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Numerical differentiation in MATLAB - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to calculate the forward difference approximation of the derivative.

MATLAB
h = 0.01;
x = 1;
f = @(x) x^2;
derivative = (f(x + [1]) - f(x)) / [1];
Drag options to blanks, or click blank then click option'
Ax
B0.1
Ch
D0
Attempts:
3 left
💡 Hint
Common Mistakes
Using x instead of h as the step size.
Using zero as the step size, which causes division by zero.
2fill in blank
medium

Complete the code to calculate the central difference approximation of the derivative.

MATLAB
h = 0.01;
x = 2;
f = @(x) sin(x);
derivative = (f(x + [1]) - f(x - [1])) / (2 * h);
Drag options to blanks, or click blank then click option'
A2
B0.1
Cx
Dh
Attempts:
3 left
💡 Hint
Common Mistakes
Using different values for the forward and backward steps.
Using x instead of h for the step size.
3fill in blank
hard

Fix the error in the code to correctly compute the numerical derivative using backward difference.

MATLAB
h = 0.001;
x = 3;
f = @(x) exp(x);
derivative = (f(x) - f(x [1] h)) / h;
Drag options to blanks, or click blank then click option'
A-
B+
C*
D/
Attempts:
3 left
💡 Hint
Common Mistakes
Using plus instead of minus, which changes the formula.
Using multiplication or division operators incorrectly.
4fill in blank
hard

Fill both blanks to create a function that returns the central difference derivative approximation.

MATLAB
function d = central_diff(f, x, [1])
    d = (f(x + [2]) - f(x - h)) / (2 * h);
end
Drag options to blanks, or click blank then click option'
Ah
Bx
C0.01
Df
Attempts:
3 left
💡 Hint
Common Mistakes
Using x or a constant instead of the step size variable.
Using the function name f instead of the step size.
5fill in blank
hard

Fill all three blanks to create a function that computes the forward difference derivative with input validation.

MATLAB
function d = forward_diff([1], [2], [3])
    if h <= 0
        error('Step size must be positive');
    end
    d = (f(x + h) - f(x)) / h;
end
Drag options to blanks, or click blank then click option'
Af
Bx
Ch
Dd
Attempts:
3 left
💡 Hint
Common Mistakes
Mixing the order of inputs.
Using variable names not related to the function inputs.

Practice

(1/5)
1. Which method in numerical differentiation uses points on both sides of the target point to estimate the derivative?
easy
A. Forward difference method
B. Euler's method
C. Backward difference method
D. Central difference method

Solution

  1. Step 1: Understand difference methods

    Forward difference uses the point and the next point; backward difference uses the point and the previous point.
  2. Step 2: Identify method using both sides

    Central difference uses points before and after the target point for better accuracy.
  3. Final Answer:

    Central difference method -> Option D
  4. Quick Check:

    Both sides points = Central difference [OK]
Hint: Central difference uses points on both sides [OK]
Common Mistakes:
  • Confusing forward with central difference
  • Thinking Euler's method is for differentiation
  • Assuming backward difference uses both sides
2. Which of the following MATLAB code snippets correctly computes the forward difference approximation of the derivative of function f at point x with step size h?
easy
A. df = (f(x+h) - f(x)) / h;
B. df = (f(x) - f(x-h)) / h;
C. df = (f(x+h) - f(x-h)) / (2*h);
D. df = (f(x) + f(x+h)) / h;

Solution

  1. Step 1: Recall forward difference formula

    Forward difference formula is (f(x+h) - f(x)) / h.
  2. Step 2: Match code to formula

    df = (f(x+h) - f(x)) / h; matches this formula exactly.
  3. Final Answer:

    df = (f(x+h) - f(x)) / h; -> Option A
  4. Quick Check:

    Forward difference = (f(x+h)-f(x))/h [OK]
Hint: Forward difference subtracts current from next point [OK]
Common Mistakes:
  • Using backward difference formula instead
  • Dividing by 2*h instead of h
  • Adding function values instead of subtracting
3. Consider the MATLAB code:
f = @(x) x^2;
x = 2;
h = 0.01;
df = (f(x+h) - f(x-h)) / (2*h);

What is the value of df approximately?
medium
A. 5.00
B. 2.00
C. 4.00
D. 3.99

Solution

  1. Step 1: Calculate f(x+h) and f(x-h)

    f(2+0.01) = (2.01)^2 = 4.0401; f(2-0.01) = (1.99)^2 = 3.9601.
  2. Step 2: Compute central difference

    df = (4.0401 - 3.9601) / (2*0.01) = 0.08 / 0.02 = 4.00.
  3. Step 3: MATLAB precision

    In MATLAB, df is computed and displayed as 4.0000.
  4. Final Answer:

    4.00 -> Option C
  5. Quick Check:

    Central difference ≈ 4 [OK]
Hint: Central difference approximates slope near x [OK]
Common Mistakes:
  • Using forward difference formula instead
  • Forgetting to divide by 2*h
  • Incorrect function evaluation
4. The following MATLAB code attempts to compute the derivative using forward difference but gives incorrect results:
f = @(x) sin(x);
x = pi/4;
h = 0.001;
df = (f(x) - f(x+h)) / h;

What is the error in this code?
medium
A. Step size h is too large
B. The subtraction order is reversed; should be f(x+h) - f(x)
C. Function handle syntax is incorrect
D. Variable x should be a vector

Solution

  1. Step 1: Recall forward difference formula

    Forward difference is (f(x+h) - f(x)) / h, not (f(x) - f(x+h)) / h.
  2. Step 2: Identify error in code

    The code subtracts f(x+h) from f(x), reversing the order and causing incorrect sign.
  3. Final Answer:

    The subtraction order is reversed; should be f(x+h) - f(x) -> Option B
  4. Quick Check:

    Forward difference = (f(x+h)-f(x))/h [OK]
Hint: Forward difference subtracts future minus current value [OK]
Common Mistakes:
  • Reversing subtraction order
  • Using too large step size without reason
  • Misunderstanding function handle syntax
5. You want to estimate the derivative of f(x) = exp(-x^2) at x = 1 using central difference in MATLAB. Which code snippet correctly implements this with step size h = 0.0001?
hard
A. f = @(x) exp(-x^2); x = 1; h = 0.0001; df = (f(x+h) - f(x-h)) / (2*h);
B. f = @(x) exp(-x^2); x = 1; h = 0.0001; df = (f(x) - f(x-h)) / h;
C. f = @(x) exp(-x^2); x = 1; h = 0.0001; df = (f(x+h) + f(x-h)) / (2*h);
D. f = @(x) exp(-x^2); x = 1; h = 0.0001; df = (f(x+h) - f(x)) / h;

Solution

  1. Step 1: Recall central difference formula

    Central difference formula is (f(x+h) - f(x-h)) / (2*h) for better accuracy.
  2. Step 2: Match code to formula

    f = @(x) exp(-x^2); x = 1; h = 0.0001; df = (f(x+h) - f(x-h)) / (2*h); matches the central difference formula exactly with correct function and step size.
  3. Final Answer:

    f = @(x) exp(-x^2); x = 1; h = 0.0001; df = (f(x+h) - f(x-h)) / (2*h); -> Option A
  4. Quick Check:

    Central difference = (f(x+h)-f(x-h))/(2*h) [OK]
Hint: Central difference uses symmetric points around x [OK]
Common Mistakes:
  • Using forward or backward difference instead
  • Adding function values instead of subtracting
  • Dividing by h instead of 2*h
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