Bar width and positioning in Matplotlib - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to set the width of the bars to 0.5.

Matplotlib

import matplotlib.pyplot as plt

x = [1, 2, 3]
heights = [4, 5, 6]
plt.bar(x, heights, width=[1])
plt.show()

Drag options to blanks, or click blank then click option'

A0

B1.5

C2

D0.5

Attempts:

3 left

💡 Hint

Common Mistakes

Using width greater than 1 makes bars overlap.

Setting width to 0 makes bars invisible.

The width parameter controls the thickness of the bars. Setting it to 0.5 makes the bars half as wide as the default.

2fill in blank

medium

Complete the code to position bars at x-coordinates shifted by 0.3 to the right.

Matplotlib

import matplotlib.pyplot as plt

x = [1, 2, 3]
heights = [4, 5, 6]
plt.bar([i + [1] for i in x], heights, width=0.5)
plt.show()

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A0.3

B0.1

C-0.3

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Using negative values shifts bars left instead of right.

Using 1 shifts bars too far.

Adding 0.3 shifts the bars to the right by 0.3 units on the x-axis.

3fill in blank

hard

Fix the error in the code to correctly position two sets of bars side by side.

Matplotlib

import matplotlib.pyplot as plt

x = [1, 2, 3]
heights1 = [4, 5, 6]
heights2 = [3, 4, 5]
width = 0.4
plt.bar(x, heights1, width=width, label='A')
plt.bar([i [1] width for i in x], heights2, width=width, label='B')
plt.legend()
plt.show()

Drag options to blanks, or click blank then click option'

A*

B-

C+

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using subtraction shifts bars left, overlapping the first set.

Using multiplication or division causes errors or wrong positions.

Adding width shifts the second set of bars to the right, placing them side by side.

4fill in blank

hard

Fill both blanks to create a dictionary of word lengths for words longer than 3 characters.

Matplotlib

words = ['apple', 'bat', 'carrot', 'dog']
lengths = {word: [1] for word in words if len(word) [2] 3}

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Alen(word)

B>

C<

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using < instead of > filters the wrong words.

Using the word itself instead of its length as the value.

The dictionary comprehension maps each word to its length only if the word length is greater than 3.

5fill in blank

hard

Fill all three blanks to create a dictionary of uppercase words mapped to their lengths if length is greater than 3.

Matplotlib

words = ['apple', 'bat', 'carrot', 'dog']
result = { [1]: [2] for word in words if len(word) [3] 3 }

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Aword.upper()

Blen(word)

C>

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using the original word instead of uppercase as key.

Using < instead of > in the condition.

This dictionary comprehension creates keys as uppercase words and values as their lengths, only for words longer than 3 characters.