It keyword for single parameter in Kotlin - Mini Project: Build & Apply

Using the It Keyword for Single Parameter in Kotlin

📖 Scenario: You are working on a simple Kotlin program that processes a list of names. You want to transform each name to uppercase using a concise way to handle single parameters in lambda expressions.

🎯 Goal: Learn how to use the it keyword in Kotlin lambda expressions when there is only one parameter.

📋 What You'll Learn

Create a list of names with exact values

Create a lambda expression using the it keyword to convert names to uppercase

Store the transformed names in a new list

Print the new list

💡 Why This Matters

🌍 Real World

Using the <code>it</code> keyword helps write shorter and clearer code when working with collections, such as lists of names, products, or messages.

💼 Career

Many Kotlin jobs require working with collections and lambdas. Knowing how to use <code>it</code> makes your code concise and easier to read, which is valued in professional Kotlin development.

1

Create a list of names

Create a list called names with these exact values: "alice", "bob", "charlie"

Kotlin

# Create a list called names with "alice", "bob", and "charlie"
# Your code here

Need a hint?

Use listOf to create a list with the given strings.

2

Create a lambda expression using the it keyword

Create a new list called upperNames by calling names.map and use a lambda expression with the it keyword to convert each name to uppercase using it.uppercase()

Kotlin

val names = listOf("alice", "bob", "charlie")
# Create upperNames by mapping names with it.uppercase()
# Your code here

Need a hint?

Use map with a lambda that uses it to refer to each element.

3

Print the transformed list

Print the upperNames list using println(upperNames)

Kotlin

val names = listOf("alice", "bob", "charlie")
val upperNames = names.map { it.uppercase() }
# Print the upperNames list
# Your code here

Need a hint?

Use println to display the list.

4

Use the it keyword in a filter lambda

Create a new list called filteredNames by calling names.filter and use a lambda with the it keyword to keep only names that start with the letter 'a' using it.startsWith('a'). Then print filteredNames using println(filteredNames)

Kotlin

val names = listOf("alice", "bob", "charlie")
val upperNames = names.map { it.uppercase() }
println(upperNames)
# Create filteredNames by filtering names with it.startsWith('a')
# Print filteredNames
# Your code here

Need a hint?

Use filter with a lambda using it to check the first letter.