution

  1. Step 1: Understand the role of n_clusters

    The n_clusters parameter tells K-Means how many groups to split the data into.
  2. Step 2: Compare with other parameters

    Other parameters control iterations, distance, or randomness, but n_clusters specifically sets group count.
  3. Final Answer:

    The number of groups (clusters) to find in the data -> Option C
  4. Quick Check:

    n_clusters = number of groups [OK]
Hint: Remember: n_clusters means how many groups you want [OK]
Common Mistakes:
  • Confusing n_clusters with max iterations
  • Thinking n_clusters sets distance metric
  • Assuming n_clusters controls randomness
2. Which of the following is the correct way to import KMeans from scikit-learn in Python?
easy
A. from sklearn import KMeans.cluster
B. import KMeans from sklearn.cluster
C. import sklearn.cluster.KMeans
D. from sklearn.cluster import KMeans

Solution

  1. Step 1: Recall Python import syntax

    Python uses 'from module import class' to import specific classes.
  2. Step 2: Match correct syntax for KMeans

    The correct import is from sklearn.cluster import KMeans.
  3. Final Answer:

    from sklearn.cluster import KMeans -> Option D
  4. Quick Check:

    Correct import syntax = from sklearn.cluster import KMeans [OK]
Hint: Use 'from module import class' for importing classes [OK]
Common Mistakes:
  • Using wrong import order
  • Trying to import with 'import' and 'from' combined incorrectly
  • Using dot notation in import statement
3. Given the code below, what will be the output of print(kmeans.labels_)?
from sklearn.cluster import KMeans
import numpy as np

X = np.array([[1, 2], [1, 4], [1, 0], [10, 2], [10, 4], [10, 0]])
kmeans = KMeans(n_clusters=2, random_state=0).fit(X)
print(kmeans.labels_)
medium
A. [0 0 0 1 1 1]
B. [1 1 1 0 0 0]
C. [0 1 0 1 0 1]
D. [1 0 1 0 1 0]

Solution

  1. Step 1: Understand data grouping

    The first three points are close together near (1, y), the last three near (10, y), so KMeans will group first three as one cluster and last three as another.
  2. Step 2: Check label assignment

    KMeans assigns cluster labels starting from 0. The first cluster gets label 0, second cluster label 1. But the cluster near (10, y) is assigned label 0 and near (1, y) label 1 due to initialization and fitting.
  3. Final Answer:

    [1 1 1 0 0 0] -> Option B
  4. Quick Check:

    Close points share label 0 or 1 [OK]
Hint: Clusters group close points; labels start at 0 [OK]
Common Mistakes:
  • Assuming labels start at 1
  • Mixing cluster order
  • Ignoring spatial grouping
4. What is wrong with the following K-Means code snippet?
from sklearn.cluster import KMeans
X = [[1, 2], [1, 4], [1, 0]]
kmeans = KMeans(n_clusters=4)
kmeans.fit(X)
print(kmeans.labels_)
medium
A. The number of clusters (4) is greater than the number of data points (3)
B. The data X should be a numpy array, not a list
C. The KMeans class requires a random_state parameter
D. The fit method should be called with labels, not data

Solution

  1. Step 1: Check cluster count vs data points

    There are only 3 data points but 4 clusters requested, which is invalid because you cannot have more clusters than points.
  2. Step 2: Validate other code parts

    Using a list for X is allowed, random_state is optional, and fit expects data, not labels.
  3. Final Answer:

    The number of clusters (4) is greater than the number of data points (3) -> Option A
  4. Quick Check:

    Clusters ≤ data points [OK]
Hint: Clusters cannot exceed number of data points [OK]
Common Mistakes:
  • Thinking data must be numpy array
  • Believing random_state is mandatory
  • Confusing fit input as labels
5. You have a dataset with 3 natural groups, but you run K-Means with n_clusters=5. What is the likely effect on the clustering result?
hard
A. K-Means will split some natural groups into smaller clusters, causing over-segmentation
B. K-Means will ignore extra clusters and only find 3 groups
C. K-Means will fail to run and throw an error
D. K-Means will merge groups to reduce clusters to 3 automatically

Solution

  1. Step 1: Understand cluster count effect

    Setting more clusters than natural groups causes K-Means to split existing groups into smaller parts.
  2. Step 2: Check K-Means behavior

    K-Means does not reduce cluster count automatically or throw error if clusters exceed natural groups; it always finds exactly n_clusters.
  3. Final Answer:

    K-Means will split some natural groups into smaller clusters, causing over-segmentation -> Option A
  4. Quick Check:

    More clusters than groups = splitting groups [OK]
Hint: More clusters than groups splits groups into smaller parts [OK]
Common Mistakes:
  • Thinking K-Means auto-adjusts cluster count
  • Expecting error when clusters > natural groups
  • Assuming extra clusters are ignored
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