Partition for splitting in Kotlin - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to split the list into two lists based on a condition.

Kotlin

val numbers = listOf(1, 2, 3, 4, 5)
val (even, odd) = numbers.partition { it [1] 2 == 0 }

Drag options to blanks, or click blank then click option'

A%

Bmod

Cdiv

Drem

Attempts:

3 left

💡 Hint

Common Mistakes

Using division operator instead of modulo

Using incorrect operator like 'mod' which is not valid syntax

The '%' operator is used to get the remainder, so 'it % 2 == 0' checks if a number is even.

2fill in blank

medium

Complete the code to partition words by length greater than 3.

Kotlin

val words = listOf("cat", "house", "dog", "elephant")
val (longWords, shortWords) = words.partition { it.length [1] 3 }

Drag options to blanks, or click blank then click option'

A<

B<=

C==

D>

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' which selects shorter words

Using '==' which selects words exactly length 3

We want words longer than 3, so the condition is 'it.length > 3'.

3fill in blank

hard

Fix the error in the partition condition to split numbers divisible by 3.

Kotlin

val nums = listOf(3, 4, 6, 7, 9)
val (divByThree, others) = nums.partition { it [1] 3 == 0 }

Drag options to blanks, or click blank then click option'

Amod

B%

C/

D*

Attempts:

3 left

💡 Hint

Common Mistakes

Using division '/' instead of modulo

Using multiplication '*' which is incorrect

The modulo operator '%' checks divisibility by 3 correctly.

4fill in blank

hard

Fill both blanks to partition a list of strings into those starting with 'a' and others.

Kotlin

val fruits = listOf("apple", "banana", "avocado", "cherry")
val (aFruits, otherFruits) = fruits.partition { it[1].startsWith([2]) }

Drag options to blanks, or click blank then click option'

A.

B->

C"a"

D'a'

Attempts:

3 left

💡 Hint

Common Mistakes

Using '->' instead of '.'

Using single quotes for string literal

Use '.' to call the method and double quotes for string literal "a".

5fill in blank

hard

Fill all three blanks to partition a list of integers into positives and non-positives.

Kotlin

val numbers = listOf(-1, 0, 2, 3, -5)
val (positive, nonPositive) = numbers.partition { it [1] [2] 0 [3] }

Drag options to blanks, or click blank then click option'

A>

B>=

C==

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' which selects negatives

Using '==' which selects only zero

The condition 'it > 0' selects positives; 'it >= 0' and 'it == 0' are common comparisons but only 'it > 0' is needed here.