Seaborn style with Matplotlib - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is the purpose of using Seaborn style with Matplotlib?

Using Seaborn style with Matplotlib improves the visual appeal of plots by applying clean, modern, and easy-to-read design elements, making charts more attractive and easier to understand.

beginner

How do you apply Seaborn style to Matplotlib plots in Python?

You can apply Seaborn style by importing Seaborn and calling seaborn.set() before creating Matplotlib plots. This sets the style globally for all plots.

intermediate

Which Seaborn styles can you use with Matplotlib?

Seaborn offers several styles like darkgrid, whitegrid, dark, white, and ticks. You can set them using seaborn.set_style('style_name').

intermediate

What is the difference between seaborn.set() and seaborn.set_style()?

seaborn.set() applies default Seaborn style and color palette together, while seaborn.set_style() only changes the background and grid style without affecting colors.

beginner

How can you revert back to Matplotlib's default style after using Seaborn style?

You can revert by calling matplotlib.style.use('default') or restarting your Python session to remove Seaborn styling effects.

Which function applies the default Seaborn style and color palette to Matplotlib plots?

A seaborn.set()

B seaborn.set_style()

C matplotlib.style.use('seaborn')

D matplotlib.pyplot.style()

seaborn.set() applies both style and color palette, making plots look like Seaborn's default style.

How do you set the 'whitegrid' style using Seaborn for Matplotlib plots?

A matplotlib.style.use('whitegrid')

B seaborn.set_style('whitegrid')

C seaborn.set_palette('whitegrid')

D matplotlib.pyplot.style('whitegrid')

seaborn.set_style('whitegrid') changes the background and grid style to white grid.

What happens if you call seaborn.set() multiple times before plotting?

A It causes an error

B It applies random styles

C It disables styling

D It resets the style and palette each time to Seaborn defaults

Calling seaborn.set() multiple times resets the style and palette to Seaborn defaults each time.

Which Seaborn style removes grid lines and uses a plain white background?

A darkgrid

B dark

C white

D ticks

The white style removes grid lines and uses a clean white background.

How can you combine Seaborn style with Matplotlib to customize plot colors separately?

A Use seaborn.set_style() and seaborn.set_palette() separately

B Use only matplotlib without seaborn

C Use seaborn.set() and then matplotlib color settings

D Use matplotlib.style.use('seaborn') only

You can set background style with seaborn.set_style() and colors with seaborn.set_palette() for more control.

Explain how to apply Seaborn styles to Matplotlib plots and why it is useful.

Think about how Seaborn changes the look of charts.

Describe the difference between seaborn.set() and seaborn.set_style() and when you might use each.

Consider what changes color palettes vs background style.

Practice

1. What does using plt.style.use('seaborn') do in Matplotlib?

easy

A. It resets all plot settings to Matplotlib defaults.

B. It changes the plot style to look like Seaborn's default theme.

C. It imports the Seaborn library for plotting.

D. It saves the current plot as a Seaborn file.

Solution

1. Step 1: Understand plt.style.use function

   This function sets the style for all plots that follow.

2. Step 2: Recognize 'seaborn' style effect

   Using 'seaborn' applies Seaborn's visual theme to Matplotlib plots.

3. Final Answer:

   It changes the plot style to look like Seaborn's default theme. -> Option B

4. Quick Check:

   Seaborn style = changes plot look [OK]

Hint: Remember: plt.style.use sets the plot's visual theme [OK]

Common Mistakes:

• Thinking it imports Seaborn library
• Confusing style setting with saving files
• Assuming it resets to default Matplotlib style

2. Which of the following is the correct way to apply the Seaborn style in Matplotlib?

easy

A. style.use.plt('seaborn')

B. plt.style('seaborn')

C. plt.use.style('seaborn')

D. plt.style.use('seaborn')

Solution

1. Step 1: Recall the correct syntax for style setting

   The correct method is plt.style.use with the style name as a string.

2. Step 2: Check each option's syntax

   Only plt.style.use('seaborn') matches the correct syntax: plt.style.use('seaborn').

3. Final Answer:

   plt.style.use('seaborn') -> Option D

4. Quick Check:

   Correct syntax = plt.style.use('seaborn') [OK]

Hint: Use plt.style.use('style_name') to set plot style [OK]

Common Mistakes:

• Using plt.style('seaborn') without .use
• Mixing order of style and use
• Incorrect method names or argument order

3. What will be the output style of the plot after running this code?

import matplotlib.pyplot as plt
plt.style.use('seaborn-darkgrid')
plt.plot([1, 2, 3], [4, 5, 6])
plt.show()

medium

A. A plot with a white background and grid lines.

B. A plot with a white background and no grid lines.

C. A plot with default Matplotlib style and no grid.

D. A plot with bright colors but no grid lines.

Solution

1. Step 1: Understand 'seaborn-darkgrid' style

   This style applies a white background with visible grid lines.

2. Step 2: Analyze the plot appearance

   Since plt.style.use('seaborn-darkgrid') is set, the plot will have a white background and grid lines.

3. Final Answer:

   A plot with a white background and grid lines. -> Option A

4. Quick Check:

   seaborn-darkgrid = white background + grid [OK]

Hint: Remember 'darkgrid' means white background with grids [OK]

Common Mistakes:

• Assuming no grid lines appear
• Confusing darkgrid with dark background styles
• Expecting default Matplotlib style

4. Identify the error in this code snippet that tries to apply Seaborn style:

import matplotlib.pyplot as plt
plt.style.use(seaborn)
plt.plot([1, 2, 3], [3, 2, 1])
plt.show()

medium

A. plt.show() is missing parentheses.

B. plt.style.use cannot be used before plt.plot.

C. Missing quotes around 'seaborn' in plt.style.use.

D. plt.plot requires two lists of equal length.

Solution

1. Step 1: Check the argument passed to plt.style.use

   The style name must be a string, so it needs quotes around 'seaborn'.

2. Step 2: Verify other parts of the code

   plt.plot has correct lists, plt.show() has parentheses, and style can be set before plotting.

3. Final Answer:

   Missing quotes around 'seaborn' in plt.style.use. -> Option C

4. Quick Check:

   Style name must be a string [OK]

Hint: Always put style names in quotes in plt.style.use [OK]

Common Mistakes:

• Forgetting quotes around style name
• Thinking plt.show() needs no parentheses
• Believing style must be set after plotting

5. You want to create a Matplotlib plot with Seaborn's 'whitegrid' style but only for one plot without affecting others. Which code snippet achieves this?

hard

A. with plt.style.context('seaborn-whitegrid'):
plt.plot(x, y)
plt.show()

B. plt.style.use('seaborn-whitegrid')
plt.plot(x, y)

C. plt.style.context('seaborn-whitegrid')
plt.plot(x, y)
plt.show()

D. plt.style.use('seaborn-whitegrid')
plt.plot(x, y)
plt.style.reset()

Solution

1. Step 1: Understand style context usage

   Using plt.style.context applies a style temporarily within the with block.

2. Step 2: Check each option for temporary style application

   with plt.style.context('seaborn-whitegrid'): plt.plot(x, y) plt.show() uses with plt.style.context('seaborn-whitegrid') to apply style only to that plot.

3. Final Answer:

   with plt.style.context('seaborn-whitegrid'): plt.plot(x, y) plt.show() -> Option A

4. Quick Check:

   Use plt.style.context for temporary style [OK]

Hint: Use with plt.style.context for one-time style [OK]

Common Mistakes:

• Using plt.style.use without resetting style
• Calling plt.style.context without with statement
• Assuming plt.style.reset() exists