Convolution in MATLAB - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

Output of 1D convolution with simple vectors

What is the output of the following MATLAB code?

x = [1 2 3];
h = [0 1 0.5];
y = conv(x, h);
disp(y);

MATLAB

x = [1 2 3];
h = [0 1 0.5];
y = conv(x, h);
disp(y);

A [1 2.5 4 1.5 0]

B [1 2 3 0 0]

C [0 1 2.5 4 1.5]

D [0 1 2 3 0.5]

💡 Hint

Remember convolution flips the second vector and slides it over the first.

The convolution of x and h results in a vector of length length(x)+length(h)-1 = 5. Calculating stepwise gives [0 1 2.5 4 1.5].

❓ Predict Output

intermediate

Output length of convolution

Given two vectors in MATLAB:

a = ones(1,4);
b = ones(1,3);
c = conv(a,b);
length_c = length(c);
disp(length_c);

What is the output?

MATLAB

a = ones(1,4);
b = ones(1,3);
c = conv(a,b);
length_c = length(c);
disp(length_c);

A 6

B 4

C 12

D 3

💡 Hint

The length of the convolution output is length(a) + length(b) - 1.

The output length is 4 + 3 - 1 = 6.

❓ Predict Output

advanced

2D convolution output matrix

What is the output of this MATLAB code?

A = [1 2; 3 4];
B = [0 1; 1 0];
C = conv2(A, B);
disp(C);

MATLAB

A = [1 2; 3 4];
B = [0 1; 1 0];
C = conv2(A, B);
disp(C);

A [[0 1 2]; [1 5 4]; [3 4 0]]

B [[0 1 2]; [1 5 6]; [3 4 0]]

C [[0 1 2]; [1 5 4]; [3 4 1]]

D [[0 1 2]; [1 5 4]; [3 4 2]]

💡 Hint

Remember conv2 output size is (m+p-1) x (n+q-1) for matrices m x n and p x q.

The convolution result is a 3x3 matrix. Calculating each element gives [[0 1 2]; [1 5 4]; [3 4 0]].

❓ Predict Output

advanced

Effect of convolution with impulse

What is the output of this MATLAB code?

x = [4 5 6];
impulse = [1 0 0];
y = conv(x, impulse);
disp(y);

MATLAB

x = [4 5 6];
impulse = [1 0 0];
y = conv(x, impulse);
disp(y);

A [4 5 6 0]

B [4 5 6]

C [0 4 5 6]

D [4 5 6 0 0]

💡 Hint

Convolution with an impulse shifts and extends the signal.

Convolution length is length(x)+length(impulse)-1 = 3+3-1=5. The output is [4 5 6 0 0].

❓ Predict Output

expert

Convolution with complex vectors output

What is the output of this MATLAB code?

x = [1+1i, 2+2i];
h = [1-1i, 0];
y = conv(x, h);
disp(y);

MATLAB

x = [1+1i, 2+2i];
h = [1-1i, 0];
y = conv(x, h);
disp(y);

A [2.0000 + 2.0000i 2.0000 + 0.0000i 0 + 0i]

B [2.0000 + 0.0000i 4.0000 + 0.0000i 0 + 0i]

C [0 + 0i 2.0000 + 0.0000i 2.0000 + 2.0000i]

D [1.0000 + 0.0000i 2.0000 + 2.0000i 0 + 0i]

💡 Hint

Multiply and sum complex numbers carefully for convolution.

Convolution length is 3. Calculations: y(1) = (1+1i)*(1-1i)=2+0i; y(2) = (1+1i)*0 + (2+2i)*(1-1i) = 4 + 0i; y(3) = (2+2i)*0=0.

Practice

1. What does the MATLAB function conv(x, h) compute?

easy

A. The convolution of vectors x and h

B. The element-wise multiplication of x and h

C. The dot product of x and h

D. The sum of vectors x and h

Solution

1. Step 1: Understand the function purpose

   The conv function in MATLAB is designed to compute the convolution of two vectors.

2. Step 2: Differentiate convolution from other operations

   Convolution combines two signals to produce a third, different from element-wise multiplication, dot product, or sum.

3. Final Answer:

   The convolution of vectors x and h -> Option A

4. Quick Check:

   conv(x, h) = convolution [OK]

Hint: Remember conv() means convolution, not multiplication [OK]

Common Mistakes:

• Confusing convolution with element-wise multiplication
• Thinking conv() sums vectors
• Mixing up dot product with convolution

2. Which of the following is the correct syntax to compute convolution of vectors a and b in MATLAB?

easy

A. conv(a, b)

B. convolve(a, b)

C. a * b

D. conv(a + b)

Solution

1. Step 1: Recall MATLAB convolution syntax

   MATLAB uses the function conv(x, h) to compute convolution of two vectors.

2. Step 2: Check each option

   conv(a, b) matches the correct syntax. convolve(a, b) is not a MATLAB function. a * b is matrix multiplication, not convolution. conv(a + b) has wrong argument format.

3. Final Answer:

   conv(a, b) -> Option A

4. Quick Check:

   Use conv(x, h) syntax [OK]

Hint: Use conv() with two arguments separated by comma [OK]

Common Mistakes:

• Using non-existent function convolve()
• Trying to multiply vectors with * for convolution
• Passing only one argument to conv()

3. What is the length of the output vector when you compute conv([1 2 3], [4 5]) in MATLAB?

medium

A. 6

B. 3

C. 5

D. 4

Solution

1. Step 1: Identify lengths of input vectors

   Vector [1 2 3] has length 3, and [4 5] has length 2.

2. Step 2: Calculate output length of convolution

   Output length = length(x) + length(h) - 1 = 3 + 2 - 1 = 4.

3. Final Answer:

   4 -> Option D

4. Quick Check:

   Output length = 3 + 2 - 1 = 4 [OK]

Hint: Output length = sum of input lengths minus one [OK]

Common Mistakes:

• Assuming output length equals input length
• Adding lengths without subtracting one
• Confusing convolution length with element-wise length

4. Consider the MATLAB code:

a = [1 2]; b = [3 4 5]; c = conv(a b);

What is the error in this code?

medium

A. Vectors a and b have different lengths

B. Missing comma between a and b in conv function

C. conv function does not exist in MATLAB

D. Using square brackets instead of parentheses

Solution

1. Step 1: Check syntax of conv function call

   The function call conv(a b) is missing a comma between the two input vectors.

2. Step 2: Verify other options

   Vectors can have different lengths for convolution. conv() is a valid MATLAB function. Square brackets are used correctly for vector definition, not in function call.

3. Final Answer:

   Missing comma between a and b in conv function -> Option B

4. Quick Check:

   Use comma to separate arguments in conv() [OK]

Hint: Separate arguments with comma inside conv() [OK]

Common Mistakes:

• Omitting comma between function arguments
• Thinking vectors must be same length
• Confusing vector definition brackets with function call syntax

5. You want to convolve two signals x = [1 0 2] and h = [3 4] but only keep the output length equal to the length of x. Which MATLAB command achieves this?

hard

A. conv(x, h, 'full')

B. conv(x, h)

C. conv(x, h, 'same')

D. conv(x, h, 'valid')

Solution

1. Step 1: Understand convolution output length options

   By default, conv(x, h) returns full convolution with length length(x)+length(h)-1.

2. Step 2: Use 'same' option to keep output length equal to x

   Using conv(x, h, 'same') returns the central part of the convolution, matching length of x.

3. Final Answer:

   conv(x, h, 'same') -> Option C

4. Quick Check:

   'same' option keeps output length equal to first input [OK]

Hint: Use 'same' option in conv() to match input length [OK]

Common Mistakes:

• Using default conv() which returns longer output
• Confusing 'valid' and 'same' options
• Expecting conv() to truncate output automatically