Throw as an expression in Kotlin

Introduction

Throwing an error can be used as a value in Kotlin. This helps write shorter and clearer code by combining error handling with expressions.

When you want to stop a function and show an error if a condition is not met.

When you want to assign a value but throw an error if the value is missing or invalid.

When you want to use a throw inside a simple expression like an if or Elvis operator.

When you want to avoid writing extra lines for error checks and keep code clean.

Syntax

Kotlin

val result = someValue ?: throw Exception("Error message")

The throw keyword can be used wherever an expression is expected.

This means you can use it with operators like ?: (Elvis) or in assignments.

Examples

If name is null, the program throws an error instead of assigning a value.

Kotlin

val name: String? = null
val safeName = name ?: throw IllegalArgumentException("Name required")

This function returns num if not null, otherwise throws an error.

Kotlin

fun getNumber(num: Int?): Int = num ?: throw NullPointerException("Number missing")

Throw is used inside an if expression to handle the else case.

Kotlin

val age = 20
val category = if (age >= 18) "Adult" else throw Exception("Too young")

Sample Program

This program tries to assign input to result. Since input is null, it throws an error instead of printing.

Kotlin

fun main() {
    val input: String? = null
    val result = input ?: throw IllegalStateException("Input cannot be null")
    println("Result: $result")
}

Important Notes

Using throw as an expression helps reduce extra if-checks and makes code concise.

Remember that throwing stops the current function unless caught by a try-catch.

Summary

Throw as an expression lets you throw errors inside expressions like assignments or operators.

This makes your code shorter and easier to read by combining error handling with value assignment.

Practice

1.

What does the throw keyword do when used as an expression in Kotlin?

easy

A. It declares a new variable.

B. It returns a value from a function.

C. It immediately stops execution and throws an exception.

D. It creates a new thread.

Solution

1. Step 1: Understand the role of throw

   The throw keyword is used to signal an error by throwing an exception.

2. Step 2: Recognize its effect in expressions

   When used as an expression, throw stops the current execution and throws the specified exception immediately.

3. Final Answer:

   It immediately stops execution and throws an exception. -> Option C

4. Quick Check:

   throw = stops and throws error [OK]

Hint: Throw always stops execution and signals an error [OK]

Common Mistakes:

• Thinking throw returns a normal value
• Confusing throw with return
• Assuming throw creates variables

2.

Which of the following is the correct way to use throw as an expression in Kotlin?

val number = if (input > 0) input else ???

easy

A. throw IllegalArgumentException("Input must be positive")

B. return IllegalArgumentException("Input must be positive")

C. println("Input must be positive")

D. throw new Exception("Input must be positive")

Solution

1. Step 1: Check Kotlin syntax for throw expression

   In Kotlin, throw is used without new keyword and can be used as an expression.

2. Step 2: Match the correct usage in the if-else expression

   The correct syntax is throw IllegalArgumentException("message") without new and it fits as an expression in else branch.

3. Final Answer:

   throw IllegalArgumentException("Input must be positive") -> Option A

4. Quick Check:

   Throw expression syntax = throw IllegalArgumentException("Input must be positive") [OK]

Hint: Use throw without 'new' keyword in Kotlin [OK]

Common Mistakes:

• Using 'new' keyword with throw
• Using return instead of throw
• Trying to print error instead of throwing

3.

What will be the output of this Kotlin code?

fun getName(name: String?): String {
    return name ?: throw IllegalArgumentException("Name required")
}

fun main() {
    println(getName(null))
}

medium

A. Compilation error

B. Name required

C. null

D. Exception in thread "main" java.lang.IllegalArgumentException: Name required

Solution

1. Step 1: Analyze the Elvis operator with throw

   The expression name ?: throw IllegalArgumentException("Name required") returns name if not null, else throws the exception.

2. Step 2: Check the input and output

   Since getName(null) is called, name is null, so the exception is thrown and program crashes with that message.

3. Final Answer:

   Exception in thread "main" java.lang.IllegalArgumentException: Name required -> Option D

4. Quick Check:

   Throw in Elvis operator throws exception [OK]

Hint: Elvis ?: with throw throws exception if left is null [OK]

Common Mistakes:

• Expecting null to print
• Thinking exception message prints normally
• Assuming code compiles but returns empty string

4.

Identify the error in this Kotlin code snippet:

val age = 20
val validAge = if (age >= 18) age else throw "Age must be 18 or older"

medium

A. Cannot throw a String, must throw an Exception object.

B. The if expression is missing braces.

C. The variable age should be nullable.

D. The else branch should return a value, not throw.

Solution

1. Step 1: Check the throw expression type

   In Kotlin, throw must throw an object of type Throwable, not a plain String.

2. Step 2: Identify the error in else branch

   The code tries to throw a String literal, which is invalid and causes a compilation error.

3. Final Answer:

   Cannot throw a String, must throw an Exception object. -> Option A

4. Quick Check:

   Throw must be Exception, not String [OK]

Hint: Throw only Exception objects, not strings [OK]

Common Mistakes:

• Throwing plain strings instead of exceptions
• Missing braces but code compiles anyway
• Confusing throw with return

5.

Given this Kotlin function:

fun parseNumber(input: String?): Int {
    val number = input?.toIntOrNull() ?: throw NumberFormatException("Invalid number")
    return number
}

What will parseNumber(null) do, and why is throw used as an expression here?

hard

A. Compiles but causes runtime error unrelated to throw.

B. Throws NumberFormatException because input is null; throw used to combine error and assignment.

C. Returns null because input is nullable; throw is a statement here.

D. Returns 0 because null converts to zero; throw is ignored.

Solution

1. Step 1: Understand the Elvis operator with throw

   The expression input?.toIntOrNull() ?: throw NumberFormatException("Invalid number") tries to convert input to Int or throws if null or invalid.

2. Step 2: Analyze behavior when input is null

   Since input is null, toIntOrNull() returns null, so the throw expression executes, throwing the exception immediately.

3. Step 3: Reason why throw is used as expression

   Using throw as expression allows combining error handling with assignment in one line, making code concise and readable.

4. Final Answer:

   Throws NumberFormatException because input is null; throw used to combine error and assignment. -> Option B

5. Quick Check:

   Throw expression combines error and value assignment [OK]

Hint: Throw as expression lets you handle errors inline [OK]

Common Mistakes:

• Thinking null converts to zero
• Confusing throw as statement only
• Ignoring exception thrown on null input