Why patterns solve common tasks in Matplotlib - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to import the matplotlib plotting library.

Matplotlib

import [1] as plt

Drag options to blanks, or click blank then click option'

Amatplotlib.pyplot

Bseaborn

Cpandas

Dnumpy

Attempts:

3 left

💡 Hint

Common Mistakes

Importing the wrong library like pandas or numpy.

Forgetting to import pyplot specifically.

We import matplotlib.pyplot as plt to create plots easily.

2fill in blank

medium

Complete the code to create a simple line plot of y versus x.

Matplotlib

plt.[1](x, y)
plt.show()

Drag options to blanks, or click blank then click option'

Aplot

Bscatter

Chist

Dbar

Attempts:

3 left

💡 Hint

Common Mistakes

Using scatter which draws points but no lines.

Using hist which draws histograms.

The plot function draws a line plot connecting points.

3fill in blank

hard

Fix the error in the code to label the x-axis correctly.

Matplotlib

plt.xlabel([1])

Drag options to blanks, or click blank then click option'

Ax_label

B'x label'

Cxlabel

Dx label

Attempts:

3 left

💡 Hint

Common Mistakes

Passing a variable name that is not defined.

Forgetting to put quotes around the label text.

The label text must be a string, so it needs quotes.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps words to their lengths if length is greater than 3.

Matplotlib

{word: [1] for word in words if [2]

Drag options to blanks, or click blank then click option'

Alen(word)

Blen(word) > 3

Cword.startswith('a')

Dword.upper()

Attempts:

3 left

💡 Hint

Common Mistakes

Using the wrong condition in the if clause.

Mapping to the word itself instead of its length.

The dictionary maps each word to its length, but only if the length is greater than 3.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase words to their counts if count is greater than 1.

Matplotlib

{ [1]: [2] for [3], [2] in word_counts.items() if [2] > 1 }

Drag options to blanks, or click blank then click option'

Aword.upper()

Bcount

Cword

Dword_counts

Attempts:

3 left

💡 Hint

Common Mistakes

Using the wrong variable names in the loop.

Not converting the word to uppercase for the key.

The comprehension maps each word in uppercase to its count, but only if the count is more than 1.