Consider a LangChain application using an LLM with caching enabled. What is the main effect of caching on API call costs?
Think about how storing previous answers can avoid repeating expensive calls.
Caching saves previous LLM responses so repeated queries do not trigger new API calls, reducing usage and cost.
Which code snippet correctly enables caching for an LLM in LangChain?
Look for the option that uses a cache object, not just a boolean.
LangChain requires a cache object like InMemoryCache() passed to the LLM constructor to enable caching.
Given this code snippet, why might caching not reduce API call costs?
from langchain.cache import InMemoryCache
from langchain.llms import OpenAI
cache = InMemoryCache()
llm = OpenAI(cache=cache)
response1 = llm('Hello')
response2 = llm('Hello')from langchain.cache import InMemoryCache from langchain.llms import OpenAI cache = InMemoryCache() llm = OpenAI(cache=cache) response1 = llm('Hello') response2 = llm('Hello')
Consider what happens to InMemoryCache when the program stops.
InMemoryCache only stores data during the program run. Restarting the program clears the cache, causing new API calls.
For a LangChain app with many repeated queries over days, which caching strategy is best to reduce API costs?
Think about how to keep cached data available across multiple days.
A persistent disk cache keeps data saved between program runs and days, reducing repeated API calls and costs effectively.
Given this code, how many API calls are made?
from langchain.cache import InMemoryCache from langchain.llms import OpenAI cache = InMemoryCache() llm = OpenAI(cache=cache) inputs = ['Hi', 'Hello', 'Hi', 'Hello', 'Hi'] responses = [llm(text) for text in inputs]
from langchain.cache import InMemoryCache from langchain.llms import OpenAI cache = InMemoryCache() llm = OpenAI(cache=cache) inputs = ['Hi', 'Hello', 'Hi', 'Hello', 'Hi'] responses = [llm(text) for text in inputs]
Count unique inputs and consider caching behavior.
Only unique inputs 'Hi' and 'Hello' cause API calls. Repeated inputs use cached results, so 2 calls total.