Custom colormaps in Matplotlib - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is a colormap in matplotlib?

A colormap is a set of colors used to map data values to colors in a plot, helping to visualize data intensity or categories.

beginner

How do you create a simple custom colormap using matplotlib?

You can create a custom colormap by using matplotlib.colors.LinearSegmentedColormap.from_list() with a list of colors you want to blend.

intermediate

What is the purpose of the from_list() method in colormaps?

It creates a colormap by blending a list of colors smoothly from start to end, allowing custom color gradients.

beginner

How can you apply a custom colormap to a heatmap in matplotlib?

Pass the custom colormap object to the cmap parameter in plotting functions like imshow() or pcolormesh().

intermediate

Why might you want to create a custom colormap instead of using built-in ones?

Custom colormaps let you choose colors that better match your data story, improve accessibility, or highlight specific data ranges.

Which matplotlib function is used to create a custom colormap from a list of colors?

A LinearSegmentedColormap.from_list()

B plt.custom_cmap()

C colors.create_map()

D colormap.new()

The correct function is LinearSegmentedColormap.from_list() to create a colormap from a list of colors.

What parameter do you use to apply a colormap to a matplotlib heatmap?

A color_map

B colormap

C color_scheme

D cmap

The parameter to apply a colormap is 'cmap' in matplotlib plotting functions.

What does a colormap do in data visualization?

A Maps data values to colors

B Changes plot size

C Adjusts font style

D Sorts data points

Colormaps map data values to colors to help visualize data intensity or categories.

Which of these is NOT a reason to create a custom colormap?

A To improve accessibility

B To change plot title font

C To highlight specific data ranges

D To better match data story colors

Changing plot title font is unrelated to colormaps.

What type of object does from_list() return?

A A plot figure

B A list of colors

C A colormap object

D A color palette

from_list() returns a colormap object that can be used in plotting.

Explain how to create and use a custom colormap in matplotlib.

Think about making a color gradient and applying it to a heatmap.

Why might custom colormaps be important in data visualization?

Consider how colors affect understanding and clarity.

Practice

1. What is the main purpose of creating a custom colormap in matplotlib?

easy

A. To speed up the plotting process

B. To automatically label axes

C. To choose colors that better represent your data and improve chart clarity

D. To change the plot size

Solution

1. Step 1: Understand what colormaps do

   Colormaps assign colors to data values in a plot to help visualize differences.

2. Step 2: Identify the benefit of custom colormaps

   Custom colormaps let you pick colors that fit your data and style, making charts clearer and more attractive.

3. Final Answer:

   To choose colors that better represent your data and improve chart clarity -> Option C

4. Quick Check:

   Custom colormaps improve data visualization clarity = B [OK]

Hint: Custom colormaps improve how data colors show up [OK]

Common Mistakes:

• Thinking colormaps speed up plotting
• Confusing colormaps with axis labels
• Assuming colormaps change plot size

2. Which of the following is the correct way to create a custom colormap from a list of colors in matplotlib?

easy

A. LinearSegmentedColormap.from_list('mycmap', ['red', 'green', 'blue'])

B. plt.colormap(['red', 'green', 'blue'])

C. color_map(['red', 'green', 'blue'])

D. create_colormap(['red', 'green', 'blue'])

Solution

1. Step 1: Recall the correct function for custom colormaps

   Matplotlib uses LinearSegmentedColormap.from_list to create colormaps from color lists.

2. Step 2: Check the syntax

   The correct syntax is LinearSegmentedColormap.from_list('mycmap', ['red', 'green', 'blue']). Other options are not valid matplotlib functions.

3. Final Answer:

   LinearSegmentedColormap.from_list('mycmap', ['red', 'green', 'blue']) -> Option A

4. Quick Check:

   Use LinearSegmentedColormap.from_list for custom colormaps = A [OK]

Hint: Use LinearSegmentedColormap.from_list with color list [OK]

Common Mistakes:

• Using plt.colormap which does not exist
• Trying to call create_colormap which is not a function
• Confusing function names

3. What will be the output of this code snippet?

import matplotlib.pyplot as plt
from matplotlib.colors import LinearSegmentedColormap

colors = ['yellow', (1, 0.5, 0), 'red']
my_cmap = LinearSegmentedColormap.from_list('mycmap', colors)
print(my_cmap(0.5))

medium

A. Error: Invalid colormap

B. (0.5, 0.5, 0.5, 1.0)

C. (1.0, 0.0, 0.0, 1.0)

D. (1.0, 0.5, 0.0, 1.0)

Solution

1. Step 1: Understand colormap interpolation

   The colormap is created from yellow, (1, 0.5, 0), and red. At 0.5 (middle), it should be the middle anchor color (1.0, 0.5, 0.0).

2. Step 2: Check RGBA values for the middle color

   The middle color exactly corresponds to (1.0, 0.5, 0.0, 1.0) in RGBA format, which matches the output.

3. Final Answer:

   (1.0, 0.5, 0.0, 1.0) -> Option D

4. Quick Check:

   Middle color in colormap = orange RGBA = A [OK]

Hint: Middle of colormap returns middle color RGBA [OK]

Common Mistakes:

• Assuming 0.5 returns gray
• Confusing color order
• Expecting an error from valid code

4. Identify the error in this code that tries to create a custom colormap:

from matplotlib.colors import LinearSegmentedColormap
colors = ['blue', 'white', 'green']
my_cmap = LinearSegmentedColormap(colors)

medium

A. LinearSegmentedColormap requires 'from_list' method to create from colors

B. Colors list must be strings of hex codes only

C. You must import pyplot to create colormaps

D. The colors list cannot have more than two colors

Solution

1. Step 1: Check how to create colormaps from colors

   LinearSegmentedColormap is a class and cannot be called directly with a list. Instead, use the class method from_list.

2. Step 2: Identify the correct usage

   The correct way is LinearSegmentedColormap.from_list('name', colors). The code misses from_list.

3. Final Answer:

   LinearSegmentedColormap requires 'from_list' method to create from colors -> Option A

4. Quick Check:

   Use from_list to create colormap from colors = D [OK]

Hint: Use from_list method to create colormap from colors [OK]

Common Mistakes:

• Calling LinearSegmentedColormap directly
• Thinking colors must be hex codes
• Importing pyplot unnecessarily

5. You want to create a custom colormap that smoothly transitions from blue to white to red, but with the white color occupying the middle 40% of the range. Which approach correctly achieves this?

hard

A. Use LinearSegmentedColormap.from_list('bwr', ['blue', 'white', 'red'])

B. Use LinearSegmentedColormap.from_list('bwr', ['blue', 'white', 'white', 'red'], [0, 0.3, 0.7, 1])

C. Use LinearSegmentedColormap.from_list('bwr', ['blue', 'white', 'red'], [0, 0.5, 1])

D. Use LinearSegmentedColormap.from_list('bwr', ['blue', 'red']) and set midpoint to white separately

Solution

1. Step 1: Understand color position control in colormaps

   To make white occupy the middle 40%, you need to specify positions for colors explicitly.

2. Step 2: Analyze the options

   Use LinearSegmentedColormap.from_list('bwr', ['blue', 'white', 'white', 'red'], [0, 0.3, 0.7, 1]) uses four colors with positions [0, 0.3, 0.7, 1], placing white twice to stretch it over 40% (from 0.3 to 0.7). This creates a smooth transition with white in the middle range.

3. Final Answer:

   Use LinearSegmentedColormap.from_list('bwr', ['blue', 'white', 'white', 'red'], [0, 0.3, 0.7, 1]) -> Option B

4. Quick Check:

   Specify color positions to stretch middle color = C [OK]

Hint: Repeat middle color with positions to stretch it [OK]

Common Mistakes:

• Not specifying positions, so white is evenly spread
• Using only three colors without position list
• Trying to set midpoint color separately