String comparison (equals, compareTo) in Kotlin - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check if two strings are equal using the correct method.

Kotlin

val result = str1.[1](str2)
println(result)

Drag options to blanks, or click blank then click option'

AcompareTo

Bequals

C==

DequalsIgnoreCase

Attempts:

3 left

💡 Hint

Common Mistakes

Using compareTo instead of equals causes confusion because it returns an integer.

Using == which compares content in Kotlin, but is an operator not a method call.

The equals method checks if two strings have the same content exactly.

2fill in blank

medium

Complete the code to compare two strings lexicographically and print the result.

Kotlin

val comparison = str1.[1](str2)
println(comparison)

Drag options to blanks, or click blank then click option'

AcompareTo

Bequals

C==

DequalsIgnoreCase

Attempts:

3 left

💡 Hint

Common Mistakes

Using equals instead of compareTo when needing order comparison.

Expecting compareTo to return a boolean.

The compareTo method compares strings lexicographically and returns an integer.

3fill in blank

hard

Fix the error in the code to correctly check if two strings are equal ignoring case.

Kotlin

val isEqual = str1.[1](str2)
println(isEqual)

Drag options to blanks, or click blank then click option'

A==

BcompareTo

Cequals

DequalsIgnoreCase

Attempts:

3 left

💡 Hint

Common Mistakes

Using equals which is case sensitive.

Using compareTo which returns an integer, not boolean.

The equalsIgnoreCase method compares strings ignoring letter case differences.

4fill in blank

hard

Fill both blanks to create a map of words to their lengths only if the length is greater than 3.

Kotlin

val lengths = buildMap<String, Int> {
  for ([1] in words) {
    if ([2] > 3) {
      this[[1]] = [2]
    }
  }
}

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Aword

Blen(word)

Cword.length

Dword.size

Attempts:

3 left

💡 Hint

Common Mistakes

Using len(word) which is Python syntax, not Kotlin.

Using word.size which is not a valid property for String length in Kotlin.

We use word as the key and word.length as the value. The condition checks length > 3.

5fill in blank

hard

Fill all three blanks to create a map of uppercase words to their lengths only if length is greater than 4.

Kotlin

val result = buildMap<String, Int> {
  for ([3] in words) {
    if ([2] > 4) {
      this[[1]] = [2]
    }
  }
}

Drag options to blanks, or click blank then click option'

Aword.uppercase()

Bword.length

Cword

Dword.lowercase()

Attempts:

3 left

💡 Hint

Common Mistakes

Using lowercase() instead of uppercase() for the key.

Using incorrect loop variable names.

The key is the uppercase version of the word, the value is its length, and the loop variable is word.