Hint: imagesc + colormap + colorbar shows colored data with scale [OK]
Common Mistakes:
Thinking colorbar needs parentheses to work
Assuming default grayscale without colormap
Confusing colormap effect with plot type
4. Identify the error in this MATLAB code snippet:
surf(peaks);
colormap('hot');
colorbar;
medium
A. There is no error; the code runs correctly.
B. The colorbar function is missing parentheses.
C. The surf function cannot be used with colormap.
D. The colormap name should not be in quotes.
Solution
Step 1: Check colormap syntax
Using colormap('hot') with quotes is valid in MATLAB to specify the colormap by name.
Step 2: Verify colorbar usage and surf compatibility
colorbar without parentheses works in MATLAB as a command. surf works fine with colormap and colorbar.
Final Answer:
There is no error; the code runs correctly. -> Option A
Quick Check:
colormap('name') and colorbar command valid = A [OK]
Hint: Quotes allowed in colormap; colorbar works without () [OK]
Common Mistakes:
Thinking colormap names must be unquoted
Believing colorbar needs parentheses always
Assuming surf can't use colormap
5. You want to create a heatmap of data with values from 0 to 100, using a colormap that smoothly changes from blue to red, and show a colorbar with ticks at 0, 50, and 100 labeled accordingly. Which MATLAB code snippet achieves this?
hard
A. imagesc(data);
colormap(hot);
colorbar('Ticks',[0 50 100],'TickLabels',{'Low','Medium','High'});
imagesc(data);
colormap([0 0 1; 1 0 0]);
colorbar('Ticks',[0 50 100],'TickLabels',{'Low','Medium','High'}); attempts a custom colormap with two colors blue and red, but MATLAB requires more points or interpolation for smooth transition. imagesc(data);
colormap(jet);
cb = colorbar;
cb.Ticks = [0 50 100];
cb.TickLabels = {'Low','Medium','High'}; uses jet, which is a smooth colormap but not strictly blue to red. imagesc(data);
colormap([linspace(0,1,256)', zeros(256,1), linspace(1,0,256)']);
cb = colorbar;
cb.Ticks = [0 0.5 1];
cb.TickLabels = {'Low','Medium','High'}; uses a custom colormap with 256 points smoothly transitioning from blue to red, but the ticks are set incorrectly at [0 0.5 1] which do not match data range 0-100. imagesc(data);
colormap(hot);
colorbar('Ticks',[0 50 100],'TickLabels',{'Low','Medium','High'}); uses hot colormap which is not blue to red.
Step 2: Set colorbar ticks and labels correctly
imagesc(data);
colormap(jet);
cb = colorbar;
cb.Ticks = [0 50 100];
cb.TickLabels = {'Low','Medium','High'}; sets ticks at [0 50 100] matching data range and labels accordingly. imagesc(data);
colormap([0 0 1; 1 0 0]);
colorbar('Ticks',[0 50 100],'TickLabels',{'Low','Medium','High'}); sets ticks and labels but the colormap is only two colors, which may not smoothly interpolate. imagesc(data);
colormap([linspace(0,1,256)', zeros(256,1), linspace(1,0,256)']);
cb = colorbar;
cb.Ticks = [0 0.5 1];
cb.TickLabels = {'Low','Medium','High'}; has incorrect ticks. imagesc(data);
colormap(hot);
colorbar('Ticks',[0 50 100],'TickLabels',{'Low','Medium','High'}); uses wrong colormap.
Step 3: Choose the best option
imagesc(data);
colormap(jet);
cb = colorbar;
cb.Ticks = [0 50 100];
cb.TickLabels = {'Low','Medium','High'}; provides a smooth colormap (jet) and correctly sets ticks and labels on the colorbar matching data range 0-100.