Conditional routing in graphs in LangChain - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a conditional routing node that directs based on input.

LangChain

from langchain.graphs import ConditionalRouter

router = ConditionalRouter(condition=[1])

Drag options to blanks, or click blank then click option'

Alambda x: x == 5

Blambda x: x > 10

Clambda x: x < 0

Dlambda x: x != 3

Attempts:

3 left

💡 Hint

Common Mistakes

Using a condition that does not return a boolean.

Forgetting to use a lambda function.

The condition lambda x: x == 5 correctly defines a condition for routing when input equals 5.

2fill in blank

medium

Complete the code to add two branches to the conditional router.

LangChain

router.add_branch('yes', [1])
router.add_branch('no', lambda x: False)

Drag options to blanks, or click blank then click option'

Alambda x: x == 5

Blambda x: x < 0

Clambda x: x > 10

Dlambda x: x != 3

Attempts:

3 left

💡 Hint

Common Mistakes

Using a condition that conflicts with the router's main condition.

Not using a lambda function.

The 'yes' branch uses the condition lambda x: x == 5 to route inputs equal to 5.

3fill in blank

hard

Fix the error in the conditional routing function to correctly route inputs.

LangChain

def route_input(input_value):
    if input_value [1] 5:
        return 'yes'
    else:
        return 'no'

Drag options to blanks, or click blank then click option'

A=>

B=

C==

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '=' instead of '==' causes syntax errors.

Using '=>' is invalid syntax in Python.

The '==' operator correctly compares input_value to 5 for routing decisions.

4fill in blank

hard

Fill both blanks to define a conditional router with two branches for positive and negative inputs.

LangChain

router = ConditionalRouter(condition=[1])
router.add_branch('positive', [2])

Drag options to blanks, or click blank then click option'

Alambda x: x >= 0

Blambda x: x > 0

Clambda x: x < 0

Dlambda x: x <= 0

Attempts:

3 left

💡 Hint

Common Mistakes

Confusing >= and > operators.

Using the same condition for both router and branch.

The router condition checks for non-negative inputs, and the 'positive' branch routes inputs greater than zero.

5fill in blank

hard

Fill all three blanks to create a conditional router with branches for even, odd, and zero inputs.

LangChain

router = ConditionalRouter(condition=[1])
router.add_branch('even', [2])
router.add_branch('odd', [3])

Drag options to blanks, or click blank then click option'

Alambda x: x != 0

Blambda x: x % 2 == 0 and x != 0

Clambda x: x % 2 != 0

Dlambda x: x == 0

Attempts:

3 left

💡 Hint

Common Mistakes

Not excluding zero in the router condition.

Mixing up even and odd conditions.

The router condition excludes zero; 'even' branch handles non-zero even numbers; 'odd' branch handles odd numbers.