C after running it?C = {1, 'text', [2 3 4]; true, {5,6}, pi};
disp(C);The code creates a 2-by-3 cell array. Each cell can hold different data types. For example, C{1,2} holds the string 'text', and C{2,3} holds the value of pi.
C after executing this code?C = cell(3,2);
C = cell(3,2); sizeC = size(C);
The cell(3,2) command creates a cell array with 3 rows and 2 columns, so its size is [3 2].
C = {1, 2, 3; 4, 5};C = {1, 2, 3; 4, 5};The first row has 3 elements, but the second row has only 2. MATLAB requires all rows to have the same number of elements when creating arrays, so it throws a dimension mismatch error.
C where the second element is itself a cell array containing numbers 10 and 20. Which code does this correctly?Option C creates a 1x3 cell array where the second element is a 1x2 cell array containing 10 and 20. Option C uses a numeric array, not a cell. Option C creates a 3x1 cell array (column), not 1x3. Option C creates a nested cell with a column cell array inside, which is valid but changes the shape.
C = {1, {2, 3}, 4};, what is the output of disp(C{2}{1})?C = {1, {2, 3}, 4};
disp(C{2}{1});C{2} accesses the second cell content, which is itself a cell array, then {1} accesses its first element.C{2} is the cell array {2, 3}. Then C{2}{1} accesses the first element inside that nested cell, which is the number 2.