This code creates a simple 10x10 gradient image and shows it using the 'viridis' colormap. The colorbar shows how colors map to values.
Matplotlib
import numpy as np
import matplotlib.pyplot as plt
# Create a 2D array with a gradient
image_data = np.linspace(0, 1, 100).reshape(10, 10)
# Show image with 'viridis' colormap
plt.imshow(image_data, cmap='viridis')
plt.colorbar()
plt.title('Image with Viridis Colormap')
plt.show()
OutputSuccess
Important Notes
Colormaps can be sequential, diverging, or qualitative depending on your data.
Use plt.colorbar() to add a color scale next to your image.
Try different colormaps to find the best one for your data story.
Summary
Colormaps change how image data values show as colors.
Use cmap in plt.imshow() to pick a colormap.
Adding a colorbar helps explain the color meaning.
Practice
(1/5)
1. What does the cmap parameter do in plt.imshow() when displaying an image?
easy
A. It changes how numbers map to colors in the image.
B. It changes the image size.
C. It adds a title to the image.
D. It saves the image to a file.
Solution
Step 1: Understand the role of cmap in plt.imshow()
The cmap parameter controls the colormap, which maps numeric values to colors in the image.
Step 2: Identify what cmap affects visually
Changing cmap changes the colors shown, helping interpret data better.
Final Answer:
It changes how numbers map to colors in the image. -> Option A
Quick Check:
Colormap = color mapping [OK]
Hint: Remember: cmap controls colors, not size or titles [OK]
Common Mistakes:
Thinking cmap changes image size
Confusing cmap with adding titles
Assuming cmap saves the image
2. Which of the following is the correct way to apply the 'viridis' colormap to an image using matplotlib?
easy
A. plt.imshow(image, color='viridis')
B. plt.imshow(image, cmap='viridis')
C. plt.imshow(image, cmap=viridis)
D. plt.imshow(image, colormap='viridis')
Solution
Step 1: Recall the correct parameter name for colormap
The parameter to set colormap in plt.imshow() is cmap, and it expects a string name.
Step 2: Check the syntax for passing the colormap
Passing cmap='viridis' is correct. Using color or colormap is incorrect, and omitting quotes causes an error.
Final Answer:
plt.imshow(image, cmap='viridis') -> Option B
Quick Check:
Use cmap='name' syntax [OK]
Hint: Use cmap='colormap_name' exactly [OK]
Common Mistakes:
Using color instead of cmap
Forgetting quotes around colormap name
Using colormap instead of cmap
3. What will the following code display?
import matplotlib.pyplot as plt
import numpy as np
image = np.array([[0, 1], [2, 3]])
plt.imshow(image, cmap='gray')
plt.colorbar()
plt.show()
medium
A. A 2x2 image with shades of gray from black (0) to white (3) and a colorbar showing values 0 to 3.
B. A 2x2 image with random colors and no colorbar.
C. A 2x2 image with rainbow colors and a colorbar showing values 0 to 1.
D. An error because 'gray' is not a valid colormap.
Solution
Step 1: Understand the image data and colormap
The image is a 2x2 array with values 0 to 3. The 'gray' colormap maps low values to black and high values to white.
Step 2: Analyze the colorbar and display
The colorbar shows the numeric range from 0 to 3, matching the image values. The image colors range from black (0) to white (3).
Final Answer:
A 2x2 image with shades of gray from black (0) to white (3) and a colorbar showing values 0 to 3. -> Option A
Quick Check:
Gray cmap maps 0-3 to black-white [OK]
Hint: Gray cmap means black to white shades [OK]
Common Mistakes:
Thinking 'gray' is invalid
Ignoring the colorbar range
Assuming rainbow colors with 'gray'
4. The code below is intended to show an image with the 'hot' colormap and a colorbar, but it raises an error. What is the problem?
import matplotlib.pyplot as plt
import numpy as np
image = np.random.rand(3,3)
plt.imshow(image, cmap=hot)
plt.colorbar()
plt.show()
medium
A. plt.colorbar() must be called before plt.imshow().
B. The image array shape is invalid for imshow.
C. The colormap name 'hot' should be a string: cmap='hot'.
D. np.random.rand() cannot be used for images.
Solution
Step 1: Check the cmap parameter usage
The colormap name must be a string. Here, hot is used without quotes, causing a NameError.
Step 2: Verify other code parts
The image shape is valid, and colorbar usage is correct. np.random.rand() is valid for image data.
Final Answer:
The colormap name 'hot' should be a string: cmap='hot'. -> Option C
Quick Check:
Colormap names need quotes [OK]
Hint: Always put colormap names in quotes [OK]
Common Mistakes:
Forgetting quotes around colormap name
Thinking image shape is wrong
Misordering colorbar and imshow
5. You have a 5x5 numpy array with values from 0 to 24. You want to display it using plt.imshow() with the 'coolwarm' colormap but only show colors for values between 5 and 20. Which code snippet correctly applies this?
hard
A. plt.imshow(data, cmap='coolwarm'); plt.colorbar(vmin=5, vmax=20)
B. plt.imshow(data, cmap='coolwarm', min=5, max=20); plt.colorbar()
C. plt.imshow(data, cmap='coolwarm', clip=(5,20)); plt.colorbar()
D. plt.imshow(data, cmap='coolwarm', vmin=5, vmax=20); plt.colorbar()
Solution
Step 1: Understand how to limit color range in imshow
Use vmin and vmax parameters to set the data range for colormap scaling.
Step 2: Check each option for correct syntax
plt.imshow(data, cmap='coolwarm', vmin=5, vmax=20); plt.colorbar() uses vmin=5 and vmax=20, which is correct. Other options use invalid parameters or place them incorrectly.
Final Answer:
plt.imshow(data, cmap='coolwarm', vmin=5, vmax=20); plt.colorbar() -> Option D
Quick Check:
Use vmin and vmax to clip colors [OK]
Hint: Use vmin and vmax to set color limits [OK]
Common Mistakes:
Using min/max instead of vmin/vmax
Trying to clip with non-existent parameters
Passing vmin/vmax to colorbar instead of imshow
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