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File path handling in MATLAB - Practice Problems & Coding Challenges

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Challenge - 5 Problems
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File Path Master
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Test your skills under time pressure!
❓ Predict Output
intermediate
2:00remaining
What is the output of this MATLAB code using fullfile?
Consider the following MATLAB code that constructs a file path. What will be the output printed?
MATLAB
folder = 'data';
file = 'results.txt';
filepath = fullfile(folder, file);
disp(filepath);
A'data/results.txt\'
B'data\\results.txt'
C'data\results.txt'
D'data/results.txt'
Attempts:
2 left
💡 Hint
fullfile joins parts of a path using the correct file separator for your system.
❓ Predict Output
intermediate
2:00remaining
What does fileparts return for this path?
Given the MATLAB code below, what are the outputs of [folder, name, ext]?
MATLAB
[folder, name, ext] = fileparts('C:\Users\user\Documents\report.pdf');
fprintf('%s|%s|%s', folder, name, ext);
A'C:/Users/user/Documents|report|pdf'
B'C:\Users\user\Documents|report|.pdf'
C'C:\Users\user\Documents\report|pdf|'
D'C:\Users\user\Documents|report.pdf|'
Attempts:
2 left
💡 Hint
fileparts splits the path into folder, filename without extension, and extension.
🔧 Debug
advanced
2:00remaining
Why does this code fail to create a valid path?
This MATLAB code tries to create a file path but produces an error. What is the cause?
MATLAB
folder = 'C:\Data';
file = 'output.txt';
filepath = [folder '\' file];
disp(filepath);
AThe backslash is not escaped properly, causing an invalid path string.
BThe concatenation operator [] cannot be used for strings in MATLAB.
CThe disp function cannot display file paths with backslashes.
DThe variable 'file' is a reserved keyword and cannot be used.
Attempts:
2 left
💡 Hint
Check how backslashes are used in strings in MATLAB.
❓ Predict Output
advanced
2:00remaining
What is the output of this code using filesep?
What will this MATLAB code display?
MATLAB
folder = 'myfolder';
file = 'data.csv';
filepath = [folder filesep file];
disp(filepath);
A'myfolder\data.csv'
B'myfolder\\data.csv'
C'myfolder/data.csv'
D'myfolderdata.csv'
Attempts:
2 left
💡 Hint
filesep returns the system-specific file separator character.
🧠 Conceptual
expert
2:00remaining
How many parts does fileparts return for a UNC path?
In MATLAB, when using fileparts on a UNC path like \\server\share\folder\file.txt, how many output parts does fileparts return?
AOne part: the full path as a single string
BFour parts: server, share, folder, and file
CTwo parts: path and filename
DThree parts: folder, name, and extension
Attempts:
2 left
💡 Hint
fileparts always returns three outputs regardless of path type.

Practice

(1/5)
1. What does the MATLAB function fullfile do?
easy
A. Joins folder and file names into a full file path safely
B. Splits a full file path into folder, name, and extension
C. Reads the contents of a file
D. Deletes a file from the disk

Solution

  1. Step 1: Understand the purpose of fullfile

    fullfile is used to combine folder and file names into one complete path, handling different operating systems correctly.
  2. Step 2: Compare with other functions

    fileparts splits paths, reading or deleting files are unrelated to fullfile.
  3. Final Answer:

    Joins folder and file names into a full file path safely -> Option A
  4. Quick Check:

    fullfile joins paths [OK]
Hint: Remember: fullfile combines parts into one path [OK]
Common Mistakes:
  • Confusing fullfile with fileparts
  • Thinking fullfile reads or deletes files
  • Assuming fullfile only works on Windows
2. Which of the following is the correct syntax to split a full file path into folder, name, and extension in MATLAB?
easy
A. [folder, name, ext] = fileparts(path);
B. [folder, name, ext] = splitfile(path);
C. split(path, folder, name, ext);
D. fileparts = [folder, name, ext](path);

Solution

  1. Step 1: Recall the correct function name and syntax

    The MATLAB function to split a path is fileparts, and it returns folder, name, and extension as outputs.
  2. Step 2: Check the syntax format

    The correct syntax uses square brackets for multiple outputs: [folder, name, ext] = fileparts(path);
  3. Final Answer:

    [folder, name, ext] = fileparts(path); -> Option A
  4. Quick Check:

    fileparts splits path correctly [OK]
Hint: Use square brackets and fileparts to split paths [OK]
Common Mistakes:
  • Using wrong function name like splitfile
  • Incorrect output assignment syntax
  • Trying to call fileparts like a variable
3. What is the output of the following MATLAB code?
fullPath = fullfile('C:', 'Users', 'Documents', 'file.txt');
[folder, name, ext] = fileparts(fullPath);
disp(folder)
medium
A. file.txt
B. C:\Users\Documents
C. C:/Users/Documents/file.txt
D. Documents

Solution

  1. Step 1: Understand fullfile output

    fullfile joins parts into a full path: 'C:\Users\Documents\file.txt' (Windows style).
  2. Step 2: Use fileparts to split the path

    fileparts splits into folder = 'C:\Users\Documents', name = 'file', ext = '.txt'.
  3. Final Answer:

    C:\Users\Documents -> Option B
  4. Quick Check:

    fileparts folder output = C:\Users\Documents [OK]
Hint: fileparts(folder) excludes file name and extension [OK]
Common Mistakes:
  • Expecting file name or extension as folder output
  • Confusing path separators (\ vs /)
  • Thinking fullfile returns a list instead of string
4. Identify the error in this MATLAB code snippet:
path = fullfile('folder', 'subfolder', 'file.txt');
[folder, name, ext] = fileparts(path);
disp(name)
medium
A. The fullfile function cannot join more than two parts
B. The function fileparts requires three output variables, not one
C. There is no error; the code runs correctly and displays 'file'
D. Variable path is a reserved word and should not be used

Solution

  1. Step 1: Check variable naming

    Although path is a common variable name, it is not reserved in MATLAB and can be used safely.
  2. Step 2: Verify function usage

    fileparts can return multiple outputs, but it also works correctly with three outputs as shown. fullfile can join multiple parts, more than two.
  3. Final Answer:

    There is no error; the code runs correctly and displays 'file' -> Option C
  4. Quick Check:

    Code runs and shows file name [OK]
Hint: Check if code runs before assuming errors [OK]
Common Mistakes:
  • Thinking path is a reserved keyword
  • Believing fullfile only joins two parts
  • Assuming fileparts needs different syntax
5. You want to create a MATLAB script that saves a file named data.csv inside a folder results located in the current working directory. Which code snippet correctly creates the full path to save the file, regardless of the operating system?
hard
A. savePath = ['results' filesep 'data.csv'];
B. savePath = strcat('results\', 'data.csv');
C. savePath = 'results/data.csv';
D. savePath = fullfile(pwd, 'results', 'data.csv');

Solution

  1. Step 1: Understand the need for OS-independent path

    Using fullfile with pwd (current folder) ensures the path works on Windows, Mac, or Linux.
  2. Step 2: Analyze each option

    savePath = ['results' filesep 'data.csv']; uses filesep but misses pwd so path is relative; savePath = 'results/data.csv'; uses forward slash which may fail on Windows; savePath = strcat('results\', 'data.csv'); uses backslash manually which is error-prone.
  3. Final Answer:

    savePath = fullfile(pwd, 'results', 'data.csv'); -> Option D
  4. Quick Check:

    fullfile + pwd = OS-independent full path [OK]
Hint: Use fullfile with pwd for safe full paths [OK]
Common Mistakes:
  • Hardcoding slashes instead of using fullfile
  • Not including current directory with pwd
  • Using strcat which ignores path separators
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