Break and continue behavior in Kotlin - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to stop the loop when i equals 3.

Kotlin

for (i in 1..5) {
    if (i == 3) {
        [1]
    }
    println(i)
}

Drag options to blanks, or click blank then click option'

Abreak

Bcontinue

Creturn

Dexit

Attempts:

3 left

💡 Hint

Common Mistakes

Using continue instead of break, which skips the current iteration but does not stop the loop.

The break statement stops the loop immediately when the condition is met.

2fill in blank

medium

Complete the code to skip printing the number 3 but continue the loop.

Kotlin

for (i in 1..5) {
    if (i == 3) {
        [1]
    }
    println(i)
}

Drag options to blanks, or click blank then click option'

Areturn

Bbreak

Ccontinue

Dskip

Attempts:

3 left

💡 Hint

Common Mistakes

Using break instead of continue, which stops the loop entirely.

The continue statement skips the current iteration and continues with the next one.

3fill in blank

hard

Fix the error in the code to correctly skip printing even numbers.

Kotlin

for (num in 1..6) {
    if (num % 2 == 0) [1]
    println(num)
}

Drag options to blanks, or click blank then click option'

Abreak

Bskip

Creturn

Dcontinue

Attempts:

3 left

💡 Hint

Common Mistakes

Using break causes the loop to stop early, not skip iterations.

Using continue skips printing even numbers but continues the loop.

4fill in blank

hard

Fill both blanks to create a loop that prints numbers 1 to 5 but stops before 4.

Kotlin

for (i in 1..5) {
    if (i [1] 4) {
        [2]
    }
    println(i)
}

Drag options to blanks, or click blank then click option'

A>=

B<

Cbreak

Dcontinue

Attempts:

3 left

💡 Hint

Common Mistakes

Using continue instead of break, which skips but does not stop the loop.

The condition i >= 4 checks if i is 4 or more, and break stops the loop when i is 4 or more.

5fill in blank

hard

Fill all three blanks to print only odd numbers from 1 to 7.

Kotlin

for (n in 1..7) {
    if (n [1] 2 == 0) {
        [2]
    }
    println([3])
}

Drag options to blanks, or click blank then click option'

A%

Bcontinue

Cn

Dbreak

Attempts:

3 left

💡 Hint

Common Mistakes

Using break instead of continue, which stops the loop early.

The modulo operator % checks for even numbers, continue skips them, and n prints the current number.