/etc/passwd and /etc/shadow in Linux CLI - Mini Project: Build & Apply

Exploring /etc/passwd and /etc/shadow Files

📖 Scenario: You are a system administrator learning how to read user account information on a Linux system. The /etc/passwd file stores basic user info, and the /etc/shadow file stores secure password data.Understanding these files helps you manage users and security on your system.

🎯 Goal: Build simple commands to read and extract information from /etc/passwd and /etc/shadow files.

📋 What You'll Learn

Use cat to display file contents

Use cut to extract specific fields

Use grep to find lines matching a username

Understand the structure of /etc/passwd and /etc/shadow

💡 Why This Matters

🌍 Real World

System administrators often need to read and understand user account files to manage users and security on Linux systems.

💼 Career

Knowing how to read /etc/passwd and /etc/shadow is essential for Linux system administration and security auditing roles.

1

Display the contents of /etc/passwd

Use the command cat /etc/passwd to display the full contents of the /etc/passwd file.

Linux CLI

# Type the command to display /etc/passwd contents
# Your code here

Hint

The cat command shows the whole file content.

2

Extract the usernames from /etc/passwd

Use the command cut -d ':' -f 1 /etc/passwd to extract only the usernames (the first field) from the /etc/passwd file.

Linux CLI

cat /etc/passwd
# Use cut to extract usernames from /etc/passwd
# Your code here

Hint

The cut command splits lines by ':' and selects the first part.

3

Find the line for the user root in /etc/shadow

Use the command grep '^root:' /etc/shadow to find the line starting with root: in the /etc/shadow file.

Linux CLI

cat /etc/passwd
cut -d ':' -f 1 /etc/passwd
# Use grep to find the root user line in /etc/shadow
# Your code here

Hint

The grep command searches for lines starting with 'root:' in the file.

4

Display the username and encrypted password field from /etc/shadow

Use the command cut -d ':' -f 1,2 /etc/shadow to display only the username and encrypted password fields from the /etc/shadow file.

Linux CLI

cat /etc/passwd
cut -d ':' -f 1 /etc/passwd
grep '^root:' /etc/shadow
# Use cut to show username and password fields from /etc/shadow
# Your code here

Hint

Use cut with fields 1 and 2 separated by a comma to get username and password.

Practice

1. What is the primary purpose of the /etc/passwd file in Linux?

easy

A. To store encrypted user passwords securely

B. To configure network settings

C. To store user account information accessible to all users

D. To log system errors

Solution

1. Step 1: Understand the role of /etc/passwd

   The /etc/passwd file contains user account details like username, user ID, group ID, home directory, and shell. It is readable by all users.

2. Step 2: Differentiate from /etc/shadow

   The encrypted passwords are stored separately in /etc/shadow for security, not in /etc/passwd.

3. Final Answer:

   To store user account information accessible to all users -> Option C

4. Quick Check:

   /etc/passwd = user info file [OK]

Hint: Remember: passwd = public user info, shadow = private passwords [OK]

Common Mistakes:

• Confusing /etc/passwd with /etc/shadow
• Thinking passwords are stored in /etc/passwd
• Assuming /etc/passwd stores system logs

2. Which of the following lines correctly shows the format of a typical /etc/shadow entry?

easy

A. username:x:1000:1000:User Name:/home/user:/bin/bash

B. username:$6$randomsalt$encryptedpassword:18000:0:99999:7:::

C. username:password:1000:1000:User Name:/home/user:/bin/bash

D. username:encryptedpassword:1000:1000:User Name:/home/user:/bin/bash

Solution

1. Step 1: Identify /etc/shadow format

   The /etc/shadow file stores encrypted passwords and related info. The password field looks like $6$randomsalt$encryptedpassword for SHA-512 encryption.

2. Step 2: Compare options

   The line username:$6$randomsalt$encryptedpassword:18000:0:99999:7::: matches the shadow file format with encrypted password (indicated by $6$) and password aging fields separated by colons. The other options resemble /etc/passwd format or have incorrect password fields.

3. Final Answer:

   username:$6$randomsalt$encryptedpassword:18000:0:99999:7::: -> Option B

4. Quick Check:

   /etc/shadow entries have encrypted passwords with $ signs [OK]

Hint: Look for $ signs and many colon-separated fields in shadow entries [OK]

Common Mistakes:

• Confusing /etc/passwd format with /etc/shadow
• Expecting plain text passwords in /etc/shadow
• Missing fields after encrypted password

3. Given the following command:

grep '^root:' /etc/passwd | cut -d':' -f1,3,7

What will be the output format?

medium

A. root:/bin/bash

B. root:x:0:0:root:/root:/bin/bash

C. root:0:0

D. root:0:/bin/bash

Solution

1. Step 1: Understand the command parts

   grep '^root:' /etc/passwd finds the line starting with 'root:'. cut -d':' -f1,3,7 extracts fields 1 (username), 3 (UID), and 7 (shell) separated by colons.

2. Step 2: Identify root line fields

   Typical root line: root:x:0:0:root:/root:/bin/bash. Fields: 1=root, 2=x, 3=0, 4=0, 5=root, 6=/root, 7=/bin/bash.

3. Step 3: Extract fields 1,3,7

   Fields 1=root, 3=0, 7=/bin/bash. Joined by colons: root:0:/bin/bash.

4. Final Answer:

   root:0:/bin/bash -> Option D

5. Quick Check:

   Fields 1,3,7 from /etc/passwd line = root:0:/bin/bash [OK]

Hint: Count fields carefully; cut -f1,3,7 picks username, UID, shell [OK]

Common Mistakes:

• Mixing up field numbers in cut command
• Expecting full /etc/passwd line output
• Confusing shadow file format with passwd

4. You run this command to check password expiry info:

sudo chage -l username

But it shows an error: chage: user 'username' does not exist. What is the most likely cause?

medium

A. The username is missing in /etc/passwd

B. The /etc/shadow file is empty

C. The chage command is not installed

D. The user has no password set

Solution

1. Step 1: Understand chage user check

   The chage command checks user password expiry info by looking up the username in /etc/passwd.

2. Step 2: Analyze error cause

   Error 'user does not exist' means the username is not found in /etc/passwd. If the user was missing there, chage cannot proceed.

3. Final Answer:

   The username is missing in /etc/passwd -> Option A

4. Quick Check:

   User must exist in /etc/passwd for chage to work [OK]

Hint: Check /etc/passwd for username before using chage [OK]

Common Mistakes:

• Assuming /etc/shadow emptiness causes this error
• Thinking chage command missing causes user error
• Believing no password set triggers 'user does not exist'

5. You want to write a script that lists all users who have a valid login shell (not /usr/sbin/nologin or /bin/false) by reading /etc/passwd. Which command snippet correctly filters these users?

hard

A. awk -F':' '$7 != "/usr/sbin/nologin" && $7 != "/bin/false" {print $1}' /etc/passwd

B. grep -v '/usr/sbin/nologin' /etc/shadow | cut -d':' -f1

C. cat /etc/passwd | grep '/bin/bash' | awk '{print $1}'

D. sed '/nologin/d' /etc/passwd | cut -d':' -f7

Solution

1. Step 1: Identify shell field in /etc/passwd

   The 7th field in /etc/passwd is the user's login shell. We want to exclude /usr/sbin/nologin and /bin/false.

2. Step 2: Analyze each option

   awk -F':' '$7 != "/usr/sbin/nologin" && $7 != "/bin/false" {print $1}' /etc/passwd uses awk with field separator ':' and filters out unwanted shells, printing usernames (field 1). grep -v '/usr/sbin/nologin' /etc/shadow | cut -d':' -f1 wrongly reads /etc/shadow and uses grep -v incorrectly. cat /etc/passwd | grep '/bin/bash' | awk '{print $1}' filters only /bin/bash but misses other valid shells. sed '/nologin/d' /etc/passwd | cut -d':' -f7 deletes lines with 'nologin' but then prints shell field, not usernames.

3. Final Answer:

   awk -F':' '$7 != "/usr/sbin/nologin" && $7 != "/bin/false" {print $1}' /etc/passwd -> Option A

4. Quick Check:

   Use awk on /etc/passwd to filter shell field and print usernames [OK]

Hint: Use awk with FS=':' and check field 7 for valid shells [OK]

Common Mistakes:

• Using /etc/shadow instead of /etc/passwd for shell info
• Printing wrong fields (shell instead of username)
• Using grep without proper field filtering