Break and continue behavior in Kotlin - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to stop the loop when i equals 3.

Kotlin

for (i in 1..5) {
    if (i == 3) {
        [1]
    }
    println(i)
}

Drag options to blanks, or click blank then click option'

Abreak

Bcontinue

Creturn

Dexit

Attempts:

3 left

💡 Hint

Common Mistakes

Using continue instead of break, which skips the current iteration but does not stop the loop.

The break statement stops the loop immediately when the condition is met.

2fill in blank

medium

Complete the code to skip printing the number 3 but continue the loop.

Kotlin

for (i in 1..5) {
    if (i == 3) {
        [1]
    }
    println(i)
}

Drag options to blanks, or click blank then click option'

Areturn

Bbreak

Ccontinue

Dskip

Attempts:

3 left

💡 Hint

Common Mistakes

Using break instead of continue, which stops the loop entirely.

The continue statement skips the current iteration and continues with the next one.

3fill in blank

hard

Fix the error in the code to correctly skip printing even numbers.

Kotlin

for (num in 1..6) {
    if (num % 2 == 0) [1]
    println(num)
}

Drag options to blanks, or click blank then click option'

Abreak

Bskip

Creturn

Dcontinue

Attempts:

3 left

💡 Hint

Common Mistakes

Using break causes the loop to stop early, not skip iterations.

Using continue skips printing even numbers but continues the loop.

4fill in blank

hard

Fill both blanks to create a loop that prints numbers 1 to 5 but stops before 4.

Kotlin

for (i in 1..5) {
    if (i [1] 4) {
        [2]
    }
    println(i)
}

Drag options to blanks, or click blank then click option'

A>=

B<

Cbreak

Dcontinue

Attempts:

3 left

💡 Hint

Common Mistakes

Using continue instead of break, which skips but does not stop the loop.

The condition i >= 4 checks if i is 4 or more, and break stops the loop when i is 4 or more.

5fill in blank

hard

Fill all three blanks to print only odd numbers from 1 to 7.

Kotlin

for (n in 1..7) {
    if (n [1] 2 == 0) {
        [2]
    }
    println([3])
}

Drag options to blanks, or click blank then click option'

A%

Bcontinue

Cn

Dbreak

Attempts:

3 left

💡 Hint

Common Mistakes

Using break instead of continue, which stops the loop early.

The modulo operator % checks for even numbers, continue skips them, and n prints the current number.

Practice

1. What does the break statement do inside a Kotlin loop?

easy

A. Stops the entire loop immediately

B. Skips the current iteration and continues the loop

C. Restarts the loop from the beginning

D. Pauses the loop until a condition is met

Solution

1. Step 1: Understand the role of break

   The break statement immediately stops the whole loop when executed.

2. Step 2: Compare with other loop controls

   Unlike continue, which skips only the current step, break ends the loop fully.

3. Final Answer:

   Stops the entire loop immediately -> Option A

4. Quick Check:

   break stops loop = B [OK]

Hint: Remember: break = stop loop, continue = skip step [OK]

Common Mistakes:

• Confusing break with continue
• Thinking break skips only one iteration
• Assuming break restarts the loop

2. Which of the following is the correct syntax to skip the current iteration in a Kotlin for loop?

easy

A. continue

B. break

C. skip

D. stop

Solution

1. Step 1: Identify the keyword to skip iteration

   In Kotlin, continue is used to skip the current loop iteration and move to the next.

2. Step 2: Check other options for correctness

   break stops the loop, skip and stop are not valid Kotlin keywords.

3. Final Answer:

   continue -> Option A

4. Quick Check:

   Skip iteration = continue [OK]

Hint: Use continue to skip steps inside loops [OK]

Common Mistakes:

• Using break instead of continue
• Using non-existent keywords like skip or stop
• Confusing syntax with other languages

3. What will be the output of this Kotlin code?

for (i in 1..5) {
    if (i == 3) break
    print(i)
}

medium

A. Error

B. 12345

C. 345

D. 12

Solution

1. Step 1: Analyze the loop and break condition

   The loop runs from 1 to 5. When i equals 3, break stops the loop immediately.

2. Step 2: Determine printed values before break

   Values 1 and 2 are printed before hitting i == 3, then loop stops.

3. Final Answer:

   12 -> Option D

4. Quick Check:

   Loop stops at 3, prints 1 and 2 [OK]

Hint: Break stops loop before printing 3 [OK]

Common Mistakes:

• Assuming 3 is printed before break
• Thinking loop continues after break
• Confusing break with continue

4. Find the error in this Kotlin code snippet:

for (i in 1..5) {
    if (i == 3) continue
    if (i == 6) break
    print(i)
}

medium

A. The loop will run infinitely

B. continue cannot be used inside for loops

C. The break condition is unreachable

D. Syntax error in if statements

Solution

1. Step 1: Check loop range and conditions

   The loop runs from 1 to 5, so i == 6 never happens.

2. Step 2: Analyze break condition reachability

   Since i never reaches 6, the break statement is never executed, making it unreachable code.

3. Final Answer:

   The break condition is unreachable -> Option C

4. Quick Check:

   Break at i=6 unreachable in 1..5 loop [OK]

Hint: Check loop range matches break condition [OK]

Common Mistakes:

• Assuming break will run at i=6
• Thinking continue is invalid in loops
• Believing loop runs infinitely

5. Consider this Kotlin code:

var sum = 0
for (i in 1..10) {
    if (i % 2 == 0) continue
    if (sum > 10) break
    sum += i
}
print(sum)

What is the output?

hard

A. 25

B. 11

C. 9

D. 16

Solution

1. Step 1: Understand loop behavior with continue and break

   The loop adds only odd numbers (because even numbers are skipped by continue). It stops when sum > 10.

2. Step 2: Calculate sum step-by-step

   Odd numbers: 1,3,5,7,9
   i=1: sum=0 <=10, sum=1
   i=3: sum=1 <=10, sum=4
   i=5: sum=4 <=10, sum=9
   i=7: sum=9 <=10, sum=16
   i=9: sum=16 >10, break (no add 9).

3. Final Answer:

   11 -> Option B

4. Quick Check:

   Sum odd numbers until sum > 10 = 11 [OK]

Hint: Add odds, stop when sum exceeds 10 [OK]

Common Mistakes:

• Adding even numbers mistakenly
• Breaking before sum exceeds 10
• Miscounting sum steps