[Solved] Which of the following code snippets correctly represents the en passant capture condition check? - Ans: if pawn.position == opponent_pawn.position + (0, 1) and... | LLD

LLD - Design — Chess Game

Which of the following code snippets correctly represents the en passant capture condition check?

Aif pawn.position == opponent_pawn.position - (0, 2) and opponent_pawn.just_moved_one_step:

Bif pawn.position == opponent_pawn.position + (1, 0) and opponent_pawn.just_moved_two_steps:

Cif pawn.position == opponent_pawn.position + (0, 1) and opponent_pawn.just_moved_two_steps:

Dif pawn.position == opponent_pawn.position + (0, 2) and opponent_pawn.just_moved_two_steps:

Step-by-Step Solution

Solution:

Step 1: Understand en passant capture logic
En passant occurs when a pawn moves two steps forward and an opponent pawn is adjacent.
Step 2: Check correct position and move conditions
The capturing pawn must be next to the opponent pawn's position plus one step forward.
Final Answer:
if pawn.position == opponent_pawn.position + (0, 1) and opponent_pawn.just_moved_two_steps: -> Option C
Quick Check:
En passant condition code = B [OK]

Quick Trick: En passant checks adjacent pawn just moved two steps [OK]

Common Mistakes:

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Which of the following code snippets correctly represents the en passant capture condition check?