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MATLABdata~10 mins

Why statistical tools drive decisions in MATLAB - Test Your Understanding

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to calculate the mean of the data array.

MATLAB
data = [5, 10, 15, 20, 25];
meanValue = [1](data);
Drag options to blanks, or click blank then click option'
Asum
Bmedian
Cmean
Dmode
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'sum' instead of 'mean' will give the total, not the average.
Using 'median' or 'mode' calculates different statistical measures.
2fill in blank
medium

Complete the code to calculate the standard deviation of the data array.

MATLAB
data = [5, 10, 15, 20, 25];
stdDev = [1](data);
Drag options to blanks, or click blank then click option'
Astd
Bvar
Cmean
Dsum
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'var' calculates variance, not standard deviation.
Using 'mean' or 'sum' does not measure spread.
3fill in blank
hard

Fix the error in the code to calculate the median of the data array.

MATLAB
data = [5, 10, 15, 20, 25];
medianValue = [1](data);
Drag options to blanks, or click blank then click option'
Amean
Bmedian
Cmed
Dmode
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'med' instead of 'median' causes a function not found error.
Using 'mean' calculates average, not median.
4fill in blank
hard

Fill both blanks to create a dictionary (struct) of word lengths for words longer than 3 characters.

MATLAB
words = {'data', 'is', 'fun', 'and', 'useful'};
lengths = struct();
for i = 1:length(words)
    word = words{i};
    if length(word) [1] 3
        lengths.([2]) = length(word);
    end
end
Drag options to blanks, or click blank then click option'
A>
B<
Cword
Dlength
Attempts:
3 left
💡 Hint
Common Mistakes
Using '<' instead of '>' will select shorter words.
Using 'length' as a field name causes errors because it's a function.
5fill in blank
hard

Fill all three blanks to create a struct of word lengths for words with length greater than 3.

MATLAB
words = {'apple', 'cat', 'banana', 'dog'};
lengths = struct();
for i = 1:length(words)
    word = words{i};
    if length(word) [1] 3
        lengths.([2]) = [3](word);
    end
end
Drag options to blanks, or click blank then click option'
A>
Bword
Clength
Dnumel
Attempts:
3 left
💡 Hint
Common Mistakes
Using '<' instead of '>' in the condition.
Using 'numel' instead of 'length' for strings may work but is less common.
Using a wrong field name causes errors.

Practice

(1/5)
1. Why do we use statistical tools like mean and std in MATLAB when making decisions?
easy
A. To make the code run faster
B. To change the data values randomly
C. To understand data patterns and make informed decisions
D. To create graphics only

Solution

  1. Step 1: Understand the purpose of statistical tools

    Statistical tools like mean and standard deviation help summarize data and show patterns.
  2. Step 2: Connect tools to decision making

    By understanding data patterns, we can make better, informed decisions rather than guessing.
  3. Final Answer:

    To understand data patterns and make informed decisions -> Option C
  4. Quick Check:

    Statistical tools guide decisions = B [OK]
Hint: Statistical tools summarize data to guide decisions [OK]
Common Mistakes:
  • Thinking statistical tools speed up code
  • Believing they randomly change data
  • Assuming they only create graphics
2. Which MATLAB command correctly calculates the average of the vector A = [4, 8, 12]?
easy
A. average(A)
B. mean(A)
C. sum(A)
D. std(A)

Solution

  1. Step 1: Identify the function for average in MATLAB

    The function mean() calculates the average of numbers in a vector.
  2. Step 2: Check other options

    average() is not a MATLAB function, sum() adds values, and std() calculates standard deviation.
  3. Final Answer:

    mean(A) -> Option B
  4. Quick Check:

    Average = mean() [OK]
Hint: Use mean() to find average in MATLAB [OK]
Common Mistakes:
  • Using average() which is not a MATLAB function
  • Confusing sum() with average
  • Using std() instead of mean()
3. What is the output of this MATLAB code?
A = [2, 4, 6, 8];
m = mean(A);
s = std(A);
disp([m, s]);
medium
A. [5 2.58199]
B. [4 2]
C. [6 3]
D. [5 3]

Solution

  1. Step 1: Calculate the mean of A

    Mean = (2 + 4 + 6 + 8) / 4 = 20 / 4 = 5.
  2. Step 2: Calculate the standard deviation of A

    Standard deviation ≈ 2.58199 for these values.
  3. Final Answer:

    [5 2.58199] -> Option A
  4. Quick Check:

    mean = 5, std ≈ 2.58 [OK]
Hint: Calculate mean and std separately, then display [OK]
Common Mistakes:
  • Mixing up mean and std values
  • Calculating sum instead of mean
  • Using wrong formula for std
4. Find the error in this MATLAB code that tries to calculate the mean of B = [1, 3, 5, 7]:
B = [1, 3, 5, 7];
average = mean(B);
disp(average);
medium
A. mean() function is not defined in MATLAB
B. Missing semicolon after mean(B)
C. disp() cannot display variables
D. Variable name 'average' overwrites a function

Solution

  1. Step 1: Check variable naming

    Using 'average' as a variable name is allowed but can confuse readers since it looks like a function name.
  2. Step 2: Confirm syntax correctness

    There is no syntax error; semicolon is optional for suppressing output, mean() is a valid function, and disp() can display variables.
  3. Final Answer:

    Variable name 'average' overwrites a function -> Option D
  4. Quick Check:

    Variable name shadows function = C [OK]
Hint: Avoid naming variables same as functions [OK]
Common Mistakes:
  • Thinking semicolon is mandatory
  • Believing mean() is undefined
  • Assuming disp() can't show variables
5. You have two data sets in MATLAB:
data1 = [10, 20, 30, 40];
data2 = [15, 25, 35, 45];

Which statistical tool helps decide if the difference between these sets is significant for decision making?
hard
A. t-test
B. std
C. sum
D. mean

Solution

  1. Step 1: Understand the goal

    We want to check if the difference between two data sets is statistically significant.
  2. Step 2: Identify the correct statistical test

    Mean and std show averages and spread but do not test significance. The t-test compares means to check significance.
  3. Final Answer:

    t-test -> Option A
  4. Quick Check:

    Significance test = t-test [OK]
Hint: Use t-test to compare two data sets statistically [OK]
Common Mistakes:
  • Using mean or std to test significance
  • Confusing sum with statistical tests
  • Ignoring the need for a significance test
Recommended

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10 questions~5 mineasy hard