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Kotlinprogramming~10 mins

Destructuring in collection iteration in Kotlin - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to destructure each pair in the list and print the key.

Kotlin
val pairs = listOf("a" to 1, "b" to 2)
for (([1], value) in pairs) {
    println([1])
}
Drag options to blanks, or click blank then click option'
Akey
Bfirst
Citem
Delement
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'key' or 'item' which are not the default names for Pair components.
2fill in blank
medium

Complete the code to destructure map entries and print both key and value.

Kotlin
val map = mapOf("x" to 10, "y" to 20)
for (([1], value) in map) {
    println("Key: $[1], Value: $value")
}
Drag options to blanks, or click blank then click option'
Aentry
Belement
Cindex
Dkey
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'entry' or 'index' which are not valid destructuring names for map entries.
3fill in blank
hard

Fix the error in destructuring a list of triples to print all three elements.

Kotlin
val triples = listOf(Triple(1, "a", true), Triple(2, "b", false))
for ((first, [1], third) in triples) {
    println("$first, $[1], $third")
}
Drag options to blanks, or click blank then click option'
Asecond
Bmiddle
Cvalue
Ditem
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'middle' or 'value' which are not valid component names for Triple.
4fill in blank
hard

Fill both blanks to destructure a list of pairs and print their sum.

Kotlin
val pairs = listOf(1 to 2, 3 to 4)
for (([1], [2]) in pairs) {
    println([1] + [2])
}
Drag options to blanks, or click blank then click option'
Afirst
Bsecond
Ckey
Dvalue
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'key' and 'value' which are for map entries, not pairs.
5fill in blank
hard

Fill all three blanks to destructure a list of triples and print a formatted string.

Kotlin
val triples = listOf(Triple("John", "Doe", 30), Triple("Jane", "Smith", 25))
for (([1], [2], [3]) in triples) {
    println("Name: $[1] $[2], Age: $[3]")
}
Drag options to blanks, or click blank then click option'
Afirst
Blast
Cthird
Dsecond
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'last' instead of 'second' for the middle element.

Practice

(1/5)
1. What does destructuring in Kotlin collection iteration allow you to do?
for ((key, value) in map) { ... }
easy
A. Only access the value in the loop
B. Only access the key in the loop
C. Access both key and value directly in the loop variables
D. Modify the map while iterating

Solution

  1. Step 1: Understand destructuring syntax

    In Kotlin, for ((key, value) in map) extracts both key and value from each map entry.
  2. Step 2: Recognize loop variable usage

    This lets you use key and value directly inside the loop without extra calls.
  3. Final Answer:

    Access both key and value directly in the loop variables -> Option C
  4. Quick Check:

    Destructuring = direct access to parts [OK]
Hint: Destructuring splits pairs into variables directly [OK]
Common Mistakes:
  • Thinking only key or value is accessible
  • Trying to modify map inside loop
  • Not using parentheses for destructuring
2. Which of the following is the correct syntax for destructuring a map in Kotlin?
val map = mapOf("a" to 1, "b" to 2)
easy
A. for (key, value in map) { println(key + value) }
B. for ((key, value) in map) { println(key + value) }
C. for [key, value] in map { println(key + value) }
D. for {key, value} in map { println(key + value) }

Solution

  1. Step 1: Recall Kotlin destructuring syntax

    Kotlin requires parentheses around variables when destructuring: for ((key, value) in map).
  2. Step 2: Check each option

    Only for ((key, value) in map) { println(key + value) } uses parentheses correctly; others use commas without parentheses or wrong brackets.
  3. Final Answer:

    for ((key, value) in map) { println(key + value) } -> Option B
  4. Quick Check:

    Parentheses needed for destructuring [OK]
Hint: Use parentheses around variables in destructuring [OK]
Common Mistakes:
  • Omitting parentheses in for loop
  • Using square or curly brackets instead
  • Confusing destructuring with tuple unpacking syntax
3. What is the output of this Kotlin code?
val map = mapOf("x" to 10, "y" to 20)
for ((k, v) in map) {
  println("$k$v")
}
medium
A. Syntax error
B. 10x\n20y
C. k v\nk v
D. x10\ny20

Solution

  1. Step 1: Understand map entries and destructuring

    The map has entries "x" to 10 and "y" to 20. The loop destructures each entry into k and v.
  2. Step 2: Print key and value concatenated

    Inside the loop, println("$k$v") prints key and value together without space, so outputs are "x10" and "y20" on separate lines.
  3. Final Answer:

    x10\ny20 -> Option D
  4. Quick Check:

    Print key + value per entry [OK]
Hint: Destructure map entries to print key and value [OK]
Common Mistakes:
  • Swapping key and value in output
  • Expecting spaces between key and value
  • Confusing variable names
4. Identify the error in this Kotlin code snippet:
val map = mapOf("a" to 1, "b" to 2)
for (key, value in map) {
  println(key + value)
}
medium
A. Missing parentheses around key and value in for loop
B. mapOf cannot be iterated
C. Cannot add key and value directly
D. No error, code runs fine

Solution

  1. Step 1: Check for destructuring syntax

    The for loop uses for (key, value in map) which lacks parentheses around key, value.
  2. Step 2: Understand correct syntax

    Kotlin requires parentheses for destructuring pairs: for ((key, value) in map). Without them, it's a syntax error.
  3. Final Answer:

    Missing parentheses around key and value in for loop -> Option A
  4. Quick Check:

    Parentheses required for destructuring [OK]
Hint: Always use parentheses for destructuring in for loops [OK]
Common Mistakes:
  • Omitting parentheses in destructuring
  • Thinking mapOf is not iterable
  • Confusing addition with string concatenation
5. Given a list of pairs representing database rows:
val rows = listOf(Pair("id", 1), Pair("name", "Alice"), Pair("age", 30))

Which Kotlin code correctly prints each key and value using destructuring?
hard
A. for ((key, value) in rows) { println("$key: $value") }
B. for (key, value in rows) { println("$key: $value") }
C. for (row in rows) { println(row.key + ": " + row.value) }
D. for ((k, v) in rows) { println(k + v) }

Solution

  1. Step 1: Recognize list of pairs and destructuring

    The list contains pairs, so destructuring with (key, value) works to access each part.
  2. Step 2: Check each option for correctness

    for ((key, value) in rows) { println("$key: $value") } uses correct destructuring syntax and prints key and value with colon and space. for (key, value in rows) { println("$key: $value") } misses parentheses, for (row in rows) { println(row.key + ": " + row.value) } tries to access properties that don't exist, for ((k, v) in rows) { println(k + v) } concatenates without separator.
  3. Final Answer:

    for ((key, value) in rows) { println("$key: $value") } -> Option A
  4. Quick Check:

    Use parentheses and print with separator [OK]
Hint: Use parentheses and print key: value format [OK]
Common Mistakes:
  • Omitting parentheses in for loop
  • Accessing pair elements as properties
  • Concatenating without separator
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