We resize and crop images to change their size or focus on important parts. This helps in saving space or highlighting details.
Image resizing and cropping in MATLAB
resizedImage = imresize(originalImage, scale); croppedImage = imcrop(originalImage, rect);
imresize changes the image size by a scale factor or to a specific size.
imcrop cuts out a rectangular part of the image defined by rect = [x y width height].
smallImage = imresize(img, 0.5);bigImage = imresize(img, [200 300]);
cropped = imcrop(img, [50 50 100 100]);
This code loads a sample image, resizes it to 30% of original size, and crops a 150x150 area starting at (100,50). It then shows all three images side by side.
img = imread('peppers.png'); smallImg = imresize(img, 0.3); croppedImg = imcrop(img, [100 50 150 150]); figure; subplot(1,3,1); imshow(img); title('Original Image'); subplot(1,3,2); imshow(smallImg); title('Resized Image (30%)'); subplot(1,3,3); imshow(croppedImg); title('Cropped Image');
Use imresize with care to keep image quality; very large scaling can blur the image.
Coordinates in imcrop start at the top-left corner of the image.
You can also crop interactively by calling imcrop(img) without arguments.
Resize changes image size by scale or exact dimensions.
Crop cuts out a rectangular part of the image.
These help prepare images for storage, display, or analysis.
Practice
imresize function do in MATLAB when working with images?Solution
Step 1: Understand the purpose of
Theimresizeimresizefunction is used to change the size of an image either by scaling it up or down or by specifying exact new dimensions.Step 2: Differentiate from cropping
Unlike cropping, which extracts a part of the image, resizing changes the entire image size.Final Answer:
Changes the size of an image by scaling or specifying new dimensions -> Option CQuick Check:
imresize = Resize image size [OK]
- Confusing resize with crop
- Thinking resize changes image colors
- Assuming resize rotates image
img to a rectangle starting at (50, 30) with width 100 and height 80 in MATLAB?Solution
Step 1: Recall
Theimcropsyntaximcropfunction takes the image and a rectangle vector [x y width height]. Here, x=50, y=30, width=100, height=80.Step 2: Check option correctness
cropped = imcrop(img, [50 30 100 80]); matches the correct syntax. cropped = imresize(img, [50 30 100 80]); usesimresizewhich is wrong. cropped = crop(img, 50, 30, 100, 80); uses a non-existent function. cropped = imcrop(img, [30 50 80 100]); swaps x and y and width and height incorrectly.Final Answer:
cropped = imcrop(img, [50 30 100 80]); -> Option AQuick Check:
imcrop(img, [x y width height]) = correct crop syntax [OK]
- Swapping x and y coordinates
- Using imresize instead of imcrop
- Incorrect rectangle vector order
resized_img after running the following MATLAB code?img = imread('peppers.png');
resized_img = imresize(img, 0.5);Solution
Step 1: Understand
Usingimresizewith scale factorimresize(img, 0.5)scales the image to 50% of its original size in both width and height.Step 2: Determine output size
The output image will have half the width and half the height of the original image.Final Answer:
Half the width and half the height of the original image -> Option AQuick Check:
imresize with 0.5 scales both dimensions by 0.5 [OK]
- Thinking only width or height changes
- Assuming scale factor doubles size
- Confusing imresize with imcrop
img to a 100x100 square starting at (20, 20):cropped_img = imcrop(img, [20 20 100]);
Solution
Step 1: Check
The rectangle vector must have four values: [x y width height]. Here only three values are given.imcroprectangle vector formatStep 2: Identify missing parameter
The height value is missing, causing a syntax error or unexpected behavior.Final Answer:
The rectangle vector is missing the height value -> Option BQuick Check:
imcrop needs [x y width height] vector [OK]
- Providing only 3 values instead of 4
- Confusing coordinates with size
- Assuming imcrop auto-fills missing values
img to exactly 200x150 pixels and then crop a 100x100 square from the center. Which MATLAB code sequence correctly achieves this?Solution
Step 1: Resize image to 200x150 pixels
Useimresize(img, [150 200])to set width=200 and height=150.Step 2: Crop 100x100 square from center
The center of resized image is at (100, 75). To crop 100x100, start at (50, 25) because 50 = 100 - 100/2 and 25 = 75 - 100/2.Step 3: Verify option correctness
resized = imresize(img, [150 200]); cropped = imcrop(resized, [50 25 100 100]); matches the correct order and coordinates. resized = imresize(img, [200 150]); cropped = imcrop(resized, [50 25 100 100]); swaps width and height. Options C and D crop before resizing, which is not what is asked.Final Answer:
resized = imresize(img, [150 200]); cropped = imcrop(resized, [50 25 100 100]); -> Option DQuick Check:
Resize first, then crop center rectangle [OK]
- Swapping width and height in resize
- Cropping before resizing
- Incorrect crop start coordinates
Ready to prove it?
Pass the test and this pattern moves unknown
