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Kotlinprogramming~10 mins

Why immutable collections are default in Kotlin - Test Your Understanding

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to create an immutable list in Kotlin.

Kotlin
val numbers = listOf[1](1, 2, 3, 4, 5)
Drag options to blanks, or click blank then click option'
A<Any>
B<Int>
C(nothing)
D<Number>
Attempts:
3 left
💡 Hint
Common Mistakes
Using mutableListOf instead of listOf
Adding parentheses incorrectly
2fill in blank
medium

Complete the code to try adding an element to an immutable list and see the error.

Kotlin
val fruits = listOf("Apple", "Banana")
fruits.[1]("Cherry")
Drag options to blanks, or click blank then click option'
Aadd
Bappend
Cpush
Dinsert
Attempts:
3 left
💡 Hint
Common Mistakes
Using methods like append or push which don't exist in Kotlin lists
Trying to modify an immutable list directly
3fill in blank
hard

Fix the error by choosing the correct mutable collection type to allow adding elements.

Kotlin
val fruits = [1]("Apple", "Banana")
fruits.add("Cherry")
Drag options to blanks, or click blank then click option'
AmutableListOf
BlistOf
CsetOf
DmapOf
Attempts:
3 left
💡 Hint
Common Mistakes
Using listOf which is immutable
Using setOf or mapOf which are different collection types
4fill in blank
hard

Fill both blanks to create an immutable map and access a value safely.

Kotlin
val capitals = [1]("France" to "Paris", "Japan" to "Tokyo")
val capital = capitals.[2]("France")
Drag options to blanks, or click blank then click option'
AmapOf
Bget
CmutableMapOf
Dput
Attempts:
3 left
💡 Hint
Common Mistakes
Using mutableMapOf which creates a mutable map
Using put which adds or updates entries, not retrieves
5fill in blank
hard

Fill all three blanks to filter an immutable list and create a new list with only even numbers.

Kotlin
val numbers = listOf(1, 2, 3, 4, 5, 6)
val evens = numbers.[1] { it [2] 2 [3] 0 }
Drag options to blanks, or click blank then click option'
Afilter
B%
C==
Dmap
Attempts:
3 left
💡 Hint
Common Mistakes
Using map instead of filter which transforms elements
Using incorrect comparison operators

Practice

(1/5)
1. Why does Kotlin use immutable collections as the default choice?
easy
A. Because they prevent accidental changes and make code safer
B. Because they are faster to create than mutable collections
C. Because they allow adding elements after creation
D. Because they use less memory than mutable collections

Solution

  1. Step 1: Understand immutability concept

    Immutable collections cannot be changed after creation, preventing accidental modifications.
  2. Step 2: Recognize safety benefits

    This immutability makes programs safer and easier to understand by avoiding unexpected side effects.
  3. Final Answer:

    Because they prevent accidental changes and make code safer -> Option A
  4. Quick Check:

    Immutable collections = safer code [OK]
Hint: Immutable means no changes allowed after creation [OK]
Common Mistakes:
  • Thinking immutable collections allow adding elements
  • Assuming immutable collections are always faster
  • Confusing immutability with memory usage
2. Which of the following is the correct way to create an immutable list in Kotlin?
easy
A. val list = ArrayList(1, 2, 3)
B. val list = mutableListOf(1, 2, 3)
C. val list = arrayListOf(1, 2, 3)
D. val list = listOf(1, 2, 3)

Solution

  1. Step 1: Identify immutable list creation function

    In Kotlin, listOf() creates an immutable list.
  2. Step 2: Differentiate from mutable list functions

    mutableListOf(), arrayListOf(), and ArrayList() create mutable lists.
  3. Final Answer:

    val list = listOf(1, 2, 3) -> Option D
  4. Quick Check:

    Immutable list = listOf() [OK]
Hint: Use listOf() for immutable lists in Kotlin [OK]
Common Mistakes:
  • Using mutableListOf() when immutable is needed
  • Confusing arrayListOf() with immutable listOf()
  • Trying to use ArrayList constructor with elements directly
3. What will be the output of this Kotlin code?
val numbers = listOf(1, 2, 3)
numbers.add(4)
medium
A. List will contain [1, 2, 3, 4]
B. Compilation error: Unresolved reference 'add'
C. Runtime error: UnsupportedOperationException
D. List remains [1, 2, 3] without error

Solution

  1. Step 1: Recognize listOf creates immutable list

    The listOf() function returns an immutable list that does not support modification methods like add().
  2. Step 2: Understand behavior of calling add() on immutable list

    Calling add() on a List<T> causes a compilation error because List<T> has no add() method: Unresolved reference 'add'.
  3. Final Answer:

    Compilation error: Unresolved reference 'add' -> Option B
  4. Quick Check:

    Immutable list + add() = compile error [OK]
Hint: Immutable lists have no add() method: compile error [OK]
Common Mistakes:
  • Expecting runtime error instead of compile-time error
  • Assuming add() works on immutable lists
  • Thinking list remains unchanged silently
4. Identify the error in this Kotlin code snippet:
val set = setOf(1, 2, 3)
set.add(4)
medium
A. Runtime error: UnsupportedOperationException when calling add()
B. Syntax error: setOf cannot be used without mutable keyword
C. Compile-time error: add() is not a function of Set
D. No error, set will contain 4 elements

Solution

  1. Step 1: Understand setOf creates immutable set

    The setOf() function returns an immutable set that does not support modification.
  2. Step 2: Analyze calling add() on immutable set

    Calling add() on a Set<T> causes a compile-time error because Set<T> has no add() method.
  3. Final Answer:

    Compile-time error: add() is not a function of Set -> Option C
  4. Quick Check:

    Immutable set + add() = compile error [OK]
Hint: Immutable sets have no add() method: compile error [OK]
Common Mistakes:
  • Expecting runtime error instead of compile-time error
  • Assuming setOf creates mutable sets
  • Thinking add() silently fails without error
5. You want to create a map in Kotlin that cannot be changed after creation. Which approach correctly ensures immutability and prevents accidental modification?
hard
A. Use mapOf() to create an immutable map
B. Use mutableMapOf() and avoid calling modification methods
C. Create a mutable map and then assign it to a val variable
D. Use HashMap() and do not expose it outside the function

Solution

  1. Step 1: Identify immutable map creation method

    mapOf() creates an immutable map that cannot be changed after creation.
  2. Step 2: Understand why other options fail

    Using mutableMapOf() or HashMap() creates mutable maps; assigning to val only prevents reassignment, not modification.
  3. Final Answer:

    Use mapOf() to create an immutable map -> Option A
  4. Quick Check:

    Immutable map = mapOf() [OK]
Hint: Use mapOf() for truly immutable maps in Kotlin [OK]
Common Mistakes:
  • Thinking val prevents map modification
  • Using mutableMapOf() expecting immutability
  • Relying on scope to protect mutable maps
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10 questions~5 mineasy hard