Seaborn is often used alongside Matplotlib. What is the main reason for this?
Think about how Seaborn makes plotting easier and prettier but still uses Matplotlib underneath.
Seaborn builds on Matplotlib by adding easier syntax and nicer default styles, especially for statistical data visualization. Matplotlib remains useful for detailed customization.
What will be the output of this code snippet?
import matplotlib.pyplot as plt import seaborn as sns sns.set_style('darkgrid') plt.plot([1, 2, 3], [4, 5, 6]) plt.title('Simple Line Plot') plt.show()
Seaborn's set_style changes the background style for Matplotlib plots.
Seaborn's set_style('darkgrid') changes the plot background to a dark grid style. The plt.plot creates a line plot. The title is added by plt.title.
After running this code, how many major grid lines will appear on the y-axis?
import matplotlib.pyplot as plt import seaborn as sns sns.set_style('whitegrid') plt.plot([0, 1, 2, 3], [10, 20, 30, 40]) plt.yticks([10, 20, 30, 40]) plt.show()
Seaborn's 'whitegrid' style adds grid lines matching y-ticks.
The 'whitegrid' style adds horizontal grid lines at each y-tick. Since y-ticks are set to 10, 20, 30, 40, there will be 4 grid lines.
What error will this code produce?
import matplotlib.pyplot as plt import seaborn as sns sns.set_style('dark') plt.plot([1, 2, 3], [4, 5, 6]) plt.show()
Verify the list of valid Seaborn styles: 'darkgrid', 'whitegrid', 'dark', 'white', 'ticks'.
'dark' is a valid Seaborn style (one of 'darkgrid', 'whitegrid', 'dark', 'white', 'ticks'), providing a dark background without grid lines. The code runs without error.
You want to create a scatter plot with Seaborn's style and Matplotlib's detailed control. Which code snippet correctly achieves this?
Remember to set Seaborn style before plotting with Matplotlib for style to apply.
Option A sets the Seaborn style first, then uses Matplotlib's scatter with color and grid enabled. This combines Seaborn's style with Matplotlib's control correctly.