Throw as an expression in Kotlin - Mini Project: Build & Apply

Throw as an expression in Kotlin

📖 Scenario: You are building a simple Kotlin program that checks user input for a valid age. If the age is invalid, the program should stop and show an error.

🎯 Goal: Learn how to use throw as an expression in Kotlin to handle errors in a clean and concise way.

📋 What You'll Learn

Create a variable with a user age value

Create a minimum age limit variable

Use throw as an expression to check the age

Print a success message if the age is valid

💡 Why This Matters

🌍 Real World

Throwing exceptions as expressions helps write cleaner Kotlin code for input validation and error handling.

💼 Career

Understanding throw as an expression is important for Kotlin developers to write concise and safe code in apps and backend services.

1

Create the user age variable

Create an Int variable called userAge and set it to 20.

Kotlin

# Create an Int variable called userAge and set it to 20
# Your code here

Hint

Use val to create a variable that does not change.

2

Create the minimum age limit variable

Create an Int variable called minAge and set it to 18.

Kotlin

val userAge: Int = 20
# Create an Int variable called minAge and set it to 18
# Your code here

Hint

Use val to create a constant variable.

3

Use throw as an expression to check age

Create a variable called validAge that uses an if expression to check if userAge is greater than or equal to minAge. If true, assign true. Otherwise, use throw IllegalArgumentException("Age is below minimum") as the else expression.

Kotlin

val userAge: Int = 20
val minAge: Int = 18
# Create a variable validAge using if expression with throw as else
# Your code here

Hint

Use throw inside the else part of the if expression.

4

Print the success message

Write a println statement to print "User age is valid".

Kotlin

val userAge: Int = 20
val minAge: Int = 18
val validAge: Boolean = if (userAge >= minAge) true else throw IllegalArgumentException("Age is below minimum")
# Print "User age is valid" below
# Your code here

Hint

Use println("User age is valid") to show the message.

Practice

1.

What does the throw keyword do when used as an expression in Kotlin?

easy

A. It declares a new variable.

B. It returns a value from a function.

C. It immediately stops execution and throws an exception.

D. It creates a new thread.

Solution

1. Step 1: Understand the role of throw

   The throw keyword is used to signal an error by throwing an exception.

2. Step 2: Recognize its effect in expressions

   When used as an expression, throw stops the current execution and throws the specified exception immediately.

3. Final Answer:

   It immediately stops execution and throws an exception. -> Option C

4. Quick Check:

   throw = stops and throws error [OK]

Hint: Throw always stops execution and signals an error [OK]

Common Mistakes:

• Thinking throw returns a normal value
• Confusing throw with return
• Assuming throw creates variables

2.

Which of the following is the correct way to use throw as an expression in Kotlin?

val number = if (input > 0) input else ???

easy

A. throw IllegalArgumentException("Input must be positive")

B. return IllegalArgumentException("Input must be positive")

C. println("Input must be positive")

D. throw new Exception("Input must be positive")

Solution

1. Step 1: Check Kotlin syntax for throw expression

   In Kotlin, throw is used without new keyword and can be used as an expression.

2. Step 2: Match the correct usage in the if-else expression

   The correct syntax is throw IllegalArgumentException("message") without new and it fits as an expression in else branch.

3. Final Answer:

   throw IllegalArgumentException("Input must be positive") -> Option A

4. Quick Check:

   Throw expression syntax = throw IllegalArgumentException("Input must be positive") [OK]

Hint: Use throw without 'new' keyword in Kotlin [OK]

Common Mistakes:

• Using 'new' keyword with throw
• Using return instead of throw
• Trying to print error instead of throwing

3.

What will be the output of this Kotlin code?

fun getName(name: String?): String {
    return name ?: throw IllegalArgumentException("Name required")
}

fun main() {
    println(getName(null))
}

medium

A. Compilation error

B. Name required

C. null

D. Exception in thread "main" java.lang.IllegalArgumentException: Name required

Solution

1. Step 1: Analyze the Elvis operator with throw

   The expression name ?: throw IllegalArgumentException("Name required") returns name if not null, else throws the exception.

2. Step 2: Check the input and output

   Since getName(null) is called, name is null, so the exception is thrown and program crashes with that message.

3. Final Answer:

   Exception in thread "main" java.lang.IllegalArgumentException: Name required -> Option D

4. Quick Check:

   Throw in Elvis operator throws exception [OK]

Hint: Elvis ?: with throw throws exception if left is null [OK]

Common Mistakes:

• Expecting null to print
• Thinking exception message prints normally
• Assuming code compiles but returns empty string

4.

Identify the error in this Kotlin code snippet:

val age = 20
val validAge = if (age >= 18) age else throw "Age must be 18 or older"

medium

A. Cannot throw a String, must throw an Exception object.

B. The if expression is missing braces.

C. The variable age should be nullable.

D. The else branch should return a value, not throw.

Solution

1. Step 1: Check the throw expression type

   In Kotlin, throw must throw an object of type Throwable, not a plain String.

2. Step 2: Identify the error in else branch

   The code tries to throw a String literal, which is invalid and causes a compilation error.

3. Final Answer:

   Cannot throw a String, must throw an Exception object. -> Option A

4. Quick Check:

   Throw must be Exception, not String [OK]

Hint: Throw only Exception objects, not strings [OK]

Common Mistakes:

• Throwing plain strings instead of exceptions
• Missing braces but code compiles anyway
• Confusing throw with return

5.

Given this Kotlin function:

fun parseNumber(input: String?): Int {
    val number = input?.toIntOrNull() ?: throw NumberFormatException("Invalid number")
    return number
}

What will parseNumber(null) do, and why is throw used as an expression here?

hard

A. Compiles but causes runtime error unrelated to throw.

B. Throws NumberFormatException because input is null; throw used to combine error and assignment.

C. Returns null because input is nullable; throw is a statement here.

D. Returns 0 because null converts to zero; throw is ignored.

Solution

1. Step 1: Understand the Elvis operator with throw

   The expression input?.toIntOrNull() ?: throw NumberFormatException("Invalid number") tries to convert input to Int or throws if null or invalid.

2. Step 2: Analyze behavior when input is null

   Since input is null, toIntOrNull() returns null, so the throw expression executes, throwing the exception immediately.

3. Step 3: Reason why throw is used as expression

   Using throw as expression allows combining error handling with assignment in one line, making code concise and readable.

4. Final Answer:

   Throws NumberFormatException because input is null; throw used to combine error and assignment. -> Option B

5. Quick Check:

   Throw expression combines error and value assignment [OK]

Hint: Throw as expression lets you handle errors inline [OK]

Common Mistakes:

• Thinking null converts to zero
• Confusing throw as statement only
• Ignoring exception thrown on null input