For loop with ranges in Kotlin - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print numbers from 1 to 5 using a for loop.

Kotlin

for (i in [1]) {
    println(i)
}

Drag options to blanks, or click blank then click option'

A1 until 5

B1..5

C5..1

D5 until 1

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'until' which excludes the end number.

Reversing the range like '5..1' which does not work as expected.

The range 1..5 includes numbers from 1 to 5 inclusive.

2fill in blank

medium

Complete the code to print numbers from 1 up to but not including 5.

Kotlin

for (i in [1]) {
    println(i)
}

Drag options to blanks, or click blank then click option'

A1 until 5

B1..5

C0 until 5

D5 downTo 1

Attempts:

3 left

💡 Hint

Common Mistakes

Using '..' which includes the end number.

Using a reversed range which does not print anything.

The until operator creates a range excluding the end value, so 1 until 5 is 1, 2, 3, 4.

3fill in blank

hard

Fix the error in the for loop to count down from 5 to 1.

Kotlin

for (i in [1]) {
    println(i)
}

Drag options to blanks, or click blank then click option'

A5 downTo 1

B5..1

C1 downTo 5

D1..5

Attempts:

3 left

💡 Hint

Common Mistakes

Using '..' with reversed numbers which does not work.

Using 'downTo' with start less than end.

The downTo function creates a decreasing range from 5 down to 1.

4fill in blank

hard

Fill both blanks to create a for loop that prints even numbers from 2 to 10.

Kotlin

for (i in [1] step [2]) {
    println(i)
}

Drag options to blanks, or click blank then click option'

A2..10

B1..10

C2

D3

Attempts:

3 left

💡 Hint

Common Mistakes

Using step 3 which skips numbers incorrectly.

Starting range at 1 which includes odd numbers.

The range 2..10 includes numbers from 2 to 10, and step 2 makes the loop jump by 2, printing even numbers.

5fill in blank

hard

Fill all three blanks to create a for loop that prints numbers from 10 down to 1, stepping by 2.

Kotlin

for (i in [1] downTo [2] step [3]) {
    println(i)
}

Drag options to blanks, or click blank then click option'

A1

BdownTo

C2

D10

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'until' instead of 'downTo' for counting down.

Using step 1 which does not skip numbers.

The loop starts at 10, counts down to 1 using downTo, and steps by 2 to skip every other number.