Set creation (setOf, mutableSetOf) in Kotlin - Mini Project: Build & Apply

Set creation (setOf, mutableSetOf)

📖 Scenario: You are organizing a small party and want to keep track of unique guests who have confirmed their attendance.

🎯 Goal: Build a Kotlin program that creates a set of guest names using setOf and a mutable set using mutableSetOf.

📋 What You'll Learn

Create an immutable set of guest names using setOf

Create a mutable set of guest names using mutableSetOf

Add a new guest to the mutable set

Print both sets to see the guests

💡 Why This Matters

🌍 Real World

Sets are useful to keep track of unique items like guest lists, product IDs, or tags without duplicates.

💼 Career

Understanding sets helps in data processing, filtering duplicates, and managing collections efficiently in software development.

1

Create an immutable set of guests

Create an immutable set called guests using setOf with these exact names: "Alice", "Bob", "Charlie".

Kotlin

# Create an immutable set called guests with "Alice", "Bob", and "Charlie"
# Your code here

Hint

Use val guests = setOf("Alice", "Bob", "Charlie") to create the set.

2

Create a mutable set of guests

Create a mutable set called mutableGuests using mutableSetOf with these exact names: "Alice", "Bob", "Charlie".

Kotlin

val guests = setOf("Alice", "Bob", "Charlie")
# Create a mutable set called mutableGuests with "Alice", "Bob", and "Charlie"
# Your code here

Hint

Use val mutableGuests = mutableSetOf("Alice", "Bob", "Charlie") to create the mutable set.

3

Add a new guest to the mutable set

Add the guest "Diana" to the mutable set mutableGuests using the add method.

Kotlin

val guests = setOf("Alice", "Bob", "Charlie")
val mutableGuests = mutableSetOf("Alice", "Bob", "Charlie")
# Add "Diana" to mutableGuests
# Your code here

Hint

Use mutableGuests.add("Diana") to add the new guest.

4

Print both sets

Print the immutable set guests and the mutable set mutableGuests using two separate println statements.

Kotlin

val guests = setOf("Alice", "Bob", "Charlie")
val mutableGuests = mutableSetOf("Alice", "Bob", "Charlie")
mutableGuests.add("Diana")
# Print guests and mutableGuests
# Your code here

Hint

Use println(guests) and println(mutableGuests) to display the sets.

Practice

1. What does the Kotlin function setOf(1, 2, 2, 3) return?

easy

A. A list containing elements: 1, 2, 2, 3

B. A set containing duplicates: 1, 2, 2, 3

C. A set containing unique elements: 1, 2, 3

D. An error because of duplicate elements

Solution

1. Step 1: Understand setOf behavior

   setOf creates a set that holds only unique elements, automatically removing duplicates.

2. Step 2: Analyze the input elements

   The input has elements 1, 2, 2, 3. The duplicate 2 is ignored in the set.

3. Final Answer:

   A set containing unique elements: 1, 2, 3 -> Option C

4. Quick Check:

   setOf removes duplicates = unique elements [OK]

Hint: Remember: sets keep only unique items [OK]

Common Mistakes:

• Thinking sets keep duplicates like lists
• Confusing setOf with listOf
• Expecting an error for duplicates

2. Which of the following is the correct way to create a mutable set of strings in Kotlin?

easy

A. val mySet = mutableSetOf<String>("apple", "banana")

B. val mySet = setOf<String>("apple", "banana")

C. val mySet = mutableSet("apple", "banana")

D. val mySet = mutableSetOf("apple", "banana")

Solution

1. Step 1: Identify correct syntax for mutableSetOf

   The correct function is mutableSetOf with type parameter and parentheses.

2. Step 2: Check each option

   val mySet = mutableSetOf<String>("apple", "banana") uses mutableSetOf<String>("apple", "banana"), which is correct. val mySet = setOf<String>("apple", "banana") uses setOf which creates an immutable set. val mySet = mutableSet("apple", "banana") uses a non-existent function mutableSet. val mySet = mutableSetOf("apple", "banana") has a syntax error with an extra quote.

3. Final Answer:

   val mySet = mutableSetOf<String>("apple", "banana") -> Option A

4. Quick Check:

   mutableSetOf syntax correct = val mySet = mutableSetOf<String>("apple", "banana") [OK]

Hint: Use mutableSetOf() to create changeable sets [OK]

Common Mistakes:

• Using setOf instead of mutableSetOf for mutable sets
• Misspelling mutableSetOf
• Syntax errors with quotes or parentheses

3. What will be the output of this Kotlin code?

val numbers = mutableSetOf(1, 2, 3)
numbers.add(2)
numbers.add(4)
println(numbers)

medium

A. Compilation error

B. [1, 2, 3, 2, 4]

C. [1, 2, 3]

D. [1, 2, 3, 4]

Solution

1. Step 1: Understand mutableSetOf and add behavior

   The set starts with 1, 2, 3. Adding 2 again does nothing because sets ignore duplicates. Adding 4 adds a new element.

2. Step 2: Determine final set contents

   After additions, the set contains 1, 2, 3, and 4.

3. Final Answer:

   [1, 2, 3, 4] -> Option D

4. Quick Check:

   Sets ignore duplicates, so 2 is not added twice [OK]

Hint: Adding duplicates to sets does nothing [OK]

Common Mistakes:

• Expecting duplicates to appear in output
• Confusing set print format with list
• Thinking add returns error on duplicates

4. Identify the error in this Kotlin code snippet:

val fruits = setOf("apple", "banana")
fruits.add("orange")
println(fruits)

medium

A. Syntax error in setOf declaration

B. Cannot add elements to an immutable set

C. Missing import for setOf

D. No error, code runs fine

Solution

1. Step 1: Check mutability of setOf

   setOf creates an immutable set that cannot be changed after creation.

2. Step 2: Analyze the add operation

   Calling add on an immutable set causes a compilation error because the set cannot be modified.

3. Final Answer:

   Cannot add elements to an immutable set -> Option B

4. Quick Check:

   setOf = immutable, add() not allowed [OK]

Hint: Use mutableSetOf to add or remove items [OK]

Common Mistakes:

• Trying to modify immutable sets
• Confusing setOf with mutableSetOf
• Ignoring compiler error messages

5. You want to create a mutable set of integers from a list but only include numbers greater than 5. Which Kotlin code correctly does this?

hard

A. val nums = mutableSetOf(1, 6, 8, 3, 7).filterTo(mutableSetOf()) { it > 5 }

B. val nums = setOf(1, 6, 8, 3, 7).filter { it > 5 }.toSet()

C. val nums = mutableSetOf(1, 6, 8, 3, 7).filter { it > 5 }

D. val nums = mutableSetOf(1, 6, 8, 3, 7).filter { it > 5 }.toSet()

Solution

1. Step 1: Understand filtering and set creation

   We want a mutable set with only numbers > 5. Using filterTo with a mutable set collects filtered items directly into a mutable set.

2. Step 2: Evaluate each option

   val nums = mutableSetOf(1, 6, 8, 3, 7).filter { it > 5 } returns a List, not a mutable set. val nums = mutableSetOf(1, 6, 8, 3, 7).filterTo(mutableSetOf()) { it > 5 } correctly filters into a mutable set. val nums = setOf(1, 6, 8, 3, 7).filter { it > 5 }.toSet() creates an immutable set first, then filters to list and toSet(), producing an immutable set, not mutable. val nums = mutableSetOf(1, 6, 8, 3, 7).filter { it > 5 }.toSet() filters to a list then toSet(), producing an immutable set, not mutable.

3. Final Answer:

   val nums = mutableSetOf(1, 6, 8, 3, 7).filterTo(mutableSetOf()) { it > 5 } -> Option A

4. Quick Check:

   filterTo with mutableSetOf creates mutable set directly [OK]

Hint: Use filterTo(mutableSetOf()) for filtered mutable sets [OK]

Common Mistakes:

• Using filter() returns list, not set
• Not converting to mutable set after filtering
• Confusing setOf and mutableSetOf usage