Conditional routing in graphs in LangChain - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a conditional routing node that directs based on input.

LangChain

from langchain.graphs import ConditionalRouter

router = ConditionalRouter(condition=[1])

Drag options to blanks, or click blank then click option'

Alambda x: x == 5

Blambda x: x > 10

Clambda x: x < 0

Dlambda x: x != 3

Attempts:

3 left

💡 Hint

Common Mistakes

Using a condition that does not return a boolean.

Forgetting to use a lambda function.

The condition lambda x: x == 5 correctly defines a condition for routing when input equals 5.

2fill in blank

medium

Complete the code to add two branches to the conditional router.

LangChain

router.add_branch('yes', [1])
router.add_branch('no', lambda x: False)

Drag options to blanks, or click blank then click option'

Alambda x: x == 5

Blambda x: x < 0

Clambda x: x > 10

Dlambda x: x != 3

Attempts:

3 left

💡 Hint

Common Mistakes

Using a condition that conflicts with the router's main condition.

Not using a lambda function.

The 'yes' branch uses the condition lambda x: x == 5 to route inputs equal to 5.

3fill in blank

hard

Fix the error in the conditional routing function to correctly route inputs.

LangChain

def route_input(input_value):
    if input_value [1] 5:
        return 'yes'
    else:
        return 'no'

Drag options to blanks, or click blank then click option'

A=>

B=

C==

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '=' instead of '==' causes syntax errors.

Using '=>' is invalid syntax in Python.

The '==' operator correctly compares input_value to 5 for routing decisions.

4fill in blank

hard

Fill both blanks to define a conditional router with two branches for positive and negative inputs.

LangChain

router = ConditionalRouter(condition=[1])
router.add_branch('positive', [2])

Drag options to blanks, or click blank then click option'

Alambda x: x >= 0

Blambda x: x > 0

Clambda x: x < 0

Dlambda x: x <= 0

Attempts:

3 left

💡 Hint

Common Mistakes

Confusing >= and > operators.

Using the same condition for both router and branch.

The router condition checks for non-negative inputs, and the 'positive' branch routes inputs greater than zero.

5fill in blank

hard

Fill all three blanks to create a conditional router with branches for even, odd, and zero inputs.

LangChain

router = ConditionalRouter(condition=[1])
router.add_branch('even', [2])
router.add_branch('odd', [3])

Drag options to blanks, or click blank then click option'

Alambda x: x != 0

Blambda x: x % 2 == 0 and x != 0

Clambda x: x % 2 != 0

Dlambda x: x == 0

Attempts:

3 left

💡 Hint

Common Mistakes

Not excluding zero in the router condition.

Mixing up even and odd conditions.

The router condition excludes zero; 'even' branch handles non-zero even numbers; 'odd' branch handles odd numbers.

Practice

1. What is the main purpose of conditional routing in Langchain graphs?

easy

A. To randomly select a node without any rules

B. To execute all nodes in parallel regardless of conditions

C. To stop the graph execution immediately

D. To choose the next node based on specific conditions

Solution

1. Step 1: Understand conditional routing concept

   Conditional routing means selecting the next step based on rules or conditions.

2. Step 2: Match purpose with options

   Only To choose the next node based on specific conditions describes choosing the next node based on conditions, which fits the concept.

3. Final Answer:

   To choose the next node based on specific conditions -> Option D

4. Quick Check:

   Conditional routing = choose next node by condition [OK]

Hint: Think: routing means choosing path by rules [OK]

Common Mistakes:

• Confusing routing with parallel execution
• Assuming routing stops the graph
• Thinking routing is random

2. Which of the following is the correct way to define a condition function for routing in Langchain?

easy

A. def condition(context): return context['value'] > 10

B. condition = context => context.value > 10

C. def condition(): return context['value'] > 10

D. condition(context): return context.value > 10

Solution

1. Step 1: Check function syntax in Python

   Python functions require 'def' keyword, a parameter list, and a return statement.

2. Step 2: Validate each option

   def condition(context): return context['value'] > 10 correctly defines a function with one parameter and returns a boolean. condition = context => context.value > 10 uses JavaScript syntax. def condition(): return context['value'] > 10 misses the parameter. condition(context): return context.value > 10 misses 'def' keyword.

3. Final Answer:

   def condition(context): return context['value'] > 10 -> Option A

4. Quick Check:

   Python function with parameter and return = def condition(context): return context['value'] > 10 [OK]

Hint: Remember Python function syntax: def name(params): return value [OK]

Common Mistakes:

• Using JavaScript arrow function syntax in Python
• Omitting function parameters
• Missing 'def' keyword

3. Given this routing setup in Langchain graph:

conditions = [
  lambda ctx: ctx['score'] > 80,
  lambda ctx: ctx['score'] > 50
]
routes = ['high', 'medium', 'low']
context = {'score': 65}

Which route will be chosen?

medium

A. "high"

B. "medium"

C. "low"

D. Error due to missing condition

Solution

1. Step 1: Evaluate conditions in order with context

   First condition: score > 80? 65 > 80 is False. Second condition: score > 50? 65 > 50 is True.

2. Step 2: Match true condition to route

   Second condition matches, so route at index 1 is chosen, which is "medium".

3. Final Answer:

   "medium" -> Option B

4. Quick Check:

   First true condition index = route chosen [OK]

Hint: Check conditions top to bottom, pick first true route [OK]

Common Mistakes:

• Choosing 'high' because 65 > 50 but ignoring order
• Picking 'low' when conditions match
• Assuming error if not all conditions true

4. Identify the error in this Langchain routing code snippet:

def route_condition(context):
  if context['value'] > 10:
    return True
  elif context['value'] < 5:
    return False

routes = ['path1', 'path2']
# Routing uses route_condition

medium

A. Routes list should have three paths

B. The function uses wrong comparison operators

C. The function does not return a value for all cases

D. The function should return strings, not booleans

Solution

1. Step 1: Check function return paths

   The function returns True if value > 10, False if value < 5, but returns nothing if value is between 5 and 10.

2. Step 2: Understand routing condition requirements

   Routing conditions must return a boolean for every input to decide path. Missing return causes errors or unexpected behavior.

3. Final Answer:

   The function does not return a value for all cases -> Option C

4. Quick Check:

   All code paths must return a boolean [OK]

Hint: Ensure all if/else paths return a value [OK]

Common Mistakes:

• Ignoring missing return in some cases
• Thinking routes count must match conditions exactly
• Returning wrong data types

5. You want to route a Langchain graph node based on user input where:
- If input contains "urgent", go to 'priority' node
- If input length > 100, go to 'long' node
- Otherwise, go to 'normal' node

Which conditional routing setup correctly implements this logic?

hard

A. conditions = [lambda ctx: 'urgent' in ctx['input'], lambda ctx: len(ctx['input']) > 100]
routes = ['priority', 'long', 'normal']

B. conditions = [lambda ctx: len(ctx['input']) > 100, lambda ctx: 'urgent' in ctx['input']]
routes = ['long', 'priority', 'normal']

C. conditions = [lambda ctx: 'urgent' in ctx['input'] and len(ctx['input']) > 100]
routes = ['priority', 'long', 'normal']

D. conditions = [lambda ctx: 'urgent' not in ctx['input'], lambda ctx: len(ctx['input']) <= 100]
routes = ['normal', 'long', 'priority']

Solution

1. Step 1: Match conditions to requirements in order

   First condition checks if 'urgent' is in input, matching priority route. Second checks input length > 100 for long route.

2. Step 2: Confirm routes order matches conditions plus default

   Routes list has 'priority', 'long', then 'normal' as default if no condition matches.

3. Final Answer:

   conditions = [lambda ctx: 'urgent' in ctx['input'], lambda ctx: len(ctx['input']) > 100] routes = ['priority', 'long', 'normal'] -> Option A

4. Quick Check:

   Order and logic match requirements [OK]

Hint: Order conditions by priority, add default route last [OK]

Common Mistakes:

• Swapping condition order and routes
• Combining conditions incorrectly
• Using negated conditions that break logic