For loop with index (withIndex) in Kotlin - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to loop over the list with index and print each index.

Kotlin

val fruits = listOf("Apple", "Banana", "Cherry")
for (([1], fruit) in fruits.withIndex()) {
    println("Index: $[1]")
}

Drag options to blanks, or click blank then click option'

Apos

Bi

Cindex

Dcount

Attempts:

3 left

💡 Hint

Common Mistakes

Using a variable name that does not match the index variable in the loop.

Forgetting to use parentheses around the destructured variables.

The variable 'index' is commonly used to represent the index in a for loop with withIndex().

2fill in blank

medium

Complete the code to print both index and fruit name inside the loop.

Kotlin

val fruits = listOf("Apple", "Banana", "Cherry")
for ((index, [1]) in fruits.withIndex()) {
    println("$index: $[1]")
}

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Aitem

Bfruit

Celement

Dvalue

Attempts:

3 left

💡 Hint

Common Mistakes

Using a variable name that is not descriptive of the list elements.

Mixing up the order of index and element in the destructuring.

The variable 'fruit' is used to represent each element in the list during iteration.

3fill in blank

hard

Fix the error in the loop variable declaration to correctly destructure index and element.

Kotlin

val numbers = listOf(10, 20, 30)
for ([1], num in numbers.withIndex()) {
    println("$num at index $[1]")
}

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A(index, num)

Bindex

C(index,)

D(index)

Attempts:

3 left

💡 Hint

Common Mistakes

Not using parentheses for destructuring.

Only declaring one variable instead of two.

The correct syntax for destructuring both index and element is '(index, num)'.

4fill in blank

hard

Fill both blanks to create a map of index to fruit name for fruits longer than 5 characters.

Kotlin

val fruits = listOf("Apple", "Banana", "Cherry", "Date")
val longFruits = fruits.withIndex().filter { it.value.length [1] 5 }.associate { it.index to it.[2] }

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A>

B<

Cvalue

Dlength

Attempts:

3 left

💡 Hint

Common Mistakes

Using the wrong comparison operator.

Using 'length' instead of 'value' in the associate function.

We filter fruits with length greater than 5 and associate index to the fruit value.

5fill in blank

hard

Fill all three blanks to create a list of strings showing index and fruit in uppercase for fruits starting with 'B' or later.

Kotlin

val fruits = listOf("Apple", "Banana", "Cherry", "Date")
val result = fruits.withIndex().filter { it.value[0] [1] 'B' }.map { "$[2]: $[3]" }
println(result)

Drag options to blanks, or click blank then click option'

A>=

Bit.index

Cit.value.uppercase()

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<=' instead of '>=' in the filter.

Not converting fruit names to uppercase.

We filter fruits starting with letters 'B' or later, then map to strings with index and uppercase fruit name.