A Map transformation in Kotlin means creating a new Map by changing the keys, values, or both from an existing Map without modifying the original one.
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beginner
How do you transform only the values of a Map in Kotlin?
You use the mapValues function, which applies a transformation to each value while keeping the keys the same.
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beginner
What does the mapKeys function do in Kotlin?
The mapKeys function creates a new Map by transforming the keys of the original Map while keeping the values unchanged.
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beginner
Show a simple example of transforming a Map's values by doubling them.
Given val map = mapOf("a" to 1, "b" to 2), val doubled = map.mapValues { it.value * 2 } Result: {"a"=2, "b"=4}
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intermediate
Can you transform both keys and values of a Map at the same time in Kotlin?
Yes, by using the map function on the Map's entries and then converting the result back to a Map with toMap().
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Which Kotlin function transforms only the values of a Map?
AmapKeys
BmapValues
Cmap
Dfilter
✗ Incorrect
The mapValues function changes only the values, keeping keys the same.
What does mapKeys do?
AFilters keys
BTransforms values only
CTransforms both keys and values
DTransforms keys only
✗ Incorrect
mapKeys changes keys but keeps values unchanged.
How do you transform both keys and values of a Map?
AUse mapValues and mapKeys together
BUse filter
CUse map on entries and then toMap()
DUse reduce
✗ Incorrect
Using map on entries lets you change both keys and values, then toMap() converts back to a Map.
What is the result of mapOf("x" to 3).mapValues { it.value + 1 }?
A{"x"=4}
B{"x"=3}
C{"x"=1}
D{}
✗ Incorrect
The value 3 is increased by 1, resulting in 4.
Which function keeps the original Map unchanged and returns a new transformed Map?
ABoth A and C
BmapValues
CmapKeys
DNone
✗ Incorrect
Both mapValues and mapKeys return new Maps without changing the original.
Explain how to transform only the values of a Map in Kotlin and give a simple example.
Think about a function that changes values but keeps keys the same.
You got /4 concepts.
Describe how to transform both keys and values of a Map in Kotlin.
Use map on entries and then convert back to Map.
You got /4 concepts.
Practice
(1/5)
1. What does the map function do when applied to a list in Kotlin?
easy
A. It removes elements from the list based on a condition.
B. It creates a new list by applying a transformation to each element.
C. It sorts the list in ascending order.
D. It changes the original list by modifying its elements.
Solution
Step 1: Understand the purpose of map
The map function applies a given transformation to each element of the list.
Step 2: Check the effect on the list
It returns a new list with transformed elements without changing the original list.
Final Answer:
It creates a new list by applying a transformation to each element. -> Option B
Quick Check:
map transforms each item and returns new list [OK]
Hint: Remember: map returns a new list, original stays same [OK]
Common Mistakes:
Thinking map modifies the original list
Confusing map with filter or sort
Assuming map removes elements
2. Which of the following is the correct syntax to transform a list of integers by doubling each value using map in Kotlin?
easy
A. val result = list.map { it * 2 }
B. val result = list.map(it * 2)
C. val result = list.map -> it * 2
D. val result = list.map { it + 2 }
Solution
Step 1: Identify correct lambda syntax
The map function requires a lambda inside curly braces: { it * 2 }.
Step 2: Check the transformation logic
Doubling means multiplying by 2, so it * 2 is correct.
Final Answer:
val result = list.map { it * 2 } -> Option A
Quick Check:
Correct lambda syntax with doubling [OK]
Hint: Use curly braces and 'it' for lambda in map [OK]
Common Mistakes:
Missing curly braces around lambda
Using parentheses instead of braces
Wrong operation inside lambda
3. What is the output of the following Kotlin code?
val numbers = listOf(1, 2, 3) val result = numbers.map { it + 5 } println(result)
medium
A. [6, 7, 8]
B. [1, 2, 3, 5]
C. [5, 6, 7]
D. [1, 2, 3]
Solution
Step 1: Apply the map transformation
Each element in numbers is increased by 5: 1+5=6, 2+5=7, 3+5=8.
Step 2: Form the new list
The new list is [6, 7, 8], which is printed.
Final Answer:
[6, 7, 8] -> Option A
Quick Check:
Each number +5 = [6, 7, 8] [OK]
Hint: Add 5 to each element inside map to get output [OK]
Common Mistakes:
Confusing original list with transformed list
Adding 5 only once instead of to each element
Misreading the output format
4. Identify the error in this Kotlin code snippet:
val list = listOf(1, 2, 3) val newList = list.map(it * 3) println(newList)
medium
A. The multiplication operator is incorrect.
B. Using map on a list is not allowed.
C. The list should be mutable to use map.
D. Missing curly braces around the lambda expression.
Solution
Step 1: Check lambda syntax in map
The map function requires a lambda inside curly braces, but here parentheses are used without braces.
Step 2: Confirm correct usage
Correct syntax is list.map { it * 3 } to apply multiplication.
Final Answer:
Missing curly braces around the lambda expression. -> Option D
Quick Check:
Lambda needs braces in map [OK]
Hint: Always use curly braces for lambda in map [OK]
Common Mistakes:
Using parentheses instead of braces for lambda
Thinking map needs mutable list
Misunderstanding operator usage
5. Given a list of strings val words = listOf("apple", "banana", "cherry"), how can you create a map where each word is a key and its length is the value using Kotlin's map transformation?
hard
A. val wordLengths = words.associateWith { it.length }
B. val wordLengths = words.map { it.length to it }
C. val wordLengths = words.map { it to it.length } .toMap()
D. val wordLengths = words.map { it.length }
Solution
Step 1: Understand the goal
We want a map where keys are words and values are their lengths.
Step 2: Use map to create pairs and convert to map
words.map { it to it.length } creates pairs (word, length). Then toMap() converts the list of pairs to a map.
Final Answer:
val wordLengths = words.map { it to it.length } .toMap() -> Option C
Quick Check:
Map pairs then convert to map [OK]
Hint: Use map to pairs and then toMap() for map creation [OK]
Common Mistakes:
Using associateWith is correct but not the asked map transformation
Mapping only lengths returns list, not map
Swapping key and value in pairs
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