Why Subscribing to topics in Kafka? - Purpose & Use Cases

The Big Idea

What if you could get all updates automatically the moment they happen, without lifting a finger?

The Scenario

Imagine you want to get updates from many different news channels by calling each one separately every minute to ask if there is new news.

The Problem

This manual checking is slow, wastes time, and you might miss important news if you check too late. Also, it's easy to make mistakes by forgetting to check some channels or mixing up the news.

The Solution

Subscribing to topics means you tell the system which news channels you want to follow, and it automatically sends you updates as soon as they happen. You don't have to keep asking; the updates come to you instantly and reliably.

Before vs After

✗ Before

while True:
    for channel in channels:
        news = check_news(channel)
        if news:
            print(news)
    sleep(60)

✓ After

consumer.subscribe(['news_channel'])
for message in consumer:
    print(message.value)

What It Enables

It enables real-time, efficient, and reliable data flow without constant manual checking.

Real Life Example

A stock trading app subscribes to stock price updates and instantly shows you changes without you refreshing or asking repeatedly.

Key Takeaways

Manual checking is slow and error-prone.

Subscribing automates receiving updates instantly.

This makes programs faster, simpler, and more reliable.

Practice

1. What is the main purpose of the subscribe() method in Kafka consumers?

easy

A. To close the Kafka consumer connection

B. To send messages to Kafka topics

C. To listen to one or more Kafka topics and receive messages automatically

D. To create new Kafka topics

Solution

1. Step 1: Understand the role of subscribe()

   The subscribe() method is used by Kafka consumers to specify which topics they want to listen to.

2. Step 2: Identify what subscribe() enables

   Once subscribed, the consumer automatically receives messages from those topics when calling poll().

3. Final Answer:

   To listen to one or more Kafka topics and receive messages automatically -> Option C

4. Quick Check:

   subscribe() = listen to topics [OK]

Hint: subscribe() means start listening to topics [OK]

Common Mistakes:

• Confusing subscribe() with sending messages
• Thinking subscribe() creates topics
• Assuming subscribe() closes connections

2. Which of the following is the correct way to subscribe a Kafka consumer to multiple topics named "topicA" and "topicB"?

easy

A. consumer.subscribe(["topicA", "topicB"])

B. consumer.subscribe("topicA", "topicB")

C. consumer.subscribe("topicA" + "," + "topicB")

D. consumer.subscribe({"topicA", "topicB"})

Solution

1. Step 1: Recall the subscribe() method signature

   In Kafka, subscribe() takes a list (or collection) of topic names as an argument.

2. Step 2: Identify correct syntax for multiple topics

   Passing a list like ["topicA", "topicB"] is the correct way to subscribe to multiple topics.

3. Final Answer:

   consumer.subscribe(["topicA", "topicB"]) -> Option A

4. Quick Check:

   subscribe() needs a list for multiple topics [OK]

Hint: Use a list to subscribe to multiple topics [OK]

Common Mistakes:

• Passing multiple string arguments instead of a list
• Concatenating topic names into one string
• Using curly braces instead of square brackets

3. Given the following Kafka consumer code snippet, what will be the output if the consumer is subscribed to topic "news" and there are two messages "Hello" and "World" in the topic?

consumer.subscribe(["news"])
records = consumer.poll(timeout_ms=1000)
for record in records:
    print(record.value)

medium

A. ['Hello', 'World']

B. Hello\nWorld

C. HelloWorld

D. No output because poll() is missing a loop

Solution

1. Step 1: Understand subscribe() and poll() behavior

   The consumer subscribes to "news" and calls poll() once, which fetches available messages.

2. Step 2: Analyze the for loop printing each record

   The loop prints each message value on its own line, so "Hello" and "World" appear separately.

3. Final Answer:

   Hello\nWorld -> Option B

4. Quick Check:

   poll() returns messages, loop prints each [OK]

Hint: poll() returns messages; loop prints each on new line [OK]

Common Mistakes:

• Thinking poll() returns a list printed directly
• Assuming messages print concatenated without newline
• Believing poll() needs a loop to work at all

4. What is wrong with the following Kafka consumer code snippet?

consumer.subscribe("topic1")
while True:
    records = consumer.poll(1000)
    for record in records:
        print(record.value)

medium

A. subscribe() expects a list, not a single string

B. poll() must be called outside the loop

C. print() cannot be used inside the loop

D. The loop should be a for loop, not while

Solution

1. Step 1: Check subscribe() argument type

   The subscribe() method requires a list of topics, even if subscribing to one topic.

2. Step 2: Identify the error in argument

   Passing a single string instead of a list causes a type error or unexpected behavior.

3. Final Answer:

   subscribe() expects a list, not a single string -> Option A

4. Quick Check:

   subscribe() needs list argument [OK]

Hint: Always pass a list to subscribe(), even for one topic [OK]

Common Mistakes:

• Passing a string instead of a list to subscribe()
• Thinking poll() can't be inside a loop
• Misunderstanding loop type requirements

5. You want to subscribe a Kafka consumer to all topics starting with "logs-" dynamically, without listing each topic name. Which approach correctly achieves this?

hard

A. Use consumer.assign() with topic partitions matching "logs-"

B. Manually list all topics starting with "logs-" in a list and pass to subscribe()

C. Call subscribe() multiple times, once per topic starting with "logs-"

D. Use consumer.subscribe(Pattern.compile("logs-.*")) to subscribe by regex pattern

Solution

1. Step 1: Understand dynamic topic subscription

   Kafka consumers can subscribe to topics matching a regex pattern using subscribe(Pattern).

2. Step 2: Identify correct method for pattern subscription

   Using consumer.subscribe(Pattern.compile("logs-.*")) subscribes to all topics starting with "logs-" automatically.

3. Final Answer:

   Use consumer.subscribe(Pattern.compile("logs-.*")) to subscribe by regex pattern -> Option D

4. Quick Check:

   subscribe() supports regex patterns [OK]

Hint: Use regex pattern with subscribe() for dynamic topic matching [OK]

Common Mistakes:

• Listing topics manually instead of using regex
• Calling subscribe() multiple times incorrectly
• Using assign() which requires partitions, not topics